Download presentation

1
Paper 1 General 2002 1 2 3 4 5 6 7 8 9 10

2
Paper 2 General 2002 1 2 3 4 5 6 7 8 9 10 11

3
Paper1 Q1 General 2002 (b) (a) 8 1 1 1 9.2 5.49 7.29 - 3.71 + 6.47 x 8 1 . 2 7 . 5 4 9 . 11 9 6 5 8 3 2 (c) 2 2 9 . = 2 6.87 3 (d)

4
Paper1 Q2 General 2002 (a) (b) New total =14

5
Paper1 Q3 General 2002

6
**5 000 000 10% = 500 000 30% = 1 500 000 Paper1 Q4 30 % of 5 million;**

General 2002 30 % of 5 million; 10% = 30% =

7
**Paper1 Q5 A (-4,-3) B (3,-1) 6 C (4,4) C 4 D 2 Gradient of AB = -6 -4**

General 2002 (a) A (-4,-3) y B (3,-1) 6 C (4,4) C 4 (b) D 2 Gradient of AB = -6 -4 -2 x 2 4 6 B -2 -4 (c) A D ( -3,2) -6

8
Paper1 Q6 General 2002 Change into decimals to compare.

9
**Paper1 Q7 O A C B AB is a tangent ; Triangle AOB is isosceles ; So**

General 2002 O A C B AB is a tangent ; Triangle AOB is isosceles ; So (Angles in a triangle)

10
**Paper1 Q8 54% 100 90 80 (c) 70 Maths mark = 60 Mathematics marks 50 40**

General 2002 10 20 30 40 50 60 70 80 90 100 Science marks Mathematics marks (c) Maths mark = 54% (estimate)

11
**Plant A has grown more by 3 cm .**

Paper1 Q9 General 2002 Week one Week two Plant A 29 cm 57 cm Plant B 46 cm 71 cm Growth 57 – 29 = 28 cm 71 – 46 = 25 cm Plant A has grown more by 3 cm .

12
**Paper1 Q10 Each tyre spends one fifth of it’s time in the trunk. So**

General 2002 Each tyre spends one fifth of it’s time in the trunk. So Each tyre does

13
**Paper2 Q1 List ; 45 mins = 45/60 hrs = 0.75 hrs D = S = T = ? ?**

General 2002 List ; 45 mins = 45/60 hrs = 0.75 hrs D = S = T = ? ? 76 km/h 3 hrs 45 mins = hrs D = S x T D = 76 x 3.75 S T = 285 km

14
**Paper2 Q2 (a) VAT = 17.5% of £779 = 17.5/100 x 779 Total cost = 779**

General 2002 (a) VAT = 17.5% of £779 = /100 x 779 Total cost = 779 = = £ = £ (b) Difference = = £ 15.33 Refund = x 2 = £ 30.66 (Double the difference)

15
Paper2 Q3 General 2002 (a) From formula sheet; V = r2 h = x (20)2 x 450 = = cm 3 450 cm (b) = 5.65 x 10 5 40 cm

16
**Paper2 Q4 15 29 85 1 section 2 sections 3 sections (a) (b)**

General 2002 1 section 2 sections 3 sections (a) 15 29 85 +7 +7 +7 (b) Number of iron bars = Number of sections x 7 + 1 b = 7s +1 12 x 7+1 (c) 176 = 7s +1 175 = 7s s = 25 25 sections

17
**Paper2 Q5 This is for 12 months Find 4.5% of £1640 Yearly interest =**

General 2002 This is for 12 months Find 4.5% of £1640 Yearly interest = Monthly interest = 9 months interest =

18
**Paper2 Q6 SOHCAHTOA tan xo = = 1.667 xo = tan –1 (1.67) = 59 o P Q R S**

General 2002 P Q R S 12 cm 20 cm P Q 10 cm 6 cm In a rhombus, diagonals are bisected at right angles. tan xo = SOHCAHTOA O = T A xo = tan –1 (1.67) = 59 o Therefore

19
**Paper2 Q7 Bath 180 cm 120 cm x According to Pythagoras:**

General 2002 Bath Strip of plastic 30cm 20 cm 180 cm 120 cm x According to Pythagoras: x2 = = = x = = cm

20
**Paper2 Q8 (a) Scale 1:2 T HP (15 cm) 7.5 cm HT (20 cm) 10 cm H P**

General 2002 (a) Scale 1:2 T HP (15 cm) 7.5 cm HT (20 cm) 10 cm H P Rod (35 cm) 17.5 cm (b) 12.5 cm By measuring PT on your drawing you get; So Actual length of PT = 2 x 12.5 = cm

21
**Paper2 Q9 4 ( 3x + 2) = 68 12x + 8 = 68 12x = 60 x = 5 10y +15 = 5 ( )**

General 2002 (a) 4 ( 3x + 2) = 68 12x + 8 = 68 12x = 60 x = 5 (b) 10y +15 = 5 ( ) 2y + 3

22
Paper2 Q10 General 2002 (b) A B 120 cm = (a) 50m will be enough!

23
**Paper2 Q11 Hire purchase price = Deposit + Total instalments**

General 2002 Hire purchase price = Deposit + Total instalments Find these to calculate this “ The hire purchase price is 22% more than the cash price” hire purchase price = cash price x 1.22 = x 1.22 = £ 7686 Each instalment = “….requires a deposit, which is 15% of the cash price” deposit = 15% of £6300 = £ = x = £945 Total instalments = Hire purchase price - Deposit = 945 = £ 6741

24
Paper 1 General 2002 1 2 3 4 5 6 7 8 9 10

Similar presentations

OK

Solving Right Triangles using Trigonometry. Labeling a Right Triangle In trigonometry, we give each side a name according to its position in relation.

Solving Right Triangles using Trigonometry. Labeling a Right Triangle In trigonometry, we give each side a name according to its position in relation.

© 2018 SlidePlayer.com Inc.

All rights reserved.

To make this website work, we log user data and share it with processors. To use this website, you must agree to our Privacy Policy, including cookie policy.

Ads by Google