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Published byWhitney Massey Modified about 1 year ago

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Warm Up Week 3 1) What is a counter example for: The sum of two numbers is always greater than the larger number.” 2) Draw two straight lines that cross each other. Measure each angle. Describe the angles. Did you make any vertical angles? Did you make any linear pairs?

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Rewind 1 ∠1 and ∠2 are linear pairs m∠1 + m∠2 = 180º 1 30 º m∠1 + 30º = 180º m∠1 = 180º - 30º m∠1 = 150º 2

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Geometry 1.6 Day 2 I will define and identify Complementary and Supplementary Angles. Complimentary Angles The measure of two angles when their sum is 90 º Ex 1 ∠1 and ∠2 are complimentary adjacent angles ∠3 and ∠4 are complimentary nonadjacent angles m∠1 + m∠2 = 90 º m∠3 + m∠4 = 90º

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Ex 2 m∠A = 5x + 12 m∠A and m∠B are complementary 5x x – 6 = 90º 7x + 6 = 90 7x = x = 84 x = 12 Find both angles m∠B = 2x - 6

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m∠A = 5x + 12 = 5( 12 ) + 12 = = 72º x = 12 m∠B = 2x - 6 = 2( 12 ) – 6 m∠A = 24 – 6 = 18ºm∠B

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m∠A = 48º m∠A + m∠B = 90º 48 + m∠B = 90 m∠B = m∠ A and m∠ B are Complementary m∠B = ? Ex 3 m∠B = 42º

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Ex 4 Supplementary Angles 1 2 ∠1 and ∠2 are supplementary adjacent m∠1 + m∠2 = 180º The measure of two angles when their sum is 180º 4 ∠3 and ∠4 are supplementary nonadjacent m∠3 + m∠4 = 180º 3

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Ex 5 m∠A = 7x m∠A and m∠B are Supplementary 7x x + 44 = 180º 8x = 180 8x = x = 384 x = 48 Find both angles m∠B = x + 44

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m∠A = 7x = 7( 48 ) = = 88º x = 48 m∠B = x + 44 = ( 48 ) + 44 m∠A = 92ºm∠B

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m∠A = ? m∠A + m∠B = 180º m∠A = 180 m∠A = m∠ A and m∠ B are Supplementary m∠B = 121º Ex 6 m∠A = 59º

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Review Assignment: Textbook page 48, 37 – 53 all Complementary angles add up to ____º. Do 1: m∠A = ? m∠ A and m∠ B are Supplementary m∠B = 47º

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