1. SHARPLESS ASYMMETRIC EPOXIDATION

2. Chapter 6 ALKYL HALIDES: NUCLEOPHILIC SUBSTITUTION AND ELIMINATION Chapter 6: Alkyl Halides: Nucleophilic Substitution and Elimination

3. SOME COMMON PESTICIDES DDT Lindane Kepone Aldrin Chlordane

4. BOILING POINT TRENDS Compoundbp [ o C] CH 3 – Cl- 24 CH 3 CH 2 – Cl12 CH 3 CH 2 CH 2 – Cl47 CH 3 CH 2 CH 2 CH 2 – Cl78 Compoundbp [ o C] CH 3 CH 2 – F- 38 CH 3 CH 2 – Cl12 CH 3 CH 2 – Br38 CH 3 CH 2 – I72 Compoundbp [ o C] CH 3 Cl- 24 CH 2 Cl 2 40 CHCl 3 61 CCl 4 77 Size of hydrocarbon part Type of halogen# of halogen atoms For comparison: CH 3 – CH 3 bp – 89 o C Chapter 6: Alkyl Halides: Nucleophilic Substitution and Elimination

5. RELATIVE SIZE CH 3 CH 2 F CH 3 CH 2 Cl CH 3 CH 2 Br CH 3 CH 2 I Chapter 6: Alkyl Halides: Nucleophilic Substitution and Elimination

6. COMPARISON OF S N 1 AND S N 2 REACTIONS 1.Effect of Nucleophile: A.S N 2: Strong nucleophiles B.S N 1: Irrelevant, since nucleophile does not participate in rate-determining step 2.Effect of Substrate: A.S N 2: CH 3 > 1 o > 2 o (3 o is sterically too hindered) B.S N 1: 3 o > 2 o (1 o or CH 3 do not easily form cations) 3.Effect of Solvent: A.S N 2: Promoted by polar aprotic solvents or non-polar solvents B.S N 1: Promoted by polar protic solvents

7. COMPARISON OF S N 1 AND S N 2 REACTIONS 4.Leaving Group Effect: A.Both S N 2 and S N 1 require good leaving groups – higher electronegativity and polarizability, weak bases 5.Kinetics: A.S N 2: A bimolecular reaction: Rate = k[RX][Nuc] B.S N 1: A monomolecular reaction: Rate = k[RX] 6.Stereochemistry: A.S N 2: Inversion of configuration B.S N 1: Complete or partial racemization 7.Rearrangements: A. S N 2: Rearrangements not possible (because it is a concerted process) B.S N 1: Rearrangements are common (because the intermediate cation often rearranges to a more stable cation)

8. COMPARISON OF E1 AND E2 REACTIONS 1.Effect of the Base: A.E2: Strong bases are required B.E1: Irrelevant, since base does not participate in rate-determining step 2.Effect of Substrate: A.E2: 3 o > 2 o > 1 o (CH 3 does not undergo E2) B.E1: 3 o > 2 o (1 o do not easily form carbocations and usually do not undergo E1; CH 3 does not undergo E1) 3.Effect of Solvent: A.E2: Solvent polarity is not very important B.E1: Promoted by polar protic solvents 4.Leaving Group Effect: A.Both E2 and E1 require good leaving groups – higher electronegativity and polarizability, weak bases

9. 5.Kinetics: A.E2: A bimolecular reaction: Rate = k[RX][B - ] B.E1: A monomolecular reaction: Rate = k[RX] 6.Stereochemistry: A.E2: Requires a coplanar arrangement of C – H and C – Leaving Group bonds. Anti-coplanar is preferred, but the reaction can also occur through a syn-coplanar, if the anti-coplanar is not achievable B.E1: Occurs via a flat carbocation. No particular geometry required. 7.Orientation of Elimination: A.Both E1 and E2: The predominant product (if more than one is possible) is the alkene with most substituted double bond (the Saytzeff product). This is known as the Saytzeff rule. 8.Rearrangements: A. E2: Rearrangements not possible (because it is a concerted process) B.E1: Rearrangements are common (because the intermediate carbocation often rearranges to a more stable carbocation) COMPARISON OF E1 AND E2 REACTIONS

10. SUBSTITUTION VERSUS ELIMINATION 1.Strong nucleophile and a methyl substrate: S N 2 reaction. 2.Strong nucleophile (base) and primary substrate (1 o ): An S N 2 reaction is most likely. Some E2 product might be obtained as well. 3.Strong nucleophile (base) and secondary substrate (2 o ): Both S N 2 and E2 reactions will occur and a mixture of substitution and elimination products is likely. Difficult to predict whether S N 2 or E2 will predominate. 4.Strong nucleophile (base) and tertiary substrate (3 o ): An E2 reaction. S N 2 does not occur since substrate is too sterically hindered.

11. SUBSTITUTION VERSUS ELIMINATION 5.Weak nucleophile (base) and methyl substrate: No reaction. 6.Weak nucleophile (base) and primary substrate (1 o ): No reaction. EXCEPTION: If the primary substrate can undergo a concerted process of ionization + rearrangement to give a more stable carbocation (as is the case with neopentyl substrates), then the outcome is a mixture of S N 1 and E1. 7.Weak nucleophile (base) and secondary substrate (2 o ): Both S N 1 and E1 will occur and a mixture of substitution and elimination products is likely. 8.Weak nucleophile (base) and tertiary substrate (3 o ): Both S N 1 and E1.

12. SUBSTITUTION VERSUS ELIMINATION ONE GENERAL CONCLUSION: With strong nucleophiles (bases) the reactions occur via bimolecular mechanism: S N 2 or E2. With weak nucleophiles (bases) the reactions occur via monomolecular mechanism: S N 1 or E1.

13. SUBSTITUTION VERSUS ELIMINATION 9.Temperature of the reaction: Increase of temperature favors elimination. Reason: Elimination starts with two species (base and substrate) but produces three (the conjugate acid of the starting base, an alkene molecule and the leaving group). This increased number of molecules (or ions) causes an increase of entropy, i.e. a positive entropy change (  S). This in its turn increases the favorable contribution of the T  S-term in the overall Gibbs free energy change (because  G =  H – T  S), making the Gibbs free energy change more negative.

14. SUBSTITUTION VERSUS ELIMINATION 10.Steric bulk of the nucleophile (base): In concerted reactions (S N 2 or E2) the nucleophile (base) participates in the rate- determining step. It has to approach closely the molecule and attack the electrophilic carbon center (then it is a nucleophile) or the proton at an adjacent carbon (then it is a base). Approaching closely the carbon center is more sensitive to changes of size. That is why the share (percentage) of elimination increases with an increasing size of the nucleophile (base).