Presentation on theme: "Lesson 8 G3 Two Source Interference of Waves"— Presentation transcript:
1 Lesson 8 G3 Two Source Interference of Waves G4 The Diffraction Grating
2 Lesson 8 – 2 source interference State the conditions necessary to observe interference between two sources.Explain, by means of the principle of superposition, the interference pattern produced by waves from two coherent point sources (The effect may be illustrated using water waves and sound waves in addition to EM waves).Outline a double-slit experiment for light and draw the intensity distribution of the observed fringe pattern (This should be restricted to the situation where the slit width is small compared to the slit separation so that diffraction effects of a single slit on the pattern are not considered).Solve problems involving two-source interference.
14 D P λ d O s P’ S1 T M S2 D = distance from slit to screen (few m) θθD = distance from slit to screen (few m)d = slit separation (0.5mm)s = distance from central maximum to first subsidiary maximum
15 sinθ = λ d tanθ = s D λ = s d D s = Dλ d At point P’, the path difference between waves from S1 and S2 is one whole wavelength. Thus they arrive in phase, constructively interfere and create a ‘bright fringe’.S1T = λDistance D is large and the wavelength of the light is small so θ must also be very small. We can also approximate that angle S1TS2 is a right angle.Using the small angle approximation sinθ = tanθ = θ or...sinθ = λdtanθ = sDλ = sd Ds = Dλd
19 The Diffraction Grating The diffraction grating is (in theory) a piece of opaque material with many parallel, equidistant and closely spaced transparent slits that transmit light. In practice lines are ruled onto glass with diamond leaving transparent glass in between.
20 Consider a grating with coherent, monochromatic light of wavelength λ incident upon it: BCAθNSection of gratingLight diffracted at θ to the normalMonochromatic light
21 If light from any pair of slits reaching a point in the distance and causes maximum constructive interference, we know that the path difference must be a whole number of wavelengths...AN = nλHence...Thus light from all slits constructively interferes with that from every other at values of θ determined by the equation, producing bright regions. This gives rise to the different order spectra for any particular wavelength of light.d sinθ = nλn = 0, 1, 2, 3 etc
22 n = 2n = 1n = 0Monochromatic lightn = 1Section of gratingn = 2
23 Note d is the separation of slits on the grating Gratings are often labelled “200 lines/mmi.e. d = 0.001/200 m = 5 x 10-6 m
24 ExperimentUse a diffraction grating to determine the wavelength of laser light.
25 The Diffraction Grating The diffraction grating is (in theory) a piece of opaque material with many parallel, equidistant and closely spaced transparent slits that transmit light. In practice lines are ruled onto glass with diamond leaving transparent glass in between.Experiment:Observe a white light source through both coarse (100 lines/mm) and fine (500 lines/mm) gratings. Repeat placing red or green filters in front of the grating.
28 Observations for white light: The diffraction spectra of white light has a central white band (called the zero order image).On either side are bright bands of colour. The first red band is the ‘first order spectrum’ for that wavelength. Further out is another identical red band - the ‘second order spectrum’ etc.Bands for the visible spectrum are seen, with violet being nearest the centre and red furthest.A finer grating forms less orders, further apart than on a coarse grating.
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