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Solving Quadratic Equations by Finding Square Roots This lesson comes from chapter 9.1 from your textbook, page 503.

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Presentation on theme: "Solving Quadratic Equations by Finding Square Roots This lesson comes from chapter 9.1 from your textbook, page 503."— Presentation transcript:

1 Solving Quadratic Equations by Finding Square Roots This lesson comes from chapter 9.1 from your textbook, page 503

2 What is a square root? If a number square (b 2 ) = another number (a), then b is the square root of a. Example: If 3 2 = 9, then 3 is the square root of 9

3 Some basics… All positive numbers have two square roots The 1 st is a positive square root, or principal square root. The 2 nd is a negative square root Square roots are written with a radical symbol You can show both square roots by using the “plus-minus” symbol ±

4 Find the square root of numbers

5 Perfect Squares: Numbers whose square roots are integers or quotients of integers.

6 Evaluate a Radical Expression

7 Quadratic Equations Standard form: ax 2 + bx + c = 0 a is the leading coefficient and cannot be equal to zero. If the value of b were equal to zero, the equation becomes ax 2 + c = 0. We can solve equations is this form by taking the square root of both sides.

8 Key Concepts When x 2 = d If d > 0, then x 2 = d has two solutions If d = 0, then x 2 = d has one solution If d < 0, then x 2 = d has no real solution

9 Solving quadratics Solve each equation. a. x 2 =4 b. x 2 =5 c. x 2 =0 d. x 2 =-1 x 2 =4 has two solutions, x = 2, x = -2 x 2 =5 has two solutions, x =√5, x =- √5 x 2 =0 has one solution, x = 0 x 2 =-1 has no real solution

10 Solve by rewriting equation Solve 3x 2 – 48 = 0 3x 2 – = x 2 = 48 3x 2 / 3 = 48 / 3 x 2 = 16 After taking square root of both sides, x = ± 4

11 Equation of a falling object When an object is dropped, the speed with which it falls continues to increase. Ignoring air resistance, its height h can be approximated by the falling object model. h is the height in feet above the ground t is the number of seconds the object has been falling s is the initial height from which the object was dropped

12 Application An engineering student is in an “egg dropping contest.” The goal is to create a container for an egg so it can be dropped from a height of 32 feet without breaking the egg. To the nearest tenth of a second, about how long will it take for the egg’s container to hit the ground? Assume there is no air resistance.

13 The question asks to find the time it takes for the container to hit the ground. Initial height (s) = 32 feet Height when its ground (h) = 0 feet Time it takes to hit ground (t) = unknown

14 Substitute 0 = -16t = -16t – = -16t / -16 = -16t 2 / = t 2 t = √2 seconds or approx. 1.4 seconds


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