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VISCOSITY CALCULATION MARYCYNTHIA EZIKE BIEN 301 INDIVIDAUL PROJECT. 5TH FEBUARY, 2007

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PROBLEM STATEMENT Given: In fig. P6.52 supposes P1 = 700kPa and the fluid specific gravity is 0.68. If the flow rate is 27 m3 / h, estimate the viscosity of the fluid. What fluid in Table A.3 is the likely suspect?

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REQUIRED REQUIRED: Estimate the viscosity and what fluid in table A.3 is the likely suspect?

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FIG. P 6.52

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ASSUMPTIONS ASSUMPTIONS: Fully developed flow, steady, one dimensional, control volume, moderate Reynolds number dependence, incompressible ( Poiseuille ) pipe flow. Atmospheric pressure at section of the tube that is open. Continuity and energy equations apply. No heat transfer. No shaft work, No entrance effect, Viscous, Constant area and constant velocity.

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Calculations from continuity Q ( flow rate) = (27m3/h) / (3600s) Q =0.0075 m3/s Length (L) = 30m + 60m+80m = 170m Diameter (d) = (5cm) / (100) = 0.05m Area (A) = πr2 = π (0.025) 2 = 0.0019635m2 V ( velocity) = Q/A = (0.0075 m3/s)/ (0.0019635m2) = 3.819m/s. Length (L) = 30m + 60m+80m = 170m

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Calculating the specific gravity of the liquid 0.68 = (ρliquid) / 998kg/m3 ρliquid = 678.64 kg/m3

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Calculating friction factor from energy equation (P1/ρg) = f (LV2/2gd) + V2 /2g + Z 2 – Z 1 f = [{(P1/ρg) – (Z 2 – Z 1) - V2 /2g} {2g d}] / LV2 f = [{105.14 – 70 – 0.74336}*{0.981}]/ (2479.4) f = 0.0136094

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To calculate Reynold’s number; f= {1.8 log [(Red) / (6.9)]}-2 …...equation 6.39b Red = 6.9 * 57916.19 = 400636 To calculate viscosity; Red = (ρVL) / (μ) ………………equation 1.24 μ = {(678.64 kg/m3) (3.819m/s) (0.05m)} / {400636} μ = 3.23e-4 kg/m.s

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Choosing the liquid Picking out the liquid that has this viscosity From Table A.3 from the book, the closest value to this viscosity value is the value for Gasoline.

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Biomedical application. Viscosity helps us to understand blood and its flow properties. The knowledge of the viscosity of blood and being able to manipulate blood physical properties will lead to the development of artificial blood.

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