1. Equilibrium Basics Acids & Bases BuffersSolubility 100 200 300

2. Equilibrium 100 Write a balanced chemical equation for the endothermic equilibrium reaction of nitrogen gas with HCl (g), producing ammonia (NH 3 ) and chlorine gas. Which direction will each of the following stresses shift the equilibrium? Tripling the volume of the system Doubling the amount of nitrogen Adding heat

3. Equilibrium 200 3 H 2 + N 2  2 NH 3 (g) K c = 0.059 at 25 °C Determine the K c values for:

4. Equilibrium 300 Calculate K c for the following reaction at 25 °C: CH 3 OH (g)  CO (g) + 2 H 2 (g) P CH3OH = 6.10 x 10 -4 atm P CO = 0.387 atm P H2 = 1.34 atm Hints: you will need to calculate K p first! R = 0.0821 L atm / (K mol)

5. Acids & Bases 100 Will each of the following salts form acidic, basic, or neutral solutions in water? KF HC 5 H 5 NCl NH 4 I NaBr

6. Acids & Bases 200 Calculate each of the following for an aqueous solution with a pH of 6.88: pOH [H 3 O+] [OH-] Is this solution acidic, basic or neutral?

7. Acids & Bases 300 Calculate the pH of a 0.350 M solution of methylamine (K b = 4.38 x 10 -4 ).

8. Acids & Bases Other Acid/Base definitions Percent dissociation questions – Examples: PSS #3, q. 3? HW problem 18.69 Henderson-Hasselbach

9. Buffers 100 What is the pH of a buffer solution containing 0.250 M HCOOH and 0.100 M NaCOOH? K a of HCOOH is 1.8 x 10 -4 Hint: The H 3 O + coming from dissociation of HCOOH is negligible

10. Buffers 200 Given solid sodium nitrite (NaNO 2 ) and 5.50 M nitrous acid (HNO 2, K a = 4.50 x 10 -4 ), how would you make 250.0 mL of a pH 3.00 buffer, with a final acid concentration of 0.500 M?

11. Buffers 300 A 600 mL sample of a buffer solution contains 1.38 M HCN and 1.07 M CN-. (K a = 6.2 x 10 -10 ) Determine the pH of this solution… initially after 50.0 mL of 3.00 M HCl has been added

12. Solubility 100 Write the solubility product constant for and determine the solubility of silver phosphate (K sp = 1.8 x 10 -18 )

13. Solubility 200 Which has a greater solubility: Silver chloride (K sp = 1.5 x 10 -10 ) Barium fluoride (K sp = 3.2 x 10 -11 )

14. Solubility 300 100. mL of 0.50 M tin (II) nitrate and 100. mL of 0.20 M Cadmium nitrate are mixed. What concentration of OH- must be added to separate the cations? K sp of Cd(OH) 2 = 8.1 x 10 -13 K sp of Sn(OH) 2 = 5.4 x 10 -27