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Charles Law Charles’s Law Jacques Charles determined the relationship between temperature and volume of a gas. He measured the volume of air at different.

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Presentation on theme: "Charles Law Charles’s Law Jacques Charles determined the relationship between temperature and volume of a gas. He measured the volume of air at different."— Presentation transcript:

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2 Charles Law

3 Charles’s Law Jacques Charles determined the relationship between temperature and volume of a gas. He measured the volume of air at different temperatures, and observed a pattern of behavior which led to his mathematical law. During his experiments pressure of the system and amount of gas were held constant. Jacques Charles determined the relationship between temperature and volume of a gas. He measured the volume of air at different temperatures, and observed a pattern of behavior which led to his mathematical law. During his experiments pressure of the system and amount of gas were held constant.

4 Volume of balloon at room temperature Volume of balloon at 5°C

5 Temp How does Temperature and Volume of gases relate graphically? Volume V/T = k Pressure, # of particles remain constant Pressure, # of particles remain constant

6 Temperature (T) The temperature of a gas is generally measured with a thermometer in Celsius. All calculations involving gases should be made after converting the Celsius to Kelvin temperature. The temperature of a gas is generally measured with a thermometer in Celsius. All calculations involving gases should be made after converting the Celsius to Kelvin temperature. Kelvin = C° + 273

7 Charles’s Mathematical Law: since V/T = k Eg: A gas has a volume of 3.0 L at 127°C. What is its volume at 227 °C? V 1 V 2 T 1 T 2 = What if we had a change in conditions?

8 1)determine which variables you have:  T 1 = 127°C + 273 = 400K  V 1 = 3.0 L  T 2 = 227°C + 273 = 5ooK  V 2 = ?  T 1 = 127°C + 273 = 400K  V 1 = 3.0 L  T 2 = 227°C + 273 = 5ooK  V 2 = ? Eg: A gas has a volume of 3.0 L at 127°C. What is its volume at 227 °C?

9 2) Plug in the variables: (500K)(3.0L) = V 2 (400K) V 2 = 3.8L 3.0L V 2 400K 500K = = 3) Cross multiply and chug


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