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Welcome to Introduction to Bioinformatics Wednesday, 16 October Metabolic modeling Table of Contents First exam: Rules of the game Sep 27, SQ4: Write subroutine.

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Presentation on theme: "Welcome to Introduction to Bioinformatics Wednesday, 16 October Metabolic modeling Table of Contents First exam: Rules of the game Sep 27, SQ4: Write subroutine."— Presentation transcript:

1 Welcome to Introduction to Bioinformatics Wednesday, 16 October Metabolic modeling Table of Contents First exam: Rules of the game Sep 27, SQ4: Write subroutine to print score array PS1M.8: Probability of evolution

2 Trypanosoma brucei Causative agent of sleeping sickness Life Cycle Central Nervous System Death

3 Trypanosoma brucei Dependence on glycolysis Entry of glucose Phosphorylation Breakdown to triose phosphates Conversion to pyruvate Release of pyruvate Arsenate (AsO 4 = As i ) Competitive with P i As i AMP-P-As AMP-P +As i Treatment

4 Trypanosoma brucei Dependence on glycolysis Something more specific? Treatment Choice #1 Starve the cell inhibitor 1

5 Trypanosoma brucei Dependence on glycolysis Something more specific? Treatment Choice #1 Starve the cell Choice #2 Stuff the cell inhibitor 2 pyruvate

6 Trypanosoma brucei Test ideas for inhibitors [glucose] added [ATP] [I] 0 1 5 10 25 inhibitor 1 We know characteristics of enzymes

7 Characteristics of enzymes Analogy of radioactivity How often does 32 S appear? One day (1/20) 1/20 of an atom per day? 1 atom of 32 S 20 atoms of 32 P per day __atoms of 32 S per day [X atoms of 32 P] = [ 32 P] concentration k rate constant = d[ 32 S] / dt rate of change

8 Characteristics of enzymes Analogy of radioactivity Which quantity is an intrinsic characteristic? One day (1/20) [ 32 P] concentration k rate constant = d[ 32 S] / dt rate of change

9 Characteristics of enzymes Analogy of radioactivity [ 32 P] concentration k rate constant = d[ 32 S] / dt rate of change [ 14 C] concentration k rate constant = d[ 14 N] / dt rate of change One day (1/20)

10 Characteristics of enzymes Chemical reactions AMP-P-AsAMP-P +As i [ 32 P] concentration k rate constant = d[ 32 S] / dt rate of change

11 Characteristics of enzymes Chemical reactions [AMP-P-As] concentration k rate constant = d[AMP-P ] / dt rate of change AMP-P-AsAMP-P +As i = = d[As i ] / dt rate of change = – = d[AMP-P-As i ] / dt rate of change

12 Characteristics of enzymes Chemical reactions [AMP-P-As] concentration k rate constant AMP-P-AsAMP-P +As i = – = d[AMP-P-As i ] / dt rate of change [S] k = – = d[S] / dt A differential equation

13 Characteristics of enzymes Chemical reactions [AMP-P-As] concentration k rate constant AMP-P-AsAMP-P +As i = – = d[AMP-P-As i ] / dt rate of change = d[S] / dt A differential equation = –k[S] = S 0 e -k(t-to) [S] Its solution? = S 0 (–k) e -k(t-to) = -k S 0 e -k(t-to) = -k [S] = d[S] / dt Check:

14 Characteristics of enzymes Chemical reactions = d[S] / dt = –k[S] [S] = S 0 e -k(t-to)

15 Characteristics of enzymes Chemical reactions [S] = Δt [S] = S 0 e -k(t-to) S0S0

16 Characteristics of enzymes Chemical reactions Δt = d[S] / dt = –k[S] S0S0 + Δt d[S] / dt[S] =S0S0

17 Characteristics of enzymes Chemical reactions (Program)

18 Characteristics of enzymes Chemical reactions = d[S] / dt = –k[S] [S] = S 0 e -k(t-to)

19 Characteristics of enzymes Chemical reactions Δt = d[S] / dt = –k[S] S0S0 + Δt d[S] / dt[S] =S0S0 Slope 0 = -k[S 0 ] [S 1 ] =+ Δt d[S] / dtS0S0 Slope 1 = -k[S 1 ] Use average of Slope 0 and Slope 1

20 Characteristics of enzymes Chemical reactions Δt = d[S] / dt = –k[S] S0S0 + Δt d[S] / dt[S] =S0S0 Slope 0 = -k[S 0 ] [S 1 ] =+ Δt d[S] / dtS0S0 Slope 1 = -k[S 1 ] Use average of Slope 0 and Slope 1 Runge-Kutta method

21 inhibitor 1 Characteristics of enzymes Enzymatic reactions

22 [G6P] concentration k rate constant Glucose-6-phosphate Fructose-6-phosphate = – = d[G6P] / dt rate of change k  0

23 Characteristics of enzymes Enzymatic reactions G6P + E G6P·EF6P·EF6P + E E-complex

24 Characteristics of enzymes Enzymatic reactions G6P + E 1 E 1 -complexF6P + E 1 d d[G6P] / dt = d[E 1 ] / dt = d[E 1 -complex] / dt = d[F6P] / dt = -[G6P] [E 1 ] k 1 f + [E 1 -complex] k 1 r k1fk1f k1rk1r k 1 cf k 1 cr -[G6P] [E 1 ] k 1 f + [E 1 -complex] k 1 r + [E 1 -complex] k 1 cf - [F6P] [E 1 ] k 1 cr +[G6P] [E 1 ] k 1 f - [E 1 -complex] k 1 r - [E 1 -complex] k 1 cf + [F6P] [E 1 ] k 1 cr +[E 1 -complex] k 1 cf - [F6P] [E 1 ] k 1 cr

25 Characteristics of enzymes Enzymatic reactions G6P + E 1 E 1 -complexF6P + E 1 d d[E 1 ] / dt = d[I] / dt = d [E 1 -I-complex] / dt = k1fk1f k1rk1r k 1 cf k 1 cr - [G6P] [E 1 ] k 1 f + [E 1 -complex] k 1 r +[E 1 -complex] k 1 cf - [F6P] [E 1 ] k 1 cr - [I] [E 1 ] k 1 if + [E 1 -I-complex] k 1 ir I + E1I + E1 k 1 if k 1 ir E 1 -I-complex

26 Characteristics of enzymes Enzymatic reactions G6P + E 1 E 1 -complexF6P + E 1 d d[G6P] / dt = d[E 1 ] / dt = d[E 1 -complex] / dt = d[F6P] / dt = -[G6P] [E 1 ] k 1 f + [E 1 -complex] k 1 r k1fk1f k1rk1r k 1 cf k 1 cr -[G6P] [E 1 ] k 1 f + [E 1 -complex] k 1 r + [E 1 -complex] k 1 cf - [F6P] [E 1 ] k 1 cr +[G6P] [E 1 ] k 1 f - [E 1 -complex] k 1 r - [E 1 -complex] k 1 cf + [F6P] [E 1 ] k 1 cr +[E 1 -complex] k 1 cf - [F6P] [E 1 ] k 1 cr

27 Characteristics of enzymes Enzymatic reactions G6P + E 1 E 1 -complexF6P + E 1 d[E 1 -complex] / dt = d[F6P] / dt = k1fk1f k1rk1r k1ck1c +[G6P] [E 1 ] k 1 f - [E 1 -complex] k 1 r - [E 1 -complex] k 1 c + [F6P] [E 1 ] k 1 cr +[E 1 -complex] k 1 c - [F6P] [E 1 ] k 1 cr 0 (steady state assumption)

28 Characteristics of enzymes Enzymatic reactions G6P + E 1 E 1 -complexF6P + E 1 d[E 1 -complex] / dt = d[F6P] / dt = k1fk1f k1rk1r k 1 cf +[G6P] [E 1 ] k 1 f - [E 1 -complex] k 1 r - [E 1 -complex] k 1 c + [F6P] [E 1 ] k 1 cr +[E 1 -complex] k 1 c - [F6P] [E 1 ] k 1 cr [G6P] [E 1 ] k 1 f = [E 1 -complex] k 1 c - [E 1 -complex] k 1 r [G6P] ([E total ]-[E 1 -complex]) k 1 f = [E 1 -complex] (k 1 c - k 1 r)

29 Characteristics of enzymes Enzymatic reactions G6P + E 1 E 1 -complexF6P + E 1 d[F6P] / dt = k1fk1f k1rk1r k 1 cf +[E 1 -complex] k 1 c - [F6P] [E 1 ] k 1 cr [G6P] [E 1 ] k 1 f = [E 1 -complex] k 1 c - [E 1 -complex] k 1 r [G6P] [E total ] k 1 f [G6P] [E total ] [G6P] + (k 1 c - k 1 r) [G6P] + (k 1 c - k 1 r)/k 1 f [G6P] ([E total ]-[E 1 -complex]) k 1 f = [E 1 -complex] (k 1 c - k 1 r) [E 1 -complex] = =

30 Characteristics of enzymes Enzymatic reactions G6P + E 1 E 1 -complexF6P + E 1 d[F6P] / dt = +[E 1 -complex] k 1 c k1fk1f k1rk1r k 1 cf [G6P] [E total ] k 1 c [G6P] + (k 1 c - k 1 r)/k 1 f = [G6P] [E total ] k 1 c [G6P] + K m =

31 Characteristics of enzymes Enzymatic reactions G6P + E 1 E 1 -complexF6P + E 1 d[F6P] / dt = +[E 1 -complex] k 1 c k1fk1f k1rk1r k 1 cf [G6P] [E total ] k 1 c [G6P] + (k 1 c - k 1 r)/k 1 f = [G6P] [E total ] k 1 c [G6P] + K m = Max d[F6P] / dt = (V max ) = [E total ] k 1 c

32 Characteristics of enzymes Enzymatic reactions G6P + E 1 E 1 -complexF6P + E 1 d[F6P] / dt = k1fk1f k1rk1r k 1 cf [G6P] V Max [G6P] + K m d[product] / dt = [S] V Max [S] + K m v (velocity) =

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