1. Disproved By: Sierra Baney 2012

2. Curving A Bullet Wanted (6/11) Movie CLIP - Wesley's First Curved Bullet (2008) HD - YouTube Wanted (6/11) Movie CLIP - Wesley's First Curved Bullet (2008) HD - YouTube

3. Mr. X

4. Video Breakdown Mr. X runs out a hallway window from a skyscraper and shoots at a man on a building across the street. While in the air he shoots 3 shots. He lands about 12 feet below his original height.

5. Involved Physics Linear Motion: Velocity Relative Motion Conservation of Momentum: – Inelastic Collisions Projectile Motion

6. Wanted (1/11) Movie CLIP - Cross Kills Mr. X (2008) HD - YouTube Wanted (1/11) Movie CLIP - Cross Kills Mr. X (2008) HD - YouTube

7. Citadel Building 131 Dearborn St, Chicago Total Height: – 580 ft = 177 m – 37 stories

8. Carbon and Carbide Building 230 Michigan Avenue, Chicago Total Height: – 503 ft = 153m – 37 stories

9. Estimations Secondary Roof – 400 ft = 121.92m Height Mr. X drops – 12 ft = 3.66 m

10. Calculating Velocity OSHA Minimum Requirement (Office) – 61ft = 18.59m 3 doorways 18.59 X 3 = 55.78m OSHA Minimum Requirement (Elevator) 1.74m 55.78 + 1.74 Total distance 131.89m in 28 sec

11. Calculating Velocity (Cont) Velocity = Distance / Time 57.53 / 6.3 = 9.13 m/s – 20.42 mph Fastest recorded speed was 10.35 m/s – top physical condition

12. David O’Hara Mr. X Height: 5’11’’ = 1.80m Estimated Weight: 165lbs = 74.83kg Stride:.748m per stride

13. Momentum: Beretta 92S 2 shots Muzzle velocity: 1250 ft/s = 381m/s Mass: 970g =.97kg Momentum = Mass X Velocity M=.97 X 381 = 369.57

14. Momentum: Flintlock Pistol 1 shot Muzzle Velocity: 1000ft/s = 304.8m/s Mass: 2.98lbs = 1.35kg Momentum = Mass X Velocity M= 1.35 X 304.8 = 411.99

15. Conservation of Momentum: Inelastic Collisions (m1 + m2)V = (m1v1f) + (m2V2f) (mass man/gun/bullet)man’s velocity mass/velocity of bullet mass/velocity man/gun

16. Conservation of Momentum: Inelastic Collisions Finding the final velocity to use for projectile motion Information for equation: – Mass of man/gun/bullet: 74.84kg – Mass of Bullets:.2kg each (3 bullets) – Mass of first gun (2 shots):.97kg – Mass of second gun (1 shot): 1.35kg – Velocity of Man running: 9.13m/s – Muzzle Velocity first gun: 381m/s – Muzzle Velocity of second gun: 304.8m/s

17. Conservation of Momentum: Inelastic Collisions: Equation (m1 + m2)V = (m1v1f) + (m2V2f) (mass man/gun/bullet)man’s velocity mass/velocity of bullet mass/velocity man/gun First Shot (74.84 +.2 +.2 +.2 + 2.32)9.13 =.2(381) + (74.84 + 2.32)vf 709.95 = 76.2 + 77.16vf Vf = 8.21m/s Second Shot (74.84 +.2 +.2 + 2.32)8.21 =.2(381) = (74.84 + 2.32)vf 636.77 = 76.2 + 77.16vf 560.57 = 77.16vf Vf = 7.27 m/s Third Shot (74.84 +.2 + 2.32)7.27 =.2(304.8) + (74.84 + 2.32)vf 562.41 = 60.96 + 77.16vf 501.45 = 77.16vf Vf = 6.50m/s

18. Projectiles: Time it should take to jump the distance d = v x t because horizontal velocity is constant City of Chicago street measurements: – D = 100 ft = 30.48m 30.48m = 9.13m/s x time t = 3.34s

19. Projectiles: How much height he would lose in that time H = ½ g t 2 H = ½ 9.81 m/s 2 (3.34 sec) 2 H = 55.78m 15 times that shown in the video