1. Chapter 2 Review

2. Find the limit by substituting algebraically: 1.lim x→ 4 2. lim x→ 0 (x+5)(x-4) x-4 (x+5) 4+5 = 9 4-0 1+2 4 3

3. Find the discontinuous points 3.4. (x+6)(x-3) x-3 (x+6) none X = -9

4. Find the limit: 5. lim x→ 0 6. lim x→ 0 4xsin3x x sin5x x + sin3x 3x 4x 1 3131 + sin5x 5x 5151 0+5 = 5 sin6x cos6x ● 1 7x sin6x 6x 1__ cos6x 6x 7x 6767

5. Find the limit: 7. lim x→∞ 8. lim x→ ∞ 6x +sin x x x 3x _ 8 x x 6+0 3-0 2 lim Θ→ 0 5cosΘ 5·1 = 5

6. 9. Find horizontal asymptote: 10. Find the vertical asymptote: Horizontal: lim x→ ∞ x 2 _ 25 x 2 x 2 2x 2 _ 9x _ 5 x 2 x 2 x 2 1 - 0 2-0-0 1212 Vertical: (x+5)(x-5) (2x+1)(x-5) y = x = -1 2