 Problem of the Day Problem of the Day Computation Money next 20 - 21.

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Problem of the Day Problem of the Day Computation Money next 20 - 21

I need to find the most money amount to give to my school. I know that my choices are 400 dollar bills, 6000 dimes or 50,000 pennies. In order to solve this problem, I must find the dollar value for each money amount. Four hundred dollar bills would be \$400 since one bill represents \$1. Then 400 times \$1 = \$400. Six thousand dimes would be \$600.

Since there are ten dimes in a dollar, I would multiply 6000 by \$.10 = \$600. Finally, 50,000 pennies would be \$500. I would multiply 50,000 pennies by \$.01 since there are 100 pennies in a dollar. The best choice for my school would be the 6000 dimes which would be equivalent to \$600. It would make sense to take the 6000 dimes because the value amount of \$600 is greater than \$400 and \$500.

Answer: \$400 400 multiplied by \$1 = \$400 \$.10 6000 multiplied by \$.10 = \$600 \$.01 50,000 multiplied by \$.01 = \$500 6000 Dimes next

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