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indicates dotted/dashed line < indicates below or to the left of the line > indicates above or to the right of the line If equals is part of the symbol then the line is solid

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y < -3x – 1 Start at -1 Move Down 3 and Right 1 Then shade below

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Graphing two lines or inequalities and determining their point of intersection or area of overlap (feasible region)

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y ≤ 2x + 4 3 y < -1x + 4 5 (feasible region)

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Is (0,0) a solution of the system in the last example? Option 1: Look at the graph. If it is in the feasible region, it is a solution for this example YES! Option 2: use substitution ◦ 0 ≤ 2(0) + 40< -1 (0) +4 3 5 0 ≤ 4 0< 4 since both are true, YES!

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Solve and graph 6< -4 – 2x < 12 -4 -4 -4 2 < -2x < 8 -2 -2 -2 -1 > x > -4 -5 -3 -1 1 3 Sketch both parts Sketch the overlap Don’t forget to change the direction of the inequality

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3x + y = 4 -2x + y = -1 Solve each for y y = -3x + 4 y = 2x - 1

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3x + y = 4 -2x + y = -1 Solve each for y y = -3x + 4 y = 2x - 1 Enter one in Y1 the other in Y2 Press graph Press 2 nd calc Choose #5 Enter (1, 1)

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3x + y = 4 -2x + y = -1 Solve one equation for y y = -3x + 4 Place the values in the other equation -2x + (-3x + 4) = -1 -2x + -3x + 4 = -1 -5x + 4 = -1 -5x = -5 x = 1

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3x + y = 4 -2x + y = -1 Create a set of opposites 3x + y = 4 2x – y = 1 5x = 5 x = 1 Place the values in the other equation -2(1) + y= -1 -2 + y = -1 y = 1

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Lesson 2.11 Solving Systems of Linear Inequalities Concept: Represent and Solve Systems of Inequalities Graphically EQ: How do I represent the solutions.

Lesson 2.11 Solving Systems of Linear Inequalities Concept: Represent and Solve Systems of Inequalities Graphically EQ: How do I represent the solutions.

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