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2.5. Impedance and Admitance. Solution: İn phasor form Example 2.9.

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Presentation on theme: "2.5. Impedance and Admitance. Solution: İn phasor form Example 2.9."— Presentation transcript:

1 2.5. Impedance and Admitance

2 Solution: İn phasor form Example 2.9.

3 İn phasor the circuit comes….

4 Example 2.9. The voltage across the capacitor is…

5 2.6. The Kirchhoff Law in Frequency Domain  In the sinusoidal steady-state, each voltage may be written in cosine form.  This can be written as

6 2.6. The Kirchhoff Law in Frequency Domain  or  

7 2.6. The Kirchhoff Law in Frequency Domain

8 2.6. İmpedance Combinations  Applying KVL around the loop gives,

9 2.6. İmpedance Combinations  The eqivalent impedance at the input terminals is;

10 2.6. İmpedance Combinations  İf N=2;  The current trough the impedance Voltage division relationship

11 2.6. İmpedance Combinations  Applying KCL at the top node;  The eqivalent impedance is;  The eqivalent admitans is;

12 2.6. İmpedance Combinations  İf N=2;  Eqivalent impedance is;  Also;  The current in the impedances; current division relationship

13 2.6. İmpedance Combinations  Delta-to-wye or wye-to-delta transformations can be applied…

14 2.6. İmpedance Combinations

15 Example 2.10.

16

17 Example 2.11. Solution:  First we must transform time-domain circuit to the phasor domain.

18 Example 2.11.

19

20 Example 2.12. Solution:  The delta network connected to nodes a,b and c can be converted to the Y network.

21 Example 2.12.

22


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