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Linear Differential Equations AP CALCULUS BC
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First-Order Differential Equations A first-order linear differential equation can be put into the form where P and Q are continuous functions on a given interval. These types of equations occur frequently in various sciences. These equations are not separable – we cannot rewrite it as f(x)g(y). So what do we do?
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Integrating Factor We can solve any first-order linear differential equation by multiplying both sides by the integrating factor, I(x). Our goal is to get the left side to equal [I(x) y] ʹ, so we can integrate it. But how do we find I(x)? We want I(x)(y ʹ + P(x)y) = (I(x)y) ʹ Expand I(x)y ʹ + I(x)P(x)y = I ʹ (x)y + I(x)y ʹ (used product rule on RHS) So I(x)P(x) = I ʹ (x)
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Integrating Factor (cont.) This is a separable differential equation if we rewrite it as Therefore, Integrate to get And finally!
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Example 1 Find the general solution to the differential equation 1)First find I(x) 2)Multiply both sides by the integrating factor 3)Replace the left side with [I(x) y] ʹ, which in this case is (xy) ʹ New equation is (xy) ʹ = 2x 4)Integrate both sides 5)Solve for y
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Example 2 Solve the differential equation
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Example 3 Find the solution of the initial value problem x 2 y ʹ + xy = 1 (x > 0), where y(1) = 2. [Hint: If there is a number or a variable in front of the y ʹ, you need to divide first.]
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Example 4 Find the solution of y ʹ + 2xy = 1.
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