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Enthalpy of Neutralisation. The enthalpy of neutralisation is the heat energy released when 1 mole of water is formed from neutralisation of an acid with.

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Presentation on theme: "Enthalpy of Neutralisation. The enthalpy of neutralisation is the heat energy released when 1 mole of water is formed from neutralisation of an acid with."— Presentation transcript:

1 Enthalpy of Neutralisation

2 The enthalpy of neutralisation is the heat energy released when 1 mole of water is formed from neutralisation of an acid with a base. Neutralisation is an exothermic reaction. The reaction between NaOH with HCl can be written as: NaOH + HCl  NaCl + H 2 O By omitting the spectator ions the reaction becomes: H + (aq) + OH - (aq)  H 2 O (l)

3 To work out the enthalpy of neutralisation you need to record the following data: 1.The average starting temperature of acid + alkali 2.The temperature of the final salt solution

4 Experiment 25 cm 3 of HCl 1 mole l cm 3 of NaOH 1 mole l -1 Na + OH - H + Cl -

5 Measurements Taken Temperature acid-19oC Temperature alkali- 19 o C Final temperature- 25 o C Calculate the enthalpy of neutralisation when 50cm 3 of 1 mol l -1 NaOH is added to 50cm 3 of 1 mol l -1 HCl.  Specimen results

6 Solution 1. Calculate average starting temperature (19+19)/2= 19 o C 2. Calculate average change in temperature 25-19= 6 o C 3. Calculate the heat energy released EH = c x m x ΔT = 4.18x0.1x6 = 2.508kJ

7 4. Mole calculation NaOH+HCl  NaCl+H 2 O 1 mole1 mole1 mole1 mole0.05 moles For both acid + alkali: n=c x v n=1 x 0.05= 0.05 moles So, 0.05 moles: 2.508kJ 1 mole : (2.508/0.05)= 50.16kJ mol -1 Enthalpy of neutralisation is kJ mol -1


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