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QUESTION # 4 Compute the number of pieces required for the 2" X 10" X 16' stringers in forming the footing for the stem wall. Apply a waste factor of.

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Presentation on theme: "QUESTION # 4 Compute the number of pieces required for the 2" X 10" X 16' stringers in forming the footing for the stem wall. Apply a waste factor of."— Presentation transcript:

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2 QUESTION # 4 Compute the number of pieces required for the 2" X 10" X 16' stringers in forming the footing for the stem wall. Apply a waste factor of 7 percent.(Note: use the SOL and do not include the footing under the garage and side doors) STRINGERS = SOL X SIDES X WASTE LENGTH SOL = P 0 – 4 t SOL = 84’ – 4 (1.67’) SOL = 84’ – 6.68’ = 77.32’ STRINGERS = 77.32’ X 2 X 1.07 = 10.34 16’ STRINGERS = #11 – 2” X 10” X 16’ 2

3 QUESTION # 5 Compute the number of stakes for the same footing as in question #4 which are 2" X 2' X 18" spaced 4' o.c. Use a waste factor of 12 percent. STAKES = SOL X SIDES X WASTE SPACE STAKES = 77.32’ X 2 X 1.12 = 43.29 4 STAKES = #44 – 2” X 2” X 18” 3

4 QUESTION #6 Compute the number of pieces of 1" X 3" X 8' spreader ties in the forming of the footing in question #4. Apply a waste factor of 7 percent. SPREADER TIES = SOL / 8’ X 1.07 4 LENGTH SPREADER TIES = 77.32’ / 8 X 1.07 4 1.67 SPREADER TIES = 19.33 X 1.07 = 4.32 4.79 SPREADER TIES = #5 – 1” X 3” X 8’ 4

5 QUESTION #7 : Compute the number of anchor bolts using a waste factor of 5 percent. Note: add two extra bolts for each corner.(use the SOL) ANCHOR BOLTS = SOL + EXTRA FOR CORNERS X WASTE SPACING ANCHOR BOLTS = 77.32’ + (2 x 4) X 1.05 4 = 19.332 + 8 X 1.05 = 28.69 = 29 ANCHOR BOLTS NOTE: SPACING ON PLANS IS 24” O.C. 5

6 #4 REBAR IN FOOTING = (SOL X NUMBER X WEIGHT) WASTE = (77.32 X 3 X.668) 1.08 = 167.34 LBS = 168 LBS 6

7 CONCRETE IN FOOTING = SOL X DEPTH X WIDTH X WASTE CU. FT. IN YD CONCRETE IN FOOTING = 77.32’ X.83 X 1.67 X 1.08 = 4.28 CU.YD. 27 CONCRETE I FOOTING = 5 CU. YDS. 7

8 QUESTION #10 Compute the cubic yards of concrete for the stem wall using a waste factor of 8 percent. CONDRETE IN STEM WALL = SOL X WIDTH X HEIGHT X WASTE CU. FT. IN CU.YD CONCRETE IN STEM WALL = 77.32’ X.67 X 2 X 1.08 = 4.14 CU.YDS 27 CONCRETE IN STEM WALL = 5 CU.YDS. 8


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