1. The Practice of Statistics, 5th Edition Starnes, Tabor, Yates, Moore Bedford Freeman Worth Publishers CHAPTER 5 Probability: What Are the Chances? 5.3 Conditional Probability and Independence

2. Learning Objectives After this section, you should be able to: The Practice of Statistics, 5 th Edition2 CALCULATE and INTERPRET conditional probabilities. USE the general multiplication rule to CALCULATE probabilities. USE tree diagrams to MODEL a chance process and CALCULATE probabilities involving two or more events. DETERMINE if two events are independent. When appropriate, USE the multiplication rule for independent events to COMPUTE probabilities. Conditional Probability and Independence

3. The Practice of Statistics, 5 th Edition3 What is a Conditional Probability? Q1: If we know that a student has pierced ears, what is the probability that the student is male? A1: P (is male given has pierced ears) =19/103 = or about 18.4% Q2: If we know that a student is a male, what is the probability that the he has pierced ears? A2: P (has pierced ears given a male) = 19/90 = or about 21.1% May look the same, but are asking two very different things.

4. The Practice of Statistics, 5 th Edition4 What is Conditional Probability? The probability we assign to an event can change if we know that some other event has occurred. This idea is the key to many applications of probability. When we are trying to find the probability that one event will happen under the condition that some other event is already known to have occurred, we are trying to determine a conditional probability. The probability that one event happens given that another event is already known to have happened is called a conditional probability. Suppose we know that event A has happened. Then the probability that event B happens given that event A has happened is denoted by P(B | A). The probability that one event happens given that another event is already known to have happened is called a conditional probability. Suppose we know that event A has happened. Then the probability that event B happens given that event A has happened is denoted by P(B | A). Read | as “given that” or “under the condition that”

5. The Practice of Statistics, 5 th Edition5 Calculating Conditional Probabilities To find the conditional probability P(A | B), use the formula The conditional probability P(B | A) is given by Calculating Conditional Probabilities

6. The Practice of Statistics, 5 th Edition6 Calculating Conditional Probabilities Find P(L) Find P(E | L) Find P(L | E) Total 3392 2952 3656 10000 Total 6300 1600 2100 P(L) = 3656 / 10000 = 0.3656 P(E | L) = 800 / 3656 = 0.2188 P(L| E) = 800 / 1600 = 0.5000 Consider the two-way table on page 321. Define events E: the grade comes from an EPS course, and L: the grade is lower than a B.

7. The Practice of Statistics, 5 th Edition7 The General Multiplication Rule The probability that events A and B both occur can be found using the general multiplication rule P(A ∩ B) = P(A) P(B | A) where P(B | A) is the conditional probability that event B occurs given that event A has already occurred. General Multiplication Rule In words, this rule says that for both of two events to occur, first one must occur, and then given that the first event has occurred, the second must occur.

8. The Practice of Statistics, 5 th Edition8 Tree Diagrams The general multiplication rule is especially useful when a chance process involves a sequence of outcomes. In such cases, we can use a tree diagram to display the sample space. Consider flipping a coin twice. What is the probability of getting two heads? Sample Space: HH HT TH TT So, P(two heads) = P(HH) = 1/4

9. The Practice of Statistics, 5 th Edition9 Tennis great Roger Federer made 63% of his first serves in the 2011 season. When Federer made his first serve, he won 78% of the points. When Federer missed his first serve and had to serve again, he won only 57% of the points. Suppose we randomly choose a point on which Federer served. What’s the probability that Federer makes the first serve and wins the point? When Federer is serving, what’s the probability that he wins the point? Going in reverse. Given that Federer wins the point, how likely is it that he missed his first serve?

10. The Practice of Statistics, 5 th Edition10 Example: Tree Diagrams 51.15% of teens are online and have posted a profile. The Pew Internet and American Life Project finds that 93% of teenagers (ages 12 to 17) use the Internet, and that 55% of online teens have posted a profile on a social-networking site. What percent of teens are online and have posted a profile?

11. The Practice of Statistics, 5 th Edition11 Read example on P.325 This is just like the Federer problem and can be another example.

12. The Practice of Statistics, 5 th Edition12 Conditional Probability and Independence When knowledge that one event has happened does not change the likelihood that another event will happen, we say that the two events are independent. Two events A and B are independent if the occurrence of one event does not change the probability that the other event will happen. In other words, events A and B are independent if P(A | B) = P(A) and P(B | A) = P(B). Two events A and B are independent if the occurrence of one event does not change the probability that the other event will happen. In other words, events A and B are independent if P(A | B) = P(A) and P(B | A) = P(B). When events A and B are independent, we can simplify the general multiplication rule since P(B| A) = P(B). Multiplication rule for independent events If A and B are independent events, then the probability that A and B both occur is P(A ∩ B) = P(A) P(B) Multiplication rule for independent events If A and B are independent events, then the probability that A and B both occur is P(A ∩ B) = P(A) P(B)

13. The Practice of Statistics, 5 th Edition13 Multiplication Rule for Independent Events Following the Space Shuttle Challenger disaster, it was determined that the failure of O-ring joints in the shuttle’s booster rockets was to blame. Under cold conditions, it was estimated that the probability that an individual O-ring joint would function properly was 0.977. Assuming O-ring joints succeed or fail independently, what is the probability all six would function properly? P( joint 1 OK and joint 2 OK and joint 3 OK and joint 4 OK and joint 5 OK and joint 6 OK) By the multiplication rule for independent events, this probability is: P(joint 1 OK) · P(joint 2 OK) · P (joint 3 OK) … · P (joint 6 OK) = (0.977)(0.977)(0.977)(0.977)(0.977)(0.977) = 0.87 There’s an 87% chance that the shuttle would launch safely under similar conditions (and a 13% chance that it wouldn’t).

14. Section Summary In this section, we learned how to… The Practice of Statistics, 5 th Edition14 CALCULATE and INTERPRET conditional probabilities. USE the general multiplication rule to CALCULATE probabilities. USE tree diagrams to MODEL a chance process and CALCULATE probabilities involving two or more events. DETERMINE if two events are independent. When appropriate, USE the multiplication rule for independent events to COMPUTE probabilities. Conditional Probabilities and Independence