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Green Packet & Yellow Rubric out! Ask your partner, “what did you do this weekend?”

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Presentation on theme: "Green Packet & Yellow Rubric out! Ask your partner, “what did you do this weekend?”"— Presentation transcript:

1 Green Packet & Yellow Rubric out! Ask your partner, “what did you do this weekend?”

2 Extra Credit Opportunity Make a chemistry valentine! Due anytime before break!

3 Warm up Complete F-G equations on the front of the green packet, read the procedure for F-G. Part F: Cu 3 (PO 4 ) 2(s) + 3H 2 SO 4(aq)  3CuSO 4(aq) + 2H 3 PO 4(aq) Part G: CuSO 4(aq) + Zn (s)  ZnSO 4(aq) + Cu (s)

4 Learning Targets I can write and balance equations for the copper series reactions. I can calculate the amount of a product I should get using stoichiometry. I can carry out a lab procedure with accuracy and record measurements using correct sig figs. I can determine a limiting reactant and percent yield.

5 Cupric nitrate Solid copper The Copper Lab You will do a series of 7 reactions to convert: Cupric sulfate Cupric phosphate Cupric chloride Cupric oxide Cupric hydroxide At the end we will calculate % error (how much Cu you lost!)

6 Schedule-Blue Monday, 2/1: Complete Parts A-C of the procedure (including taking pictures), write balanced equations, complete green sheet Wednesday, 2/3: Complete Parts D-E (procedure, equations, green packet); Start PowerPoint Friday, 2/5: Complete Parts F-G (procedure, equations, green packet) Tuesday, 2/9: Final weigh-in. Packet/PPT work time. Stoichiometry “Quest” Thursday, 2/11: All Copper Series Lab handouts and PowerPoint due,

7 Schedule-Gold Tuesday, 2/2: Complete Parts A-C of the procedure (including taking pictures), write balanced equations, complete green sheet Thursday, 2/4: Complete Parts D-E (procedure, equations, green packet); Start PowerPoint Monday, 2/8: Complete Parts F-G (procedure, equations, green packet) Wednesday, 2/10: Final weigh-in. Packet/PPT work time. Stoichiometry “Quest” Friday, 2/12: All Copper Series Lab handouts and PowerPoint due,

8 Today’s Tasks Remember we always want Copper to be the limiting reagent! Complete Parts F and G Weigh your clean dry filter paper first!!! Record this labeled measurement on the bottom of the procedure! Find your dried sample by the fume hood Wear goggles and be careful with the H 2 SO 4 ! Work on your group PowerPoint on gotahoma/google docs I will give you your results next time after you do your final weigh-in!

9 PowerPoint Work Time Read the yellow rubric (especially the 100% column) and use it as a checklist Make a Google presentation using your Gotahoma account Here’s what success looks like: (next slide)

10 Cu (s) + 4HNO 3 (aq)  Cu(NO 3 ) 2 (aq) + 2NO 2 (g) + 2H 2 O (l) Nitrogen Dioxide Connection: Smog above a city Watch The Video Next Reaction Riley gets a better view: making sure her measurements for deionized water are accurate. The solid copper is becoming blue aqueous cupric nitrate and a brown gas (NO 2 ) is being released. Reaction A Reaction: Oxidation-Reduction Reaction Driving Forces: Transfer of electrons, formation of gas, formation of water. Copper Shavings Cu(NO 3 ) 2(aq)

11 Stoichiometry Quiz Next Class Homework:  Stoichiometry Worksheet (review for our quiz next class)  Post-lab for parts F-G  Work on PowerPoint

12 Lim. Reactants and Percent Yield Ex: Sodium sulfate and water are created when 50 g of NaOH and 75 g of H 2 SO 4 are mixed. Calculate the percent yield if only 25 g of sodium sulfate are made. Steps: 1.Write and balance equation 2.Calculate how much Na 2 SO 4 can be made with 50 g NaOH 3.Calculate how much Na 2 SO 4 can be made with 75 g of H 2 SO 4 The lower # from 2 and 3 is how much Na 2 SO 4 you can make 1.Percent yield = actual yield (25g)/theoretical yield (answer from #4) x 100 How much did I actually get/How much should I have gotten?

13 Answers 1.H 2 SO 4 (aq) + 2NaOH (aq)  Na 2 SO 4 (aq) + 2H 2 O (aq) 2.(50g/39.07/2*140.15)=89.6787  90. g of Na 2 SO 4 3.(75/98.09*140.15)=107.159  110 g of Na 2 SO 4 NaOH is the limiting reagent so I can only make 90. grams of Na 2 SO 4 4. 25 g / 90 g = 27.77777…  28 % yield


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