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5.8 Applications of Quadratic Equations. Steps (reviews) Read and underline important words and numbers Assign variables Create equation and solve equation.

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Presentation on theme: "5.8 Applications of Quadratic Equations. Steps (reviews) Read and underline important words and numbers Assign variables Create equation and solve equation."— Presentation transcript:

1 5.8 Applications of Quadratic Equations

2 Steps (reviews) Read and underline important words and numbers Assign variables Create equation and solve equation Check State answer

3 Problem with Geometric Figures 1) The length of a hall is five times the width. The area of the floor is 45m 2. Find the length and width of the hall.

4 Equation: w (5w) = 45 5w 2 = 45 w 2 = 9 w 2 – 9 = 0 (w-3)(w+3) = 0 w = 3 or w = -3 w 5w THEREFORE: The width is 3m and the length is 5(3) = 15m Impossible to have negative width so discard this answer

5 Problem with consecutive numbers 2) The product of the smallest and largest of three consecutive odd integers is 16 more than the middle integer. Find the numbers.

6 Let x, x+2, x+4 are three consecutive odd integers Equation: x (x+4) = (x+2) + 16 x 2 + 4x = x + 2 + 16 x 2 + 4x = x + 18 x 2 + 4x – x – 18 = 0 x 2 + 3x – 18 = 0 (x + 6) (x -3) = 0 x = -6 or x = 3 Therefore, the numbers are 3, 5, 7 -6 is an even number so discard this answer

7 4) If an object is propelled upward from ground level with an initial velocity of 64 ft per sec, its height h in feel t seconds later is h = -16 t 2 + 64t a)After how many seconds is the height 48ft b)After how many seconds does the object hit the ground?

8 a)48 = -16t 2 + 64t -3 = t 2 – 4t (divide both sides by -16) t 2 – 4t + 3 = 0 (t- 3) (t-1) = 0 t = 3 or t = 1 Therefore, the height is 48 ft after 1 second or after 3 seconds b) 0 = -16t 2 + 64t 0 = t 2 – 4t (divide both sides by -16) 0 = t (t – 4) t = 0 or t = 4 Therefore, the object hits the ground after 4 seconds.

9 Pythagorean Formula a 2 + b 2 = c 2 Hypotenuse c Leg a Leg b


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