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Published byHeather Wilkerson Modified over 7 years ago
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LECTURE 5 OF 8 Topic 5: VECTORS 5.5 Application of Vectors In Geometry
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LEARNING OUTCOMES find a vector equation of the straight line in the form of where t is a scalar. (b) find the parametric and cartesian equations of a straight line.
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The Equation of a Line In Space
A line in space is a straight line. Suppose that R (x,y,z) is a point which is free to move on a line containing a fixed point A (a1,a 2,a3). If is a direction vector of the line NOTE :
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, t is a scalar A vector equation of a line is : NOTE : To find a vector equation of a line, we have to determine a position vector of one point on the line and any vector which is parallel to the line, then use the above equation .
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In the component form, it can be written as
Equating the respective components, we obtain, x = a1 + tv1 y = a2 + tv2 z = a3 + tv3 The parametric equations of the line
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x = a1 + tv1 y = a2 + tv2 z = a3 + tv3 tv1 = x - a1 tv2 = y – a2 tv3 = z – a3 Isolating t in each of these equations gives, The Cartesian equations of the line
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Find the vector equation,the parametric
Example 1 Find the vector equation,the parametric equations and the Cartesian equation of the line through (1,-2,3) in the direction of Solution the vector equation is
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The parametric equations are
x = 1 + 4t, y = t, z = 3 - 6t The Cartesian equations are
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Example 2 Find a vector equation for a line passing through a point with position vector and is parallel to the line with cartesian equation Hence find a point on the line when y = 0
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Solution The vector equation is
A general point on the line has coordinates x = 5 + 3t, y = t, z = t If y = 0 0 = t t =
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when t = The point on the line where y = 0 is
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Example 3 a) Find parametric equations for the line L passing through the points A (2,4,-1) and B (5,0,7). b) Where does the line intersect the xy-plane ?
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Solution a) The vector equation is The parametric equations
x = 2 + 3t, y = 4 - 4t, z = t
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b) The line intersects the xy-plane
at the point where z = 0 So, when z = 0 0 = t t = When t = x = 2 + 3( ) = 2 + =
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y = 4 - 4( ) = 4 - = The line intersects the xy-plane at
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Conclusion the vector equation of the line : To find the equation, determine
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The vector equation of the line :
The parametric equations of the line : x = a1 + tv1 y = a2 + tv2 z = a3 + tv3 The Cartesian equations of the line
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