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Slide 10.2- 1 Copyright © 2007 Pearson Education, Inc. Publishing as Pearson Addison-Wesley.

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Presentation on theme: "Slide 10.2- 1 Copyright © 2007 Pearson Education, Inc. Publishing as Pearson Addison-Wesley."— Presentation transcript:

1 Slide 10.2- 1 Copyright © 2007 Pearson Education, Inc. Publishing as Pearson Addison-Wesley

2 OBJECTIVES Copyright © 2008 Pearson Education, Inc. Publishing as Pearson Addison-Wesley The Parabola Learn the definition of a parabola. Learn to find an equation of a parabola. Learn translations of parabolas. Learn the reflecting property of parabolas. SECTION 10.2 1 2 3 4

3 Slide 10.2- 3 Copyright © 2007 Pearson Education, Inc. Publishing as Pearson Addison-Wesley PARABOLA Let l be a line and F a point in the plane not on the line l. The the set of all points P in the plane that are the same distance from F as they are from the line l is called a parabola. Thus, a parabola is the set of all points P for which d(F, P) = d(P, l), where d(P, l) denotes the distance between P and l.

4 Slide 10.2- 4 Copyright © 2007 Pearson Education, Inc. Publishing as Pearson Addison-Wesley PARABOLA Line l is the directrix. the directrix is the axis or axis of symmetry. The line through the focus, perpendicular to Point F is the focus. The point where the axis intersects the parabola is the vertex.

5 Slide 10.2- 5 Copyright © 2007 Pearson Education, Inc. Publishing as Pearson Addison-Wesley EQUATION OF A PARABOLA The equation y 2 = 4ax is called the standard equation of a parabola with vertex (0, 0) and focus (a, 0). Similarly, if the focus of a parabola is placed on the negative x-axis, we obtain the equation y 2 = – 4ax as the standard equation of a parabola with vertex (0, 0) and focus (– a, 0).

6 Slide 10.2- 6 Copyright © 2007 Pearson Education, Inc. Publishing as Pearson Addison-Wesley EQUATION OF A PARABOLA By interchanging the roles of x and y, we find that the equation x 2 = 4ay is the standard equation of a parabola with vertex (0, 0) and focus (0, a). Similarly, if the focus of a parabola is placed on the negative x-axis, we obtain the equation x 2 = – 4ay as the standard equation of a parabola with vertex (0, 0) and focus (0, – a).

7 Slide 10.2- 7 Copyright © 2007 Pearson Education, Inc. Publishing as Pearson Addison-Wesley LATUS RECTUM The line segment that passes through the focus of a parabola, is perpendicular to the axis of the parabola, and has endpoints on the parabola is called the latus rectum of the parabola. Following are figures that show that the length of the latus rectum for the graphs of y 2 = ±4ax and x 2 = ±4ay for a > 0 is 4a.

8 Slide 10.2- 8 Copyright © 2007 Pearson Education, Inc. Publishing as Pearson Addison-Wesley LATUS RECTUM

9 Slide 10.2- 9 Copyright © 2007 Pearson Education, Inc. Publishing as Pearson Addison-Wesley LATUS RECTUM

10 Slide 10.2- 10 Copyright © 2007 Pearson Education, Inc. Publishing as Pearson Addison-Wesley EXAMPLE 2 Finding the Equation of a Parabola Find the standard equation of a parabola with vertex (0, 0) and satisfying the given description. Solution a.Vertex (0, 0) and focus (–3, 0) are both on the x-axis, so parabola opens left and the equation has the form y 2 = – 4ax with a = 3. a.The focus is (–3, 0). b.The axis of the parabola is the y-axis, and the graph passes through the point (–4, 2). The equation is

11 Slide 10.2- 11 Copyright © 2007 Pearson Education, Inc. Publishing as Pearson Addison-Wesley EXAMPLE 2 Finding the Equation of a Parabola Solution continued b.Vertex is (0, 0), axis is the y-axis, and the point (–4, 2) is above the x-axis, so parabola opens up and the equation has the form x 2 = – 4ay and x = –4 and y = 2 can be substituted in to obtain The equation is

12 Slide 10.2- 12 Copyright © 2007 Pearson Education, Inc. Publishing as Pearson Addison-Wesley Main facts about a parabola with vertex ( h, k ) and a > 0 Standard Equation(y – k) 2 = 4a(x – h) Equation of axisy = k DescriptionOpens right Vertex(h, k) Focus(h + a, k) Directrixx = h – a

13 Slide 10.2- 13 Copyright © 2007 Pearson Education, Inc. Publishing as Pearson Addison-Wesley Main facts about a parabola with vertex ( h, k ) and a > 0

14 Slide 10.2- 14 Copyright © 2007 Pearson Education, Inc. Publishing as Pearson Addison-Wesley Main facts about a parabola with vertex ( h, k ) and a > 0 Standard Equation(y – k) 2 = –4a(x – h) Equation of axisy = k DescriptionOpens left Vertex(h, k) Focus(h – a, k) Directrixx = h + a

15 Slide 10.2- 15 Copyright © 2007 Pearson Education, Inc. Publishing as Pearson Addison-Wesley Main facts about a parabola with vertex ( h, k ) and a > 0

16 Slide 10.2- 16 Copyright © 2007 Pearson Education, Inc. Publishing as Pearson Addison-Wesley Main facts about a parabola with vertex ( h, k ) and a > 0 Standard Equation(x – h) 2 = 4a(y – k) Equation of axisx = h DescriptionOpens up Vertex(h, k) Focus(h, k + a) Directrixy = k – a

17 Slide 10.2- 17 Copyright © 2007 Pearson Education, Inc. Publishing as Pearson Addison-Wesley Main facts about a parabola with vertex ( h, k ) and a > 0

18 Slide 10.2- 18 Copyright © 2007 Pearson Education, Inc. Publishing as Pearson Addison-Wesley Main facts about a parabola with vertex ( h, k ) and a > 0 Standard Equation(x – h) 2 = – 4a(y – k) Equation of axisx = h DescriptionOpens down Vertex(h, k) Focus(h, k – a) Directrixy = k + a

19 Slide 10.2- 19 Copyright © 2007 Pearson Education, Inc. Publishing as Pearson Addison-Wesley Main facts about a parabola with vertex ( h, k ) and a > 0

20 Slide 10.2- 20 Copyright © 2007 Pearson Education, Inc. Publishing as Pearson Addison-Wesley EXAMPLE 3 Graphing a Parabola Find the vertex, focus, and the directrix of the parabola 2y 2 – 8y – x + 7 = 0. Sketch the graph of the parabola. Solution Complete the square on y.

21 Slide 10.2- 21 Copyright © 2007 Pearson Education, Inc. Publishing as Pearson Addison-Wesley EXAMPLE 3 Graphing a Parabola Solution continued We have h = –1, k = 2, and Vertex: (h, k) = (–1, 2) Focus: (h + a, k) = Directrix: x = h – a = Comparewith the standard form

22 Slide 10.2- 22 Copyright © 2007 Pearson Education, Inc. Publishing as Pearson Addison-Wesley EXAMPLE 3 Graphing a Parabola Solution continued

23 Slide 10.2- 23 Copyright © 2007 Pearson Education, Inc. Publishing as Pearson Addison-Wesley REFELCTING PROPERTY OF PARABOLAS A property of parabolas that is useful in applications is their reflecting property. The reflecting property says that if a reflecting surface has parabolic cross sections with a common focus, then all light rays entering the surface parallel to the axis will be reflected through the focus. This property is used in reflecting telescopes and satellite antennas, since the light rays or radio waves bouncing off a parabolic surface are reflected to the focus, where they are collected and amplified. (See next slide.)

24 Slide 10.2- 24 Copyright © 2007 Pearson Education, Inc. Publishing as Pearson Addison-Wesley REFELCTING PROPERTY OF PARABOLAS

25 Slide 10.2- 25 Copyright © 2007 Pearson Education, Inc. Publishing as Pearson Addison-Wesley REFELCTING PROPERTY OF PARABOLAS Conversely, if a light source is located at the focus of a parabolic reflector, the reflected rays will form a beam parallel to the axis. This principle is used in flashlights, searchlights, and other such devices. (See next slide.)

26 Slide 10.2- 26 Copyright © 2007 Pearson Education, Inc. Publishing as Pearson Addison-Wesley REFELCTING PROPERTY OF PARABOLAS


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