1. Solving Quadratic Equations by Factoring

2. Ways of finding the factors/ zeros
Quadratic formula
Factorization using zero property
By taking square roots
By squaring

3. Imaginary roots/ complex roots Fractions Decimals
Types of solutions
Real roots
Imaginary roots/ complex roots
Fractions
Decimals

4. For any real numbers a and b, if ab=0, then either a=0, b=0, or both.
Zero Product Property
For any real numbers a and b, if ab=0, then either a=0, b=0, or both.

5. STEPS Solving a Quadratic Equation by Factoring
Step 1 Write the equation in standard form.
Step 2 Factor completely.
Step 3 Use the zero-factor property. Set each factor with a variable equal to zero.
Step 4 Solve each equation produced in step 3.

6. Quadratic Equations
Standard Form

7. The solutions are -3 and 1/2.
In this first example, the equation is already factored and is set equal to zero. To solve, simply set the individual factors equal to zero.
The solutions are -3 and 1/2.

8. Factor using “difference of two squares.”
In this example, you must first factor the equation. Notice the familiar pattern. After factoring, set the individual factors equal to zero.
Factor using “difference of two squares.”

9. Now, try several problems
Now, try several problems. Write these on your own paper, showing all steps carefully.

10. Here are the answers.
If all are correct, you’re finished!

11. Solutions… work it out 1.

12. 2.

13. 3.

14. 4.

15. How to factor a quadratic equation?
Factoring a polynomial means expressing it as a product of other polynomials.

16. Factoring Method using difference of squares
Factoring polynomials that are a difference of squares.

17. A “Difference of Squares” is a binomial (. 2 terms only
A “Difference of Squares” is a binomial (*2 terms only*) and it factors like this:

18. To factor, express each term as a square of a monomial then apply the rule...

19. Here is another example:

20. Try these on your own:

21. Factoring Method Finding gcf
Factoring polynomials with a common monomial factor (using GCF).
**Always look for a GCF before using any other factoring method.

22. Steps: 1. Find the greatest common factor (GCF).
2. Divide the polynomial by the GCF. The quotient is the other factor.
3. Express the polynomial as the product of the quotient and the GCF.

23. This one uses a different technique than the previous ones
This one uses a different technique than the previous ones. Really, this is something you should consider at the beginning of every factoring problem. See if you can solve it.
Did you take out GCF?

24. Step 1:
Step 2: Divide by GCF

25. The answer should look like this:

26. Factor these on your own looking for a GCF.

27. Factoring Method
Factoring a trinomial in the form:

28. Solve by factoring into two binomials
Step 1: Make one side zero, if not already
Step 2: Factor into two binomials
(x + __)(x + ___) = 0
Step 3: Set each factor to zero and solve.

29. 2. Product of first terms of both binomials
Factoring a trinomial:
1. Write two sets of parenthesis, ( )( ). These will be the factors of the trinomial.
2. Product of first terms of both binomials
must equal first term of the trinomial.
Next

30. Factoring a trinomial:
3. The product of last terms of both binomials must equal last term of the trinomial (c).
4. Think of the FOIL method of multiplying binomials, the sum of the outer and the inner products must equal the middle term (bx).

31. x -2 -4 Factors of +8: 1 & 8 2 & 4 -1 & -8 -2 & -4 2x + 4x = 6x
O + I = bx ?
Factors of +8:
1 & 8
2 & 4
-1 & -8
-2 & -4
1x + 8x = 9x
2x + 4x = 6x
-1x - 8x = -9x
-2x - 4x = -6x

32. Check your answer by using FOIL

33. In the next example, you must set the equation equal to zero before factoring. Then set the individual factors equal to zero and solve.

34. Re-write this example in the proper form
Re-write this example in the proper form. Notice that the leading coefficient is not one. Use an appropriate factoring technique. Then solve as you have done before.

35. One side needs to be zero first!
Practice
Solve
One side needs to be zero first!

36. Divide both sides by GCF first!
Practice
Solve
Divide both sides by GCF first!

37. Factoring a perfect square trinomial in the form:
Factoring Technique
continued
Factoring a perfect square trinomial in the form:

38. Perfect Square Trinomials can be factored just like other trinomials (guess and check), but if you recognize the perfect squares pattern, follow the formula!

39. a b
Does the middle term fit the pattern, 2ab?
Yes, the factors are (a + b)2 :

40. One side needs to be zero first!
Practice
Solve
One side needs to be zero first!

41. a b
Does the middle term fit the pattern, 2ab?
Yes, the factors are (a - b)2 :

42. Try these on your own:

43. Answers:

44. Solve

45. Solve.
BACK

46. Solve.

47. Solve

48. Number Of Solutions
The degree of a polynomial is equal to the number of solutions.
Three solutions!!!

49. Solve.
BACK

50. x2 – 9x + 20 = 0 (x – 4)(x – 5) = 0 x – 4 = 0 x = 4 x – 5 = 0 x = 5
Example:
x2 – 9x + 20 = 0
(x – 4)(x – 5) = 0
x – 4 = 0
x = 4
x – 5 = 0
x = 5
x = {5, 4}
Standard form
Factor
Set each factor = 0
Solve
Write the solution set

51. 4x2 – 49 = 0 (2x + 7)(2x – 7) = 0 2x + 7 = 0 2x – 7 = 0 Example
Standard form
Factor
Set each factor = 0
Solve
Write the solution set
SOLUTION IS

52. Step 1: Factor the polynomial. (x - 6)(x + 6) = 0
How would you solve the following equation?
x2 – 36 = 0
Step 1: Factor the polynomial.
(x - 6)(x + 6) = 0

53. This equation has two solutions or zeros: x = 6 or x = -6.
Step 2: Apply the zero product property which states that
For all numbers a and b, if ab = 0, then
a = 0, b = 0, or both a and b equal 0.
(x - 6)(x + 6) = 0
Therefore (x – 6) = 0 or (x + 6) = 0.
x – 6 = 0
x + 6 = 0 or
x = 6
x = -6
This equation has two solutions or zeros: x = 6 or x = -6.

54. x2 – 25 = 0 x2 + 7x – 8 = 0 x2 – 12x + 36 = 0 c2 – 8c = 0 You Try It
Solve the following equations.
x2 – 25 = 0
x2 + 7x – 8 = 0
x2 – 12x + 36 = 0
c2 – 8c = 0

55. Summary of Steps
Get a value of zero on one side of the equation.
Factor the polynomial if possible.
Apply the zero product property by setting each factor equal to zero.
Solve for the variable.

56. SOLVING QUADRATIC EQUATIONS- When to use what???
Get the equation in standard form:
If there is no middle term (b = 0) then get the x2 alone and square root both sides (if you get a negative under the square root there are no real solutions).
If there is no constant term (c = 0) then factor out the common x and solve (set each factor = 0).
If a, b and c are non-zero, see if you can factor and use the factor law to solve.
If it doesn't factor or is hard to factor, use the quadratic formula to solve (if you get a negative under the square root there are no real solutions).

57. Vocabulary If b2 = a then b is a square root of a.
All positive real numbers have two square roots
A positive square root (or principle square root) and a negative square root.
This is written as

58. Vocabulary A square root is written with the radical symbol
The number or expression inside the radical symbol is the radicand.

59. Vocabulary Give some examples of perfect squares
The square of an integer is called a perfect square.
Give some examples of perfect squares

60. Simplify each expression:

61. Solving Quadratic Equations: Solving by Taking Square Roots
Isolate the squared variable term
Put the number over on the other side

62. Solving quadratics by taking square roots
Solve each equation.
a. x2=4 b. x2=5 c. x2=0 d. x2=-1
x2=4 has two solutions, x = 2, x = -2
x2=5 has two solutions, x =√5, x =- √5
x2=0 has one solution, x = 0
x2=-1 has no real solution

63. Then the solution is x = ± 2
x2 – 4 = 0 
x2 = 4
I know that, when solving an equation, I can do whatever I like to that equation as long as I do the same thing to both sides of the equation. On the left-hand side of this particular equation, I have an x2, and I need a plain x. To turn an x2 into an x, I can take the square root of each side of the equation:

x = ± 2
Then the solution is x = ± 2

64. Example 2:
Solve 9m2 = 169

65. Example 1:
Solve the equation:
x2 – 7 = 9
z = 5

66. Solve x2 – 50 = 0.
This quadratic has a squared part and a number part. I'll start by adding the numerical term to the other side of the equaion (so the squared part is by itself), and then I'll square-root both sides. I'll need to remember to simplify the square root:

69. Solve by rewriting equation
Solve 3x2 – 48 = 0
3x2 – =
3x2 = 48
3x2 / 3 = 48 / 3
x2 = 16
After taking square root of both sides,
x = ± 4

70. Solving Quadratics by Using Square Roots
Solve each equation.
Ex. 5
Ex. 6
Ex. 7
Can’t take the square
root of a negative.

71. Solving Quadratics by Using Square Roots
Solve the following for x.
Ex. 4
Add 98 to both sides.
Divide both sides by 2.
Square root both sides.
Remember: When you square root something, it gives you a plus and a minus answer.

72. Example 3:
Solve 2x2 + 5 = 15

73. Example 4:
Solve 3(x + 3)2 = 39

74. You Try:
w2 – 9 = 0
4r2 – 7 = 9
2(y + 4)2 = 18

75. Equation of a falling object
When an object is dropped, the speed with which it falls continues to increase. Ignoring air resistance, its height h can be approximated by the falling object model.
h is the height in feet above the ground
t is the number of seconds the object has been falling
s is the initial height from which the object was dropped

76. Application
An engineering student is in an “egg dropping contest.” The goal is to create a container for an egg so it can be dropped from a height of 32 feet without breaking the egg. To the nearest tenth of a second, about how long will it take for the egg’s container to hit the ground? Assume there is no air resistance.

77. The question asks to find the time it takes for the container to hit the ground.
Initial height (s) = 32 feet
Height when its ground (h) = 0 feet
Time it takes to hit ground (t) = unknown

78. Substitute
0 = -16t2 + 32
= -16t – 32
-32 = -16t2
-32 / -16 = -16t2 / -16
2 = t2
t = √2 seconds or approx. 1.4 seconds

79. Solving Quadratic Equations by Completing the Square

80. Perfect Square Trinomials
Examples
x2 + 6x + 9
x2 - 10x + 25
x2 + 12x + 36

81. Creating a Perfect Square Trinomial
In the following perfect square trinomial, the constant term is missing X2 + 14x + ____
Find the constant term by squaring half the coefficient of the linear term.
(14/2) X2 + 14x + 49

82. Perfect Square Trinomials
Create perfect square trinomials.
x2 + 20x + ___
x2 - 4x + ___
x2 + 5x + ___
100 4
25/4

83. Solving Quadratic Equations by Completing the Square
Solve the following equation by completing the square:
Step 1: Move quadratic term, and linear term to left side of the equation

84. Solving Quadratic Equations by Completing the Square
Step 2: Find the term that completes the square on the left side of the equation. Add that term to both sides.

85. Solving Quadratic Equations by Completing the Square
Step 3: Factor the perfect square trinomial on the left side of the equation. Simplify the right side of the equation.

86. Solving Quadratic Equations by Completing the Square
Step 4: Take the square root of each side

87. Solving Quadratic Equations by Completing the Square
Step 5: Set up the two possibilities and solve

88. Completing the Square-Example #2
Solve the following equation by completing the square:
Step 1: Move quadratic term, and linear term to left side of the equation, the constant to the right side of the equation.

89. Solving Quadratic Equations by Completing the Square
Step 2: Find the term that completes the square on the left side of the equation. Add that term to both sides.
The quadratic coefficient must be equal to 1 before you complete the square, so you must divide all terms by the quadratic coefficient first.

90. Solving Quadratic Equations by Completing the Square
Step 3: Factor the perfect square trinomial on the left side of the equation. Simplify the right side of the equation.

91. Solving Quadratic Equations by Completing the Square
Step 4: Take the square root of each side

92. Ex 4 Solve by completing the square

93. Solving Quadratic Equations by Completing the Square: Try the following examples. Do your work on your paper and then check your answers.

95. Solving Equations by graphing
When we talk about solving these equations, we want to find the value of x when y = 0. These values, where the graph crosses the x-axis, are called the x-intercepts.
These values are also referred to as solutions, zeros, or roots.

96. Quadratic Solutions The number of real solutions is at most two.
No solutions
One solution
Two solutions

97. Graphing Quadratic Equations
The graph of a quadratic equation is a parabola.
The roots or zeros are the x-intercepts.
The vertex is the maximum or minimum point.
All parabolas have an axis of symmetry.

98. Vertex: (-1, 9) Roots: (-4, 0) (2, 0) Viewing window: Xmin= -10
Graph y= -x2 - 2x + 8 and find its roots.
Vertex: (-1, 9)
Roots: (-4, 0) (2, 0)
Viewing window:
Xmin= -10
Xmax=10
Ymin= -10
Ymax= 10

99. Identifying Solutions
Example f(x) = x2 - 4
Solutions are -2 and 2.

100. Identifying Solutions
Now you try this problem.
f(x) = 2x - x2
Solutions are 0 and 2.

101. Graphing Quadratic Equations
Graph y = x2 - 4x
Roots 0 and 4 , Vertex (2, -4) ,
Axis of Symmetry x = 2

102. Solving Quadratics by Graphing

103. Solving Quadratics by Graphing
Ex. 3

105. I can solve quadratic equations by graphing.
I can solve quadratic equations by using square roots.