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Copyright © 2012, 2009, 2005, 2002 Pearson Education, Inc. Chapter 5 Percent.

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Presentation on theme: "Copyright © 2012, 2009, 2005, 2002 Pearson Education, Inc. Chapter 5 Percent."— Presentation transcript:

1 Copyright © 2012, 2009, 2005, 2002 Pearson Education, Inc. Chapter 5 Percent

2 Copyright © 2012, 2009, 2005, 2002 Pearson Education, Inc. Solving Applied Percent Problems 5.4

3 Copyright © 2012, 2009, 2005, 2002 Pearson Education, Inc. Solving General Percent Problems Example: Mary received a raise of 8% of her monthly salary. The amount of her raise was $48.16 per month. What was her monthly salary before her raise? This problem can be solved using the equation method. 48.16 is 8% of n The unknown quantity is the base.

4 Copyright © 2012, 2009, 2005, 2002 Pearson Education, Inc. Solving General Percent Problems Example: Mary received a raise of 8% of her monthly salary. The amount of her raise was $48.16 per month. What was her monthly salary before her raise? Equation method Mary’s monthly salary before the raise was $602.

5 Copyright © 2012, 2009, 2005, 2002 Pearson Education, Inc. Solving Markup Problems Percents can be added if the base is the same. These types of problems are called markup problems. The markup is 15%. Original Cost + 15% of Original Cost

6 Copyright © 2012, 2009, 2005, 2002 Pearson Education, Inc. Solving Markup Problems Example: Mark is taking Peggy out to dinner. He has $66 to spend. If he wants to tip the server 20%, how much can he afford to spend on the meal? Let n = the cost of the meal. Cost of meal n + tip of 20% of the cost = $66 100% of n+20% of n=$66 120% of n=$66 Mark and Peggy can spend up to $55 on the meal itself.

7 Copyright © 2012, 2009, 2005, 2002 Pearson Education, Inc. Solving Discount Problems The amount of a discount is the product of the discount rate and the list price. The discount rate is 25%. SALE! 25% off Discount = discount rate  list price

8 Copyright © 2012, 2009, 2005, 2002 Pearson Education, Inc. Solving Discount Problems Example: Julie bought a leather sofa that was on sale for 35% off the original price of $1200. What was the discount? How much did Julie pay for the sofa? Julie paid $780 for the sofa. Discount = discount rate  list price Discount = 35%  1200 = 420 The discount was $420. Amount paid = list price – discount Amount paid = 1200 – 420 = 780


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