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Balancing Equations. Law of Conservation of Mass The Law of Conservation of Mass states: that mass is neither created nor destroyed in any chemical reaction.

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Presentation on theme: "Balancing Equations. Law of Conservation of Mass The Law of Conservation of Mass states: that mass is neither created nor destroyed in any chemical reaction."— Presentation transcript:

1 Balancing Equations

2 Law of Conservation of Mass The Law of Conservation of Mass states: that mass is neither created nor destroyed in any chemical reaction. Therefore balancing equations requires the same number of atoms on both sides of a chemical reaction. The number of atoms in the Reactants must equal the Number of atoms in the Products

3 Balance elements in the following order: 1. Nonmetals 2. Metals 3. Polyatomic ions 4. Hydrogen 5. Oxygen

4 Polyatomic Ions When balancing polyatomic ions treat them as one unit if they appear on both sides of the equation.

5 Balancing Equations Complete an atom inventory. N 2 + H 2 NH 3 __N__ __H__

6 Balancing Equations Nothing is balanced. Balance the nitrogen first by placing a coefficient of 2 in front of the NH 3. N 2 + H 2 2NH 3

7 Balancing Equations Hydrogen is not balanced. Place a 3 in front of H 2. N 2 + 3H 2 2NH 3 Complete a final atom inventory. __N__ __H__ 2 6

8 Balancing Equations Complete an atom inventory. C 3 H 8 + O 2 → CO 2 + H 2 O __C__ __H__ __O__

9 Balancing Equations Nothing is balanced. Balance the carbon first by placing a coefficient of 3 in front of the CO 2. C 3 H 8 + O 2 → 3CO 2 + H 2 O

10 Balancing Equations Now balance the hydrogen by placing a 4 in front of the water on the products side. C 3 H 8 + O 2 → 3CO 2 + 4H 2 O

11 Balancing Equations Balance the oxygen on the reactants side with a coefficient of 5. C 3 H 8 + 5O 2 → 3CO 2 + 4H 2 O Complete a final atom inventory. __C__ __H__ __O__

12 Balancing Equations Complete an atom inventory. → BF 3 + Li 2 SO 3 → B 2 (SO 3 ) 3 + LiF __B__ __F__ __Li__ __SO 3 __

13 Balancing Equations Nothing is balanced. Balance the fluorine first by placing a coefficient of 3 in front of the LiF. → BF 3 + Li 2 SO 3 → B 2 (SO 3 ) 3 + 3LiF

14 Balancing Equations Now balance the boron by placing a 2 in front of the BF 3 on the reactants side. → 2BF 3 + Li 2 SO 3 → B 2 (SO 3 ) 3 + 3LiF Notice we’ve unbalanced the fluorine, and now must adjust our coefficients.

15 Balancing Equations Now balance the boron by placing a 2 in front of the BF 3 on the reactants side. → 2BF 3 + Li 2 SO 3 → B 2 (SO 3 ) 3 + 6LiF Notice we’ve unbalanced the fluorine, and now must adjust our coefficients.

16 Balancing Equations Balance the lithium sulfite on the reactants side with a coefficient of 3. Complete a final atom inventory. → 2BF 3 + 3Li 2 SO 3 → B 2 (SO 3 ) 3 + 6LiF __B__ __F__ __Li__ __SO 3 __

17 YOU ARE BALANCED!!


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