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**Enthalpy of Solution (HSOLN)**

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**When substances dissolve in water, an energy change usually occurs.**

Enthalpy of solution is defined as the enthalpy change when 1 mole of a substance completely dissolves (kJ mol-1)

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Experiment 50cm3 of H2O Thermometer Balance 2g NaOH or 4g NH4NO3

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**Measurements Taken Volume (mass) of water Mass of substance dissolves**

Temperature of water at start Temperature of water at end

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Specimen Results 1.03g of NaOH was dissolved in 50g (0.05kg) of water. The temperature of water rose by 5oC. Calculate the enthalpy of solution of NaOH.

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**1. Calculate energy change**

EH = c x m x ΔT = 4.18x0.05x5 = kJ 2. Calculate the number of moles of NaOH 1 mole NaOH=40g so 1.03g=1.03/40= mol 3. Calculate enthalpy of solution 0.026 moles: 1.045kJ 1 mole : 40.2kJ

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**Therefore the Enthalpy of solution= -40.2kJ**

Note that HSOLN can be a +ve or –ve value. You can work out which it is from the question.

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