# Calculator Skills 2 INPUT EACH EQUATION INTO YOUR CALCULATOR AND PRESS GRAPH THEN FIND THE ORDERED PAIR SOLUTION HOLD UP YOUR CACLULATOR WHEN YOU HAVE.

## Presentation on theme: "Calculator Skills 2 INPUT EACH EQUATION INTO YOUR CALCULATOR AND PRESS GRAPH THEN FIND THE ORDERED PAIR SOLUTION HOLD UP YOUR CACLULATOR WHEN YOU HAVE."— Presentation transcript:

Calculator Skills 2 INPUT EACH EQUATION INTO YOUR CALCULATOR AND PRESS GRAPH THEN FIND THE ORDERED PAIR SOLUTION HOLD UP YOUR CACLULATOR WHEN YOU HAVE THE SOLUTION

y = 3x  6 y =  2x + 4 INPUT INTO y1 AND y2 GRAPH 2 ND TRACE (CALC) 5 (INTERCEPT) ENTER, ENTER, ENTER

(2,0) y1 = 3x  6 y2 =  2x + 4

4x – 2y = 8 y =  7x + 5 INPUT INTO y1 AND y2 GRAPH 2 ND TRACE (CALC) 5 (INTERCEPT) ENTER, ENTER, ENTER

(1, –2) y1 = (8 – 4x)/ – 2 y2 =  7x + 5

3x + 6y = 12 y  3 = 2(x  2) (1.2, 1.4) y1 = (12–3x)/6 y2 = 2(x  2) + 3

y + 1 = 4(x  2) y = 6x  10 (.5, –7) y1 = 4(x  2) – 1 y2 = 6x  10

5x – y = 2 – x + y = 2 (1, 3) y1 = (2– 5x)/ – 1 y2 = (2 + x)/1

2x + 2y = 6 – 2x + 3y = –1 (2, 1) y1 = (6 – 2x)/ 2 y2 = (–1 + 2x)/ 3

– 2y – 2x = – 8 2y – 3x = – 2 LOOK AT WHERE THE “X” AND “Y” ARE LOCATED IN PROBLEM (2, 2) y1 =( – 8 +2x )/–2 y2 =( – 2 + 3x)/ 2

4y = 3x – 2 3x + 2y = – 10 (–2, –2) y1 = (– 2+3x)/4 y2 = (– 10 –3x)/2

4x + (–2y) + x = 2 6x + 2y = – 4 (-.181818, –1.454545) y1= (2 – 4x –x)/ –2 y2 = (– 4 – 6x)/2

2x + 2y ≤ 6 y ≥ x + 1 FOR INEQALITIES INPUT EQ. INTO y1 AND y2 USE LEFT SCROLL ARROW  TO MOVER CURSER TO EXTREME LEFT PRESS ENTER UNTIL YOU GET THE UP RIGHT TRIANGLE  ( GREATER THAN) OR PRESS ENTER UNTIL YOU GET THE DOWN RIGHT TRIANGLE  (LESS THAN) PRESS GRAPH LOOK FOR DOUBLE SHADED REGION FIND POINT OF INTERSECTION

Left double shaded with (1,2) intercept y ≤ (6 – 2x)/2 y ≥ x + 1

x ≥ – y + 2 y – 3x < 2 REMEMBER TO REVERSE (OR FLIP ) THE INEQUALITY WHEN DIVIDING OR MULTIPLYING BY A NEGATIVE “–” NUMBER

SHADED LEF: (0,2) y1 ≤ (x – 2)/ –1 y2 < (3x+ 2)

3x + 2y > 6 y < 2(x – 2) SHADED RIGHT: (2,0) y1 > (6 – 3x)/2 y2 < 2(x – 2)

y – 3 ≤ 2(x – 1) x > – 2(y – 1) Upper Right double shaded: (0,1) y1 ≤ 2(x – 1) + 3 y2 > (x – 2)/–2

2y ≥ – 2x + 4 – y – 3 > 2(x – 4) TOP LEFT DOUBLE SHADED: (3, – 1) y1 ≥ (– 2x + 4)/2 y2 < (2(x – 4) + 3)/ –1

– 3x + 2y ≤ 3 y > – 3 REMEMBER: SINCE NO “x” IN SECOND INEQALITY, JUST PLACE –3 INTO y2 TOP RIGHT DOUBLE SHADED: (–3, –3) y1 ≤ (3 +3x)/2 y2 > – 3

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