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Published byHarold Griffin Modified over 9 years ago
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Objective The student will be able to: solve two-step inequalities. SOL: A.5abc Designed by Skip Tyler, Varina High School
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1) Solve 5m - 8 > 12 + 8 + 8 5m > 20 5 5 m > 4 5(4) – 8 = 12 o 453
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2) Solve 12 - 3a > 18 - 12 - 12 -3a > 6 -3 -3 a < -2 12 - 3(-2) = 18 o -2-3
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Which graph shows the solution to 2x - 10 ≥ 4? 1.. 2. 3. 4. Answer Now
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4) Solve 2r - 18 ≤ 5r + 3 -2r -18 ≤ 3r + 3 - 3 - 3 -21 ≤ 3r 3 3 -7 ≤ r r ≥ -7 1.Subtract the variable term 2.Solve 3.Graph ● -7-6-8
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6) Solve -2x + 6 ≥ 3x - 4 1.x ≥ -2 2.x ≤ -2 3.x ≥ 2 4.x ≤ 2 Answer Now
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5) Solve 26p - 20 > 14p + 64 -14p 12p – 20 > 64 + 20 + 20 12p > 84 12 12 p > 7 o 786 1.Subtract the variable term 2.Solve 3.Graph
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What are the values of x if 3(x + 4) - 5(x - 1) < 5? Answer Now 1.x < -6 2.x > -6 3.x < 6 4.x > 6
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