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Lecture 27: Lift Many biological devices (Biofoils) are used to create Lift. How do these work?

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Presentation on theme: "Lecture 27: Lift Many biological devices (Biofoils) are used to create Lift. How do these work?"— Presentation transcript:

1 Lecture 27: Lift Many biological devices (Biofoils) are used to create Lift. How do these work?

2 chord section analysis….
First, some definitions… wing section,c (chord) wing length, R wing area, S total force (normal to wing) drag lift (normal to U) (parallel to U) chord section analysis…. wing velocity = U angle of attack = a

3 air deflected downward by wing
Two ways to derive lift: 1) mass deflection total force a U Surface area, S air deflected downward by wing Pressure always acts normal to the surface of an object. Therefore, this mass deflection force acts roughly perpendicular to surface of biofoil.

4 air deflected downward by wing
1) Mass deflection total force lift Lift and drag are defined as components perpendicular and parallel to direction of motion. a drag U Surface area, S air deflected downward by wing

5 RoboFly dimensionless scaling parameters amplitude · length2
Borf_silent amplitude · length2 frequency · viscosity Reynolds number = reduced frequency = forward velocity length · angular velocity dimensionless scaling parameters

6 Fs a q total force 90o CL CD total force coefficient CT
- 9 1 8 2 7 3 6 4 5 . total force coefficient CT angle of attack a (degs) - 9 1 8 2 7 3 6 4 5 90o total force orientation q (degs) angle of attack a (degs)

7 a { CT CT cos a CT CT = 3.5 sin a CT sin a CD = CT sin a CL = CT cos a
1 5 3 4 6 7 9 2 CT angle of attack (a) CT = 3.5 sin a CT sin a a CT CT cos a 1 5 3 4 6 7 9 2 angle of attack (a) CL = CT cos a CL 1 5 3 4 6 7 9 2 CD angle of attack (a) CD = CT sin a { viscous drag

8 total force lift a drag U Surface area, S

9 highest lift:drag ratio
Polar plot of lift and drag: 1 2 3 4 - drag coefficient lift coefficient a=-9 a=22.5 a=45 a=90 highest lift:drag ratio - 9 1 8 2 7 3 6 4 5 . angle of attack (degs) force coefficients CL CD

10 2. Circulation U fluid travels faster over to of biofoil
Flow is tangential at trailing edge Law of continuity applies to streamline Flow separates at leading edge U

11 Kutta-Joukowski Theorem:
Difference in velocity across surface is equivalent to net circular flow around biofoil = Circulation, G mathematically: U Kutta-Joukowski Theorem: (lift per unit span) combine with previous definition: R=biofoil length c= biofoil width

12 +G -G G=0 G=0 Consider 2D biofoil starting from rest:
starting vortex bound vortex Required by Kelvin’s Law

13 Circulation, G, is constant along vortex ring
Consider 3D biofoil starting from rest: Helmholtz’ Law requires that a vortex filament cannot end abruptly: bound vortex Downward flow through center of vortex ring starting vortex tip vortex Circulation, G, is constant along vortex ring

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15 How is structure of vortex ring related to lift on biofoil?
forward velocity, U R Circulation, G Area = A Ring momentum = mass flux through ring= GrA Force = d/dt (GrA) = Gr d/dt(A) = Gr R U Force/R = GrU = Kutta-Joukwski Therefore, elongation of vortex ring is manifestation of force on biofoil.

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17 ux uy u(x,y) Three important descriptors of fluid motion:
1. velocity, u(x,y) u(x,y) ux uy 2. vorticity, w(x,y) 3. circulation, G Dx Duy w = G = S w x y Dux Dy

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20 Fslap = m U / t where m is bolus of accelerated water, moving at velocity, u impulse (F x t) = mass x velocity Fstroke = r G A /t Momentum of vortex ring r G A G = circulation A

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