1. 6. Calculate the total magnification of an object viewed under a) the low power objective and b) the high power objective?

2.  Supply check  Attendance  Remember to sign up for UT Quest and submit your “Test Paper” to turnitin.com  DUE TOMORROW  THIS IS THE EASIEST 100 YOU WILL EVER GET!

3. August 26, 2010

4.  A free body diagram is the visual representation of force vectors W OE = — mg N OS = + mg F OA = maf OS = µN ∑ F y = mg - mg = 0 ∑ F x = ma - µN = ma net F net = ma net

5.  #1 & 2 together  10 minutes to complete  #3 & 6 Groups 1, 4, 7  #4 & 7 Groups 2, 5, 8  #5 & 8 Groups 3, 6, 9

6. W OE = — mg N OS = + mg ∑ F y = N OS - W OE = 0 ∑ F y = mg - mg = 0

7. W OE = — mg N OS ∑ F ynet = N OS - W OE = ma net

8. W OE = — mg N OS = + mg F OA = ma ∑ F y = N OS - W OE = 0 = mg - mg = 0 ∑ F x = ma net

9. W OE = — mg N OS = + mg F OA = maf OS = µN ∑ F y = mg - mg = 0 ∑ F x = ma - µN = ma net F net = ma net

10. W OE = — mg N OS = + mg F OA = maf OS = µN ∑ F y = mg - mg = 0 ∑ F x = ma - µN = — ma net F net = — ma net

11. T OR = + mg W OE = — mg

12. T OR = + mg W OE = — mg F OA = ma

13. T OR = + mg W OE = — mg Can we directly measure the Tension? Is it still equal to +mg? Why or why not? -x +y The x and y are just the components of the actual forces. This is why they’re drawn with dotted lines. You must ALWAYS draw components with dotted lines. F OA = ma

14.  Trigonometry: deals with angles and sides of triangles  Sine  (sin  )  Opposite over  Hypoteneuse  C osine  (cos  )  Adjacent over  Hypoteneuse  T angent  (tan  )  Opposite over  A djacent  Y = Opp. X =Adj. Hyp.

15. x adj y opp T S O HC A HT O A i p y o d y a p d n p p s j pn p j sin Ѳ = opp = y hyp T cos Ѳ = adj = x hyp T tan Ѳ = opp = y adj x Ѳ

16. X T cos Ѳ =x adj Y T sin Ѳ = y opp T S O HC A HT O A i p y o d y a p d n p p s j pn p j T sin Ѳ = y T cos Ѳ = x Ѳ

17. T OR = + mg W OE = — mg -x T cos Ѳ =x +y T sin Ѳ = +y ∑ F y = T sin Ѳ - mg = 0 ∑ F x = ma - T cos Ѳ = 0 F OA = ma

18. W OE = — mg Ѳ Ѳ T OR2 T OR1 In order for this box to just be hanging, what does the upward y component of the tension HAVE to be??