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Copyright © Cengage Learning. All rights reserved. 11 Analytic Geometry in Three Dimensions
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Copyright © Cengage Learning. All rights reserved. The Cross Product of Two Vectors 11.3
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3 Find cross products of vectors in space. Use geometric properties of cross products of vectors in space. Use triple scalar products to find volumes of parallelepipeds. Objectives
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4 The Cross Product
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5 Many applications in physics, engineering, and geometry involve finding a vector in space that is orthogonal to two given vectors. In this section, you will study a product that will yield such a vector. It is called the cross product, and it is conveniently defined and calculated using the standard unit vector form.
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6 The Cross Product It is important to note that this definition applies only to three-dimensional vectors. The cross product is not defined for two-dimensional vectors. A convenient way to calculate u v is to use the following determinant form with cofactor expansion. (This 3 3 determinant form is used simply to help remember the formula for the cross product—it is technically not a determinant because the entries of the corresponding matrix are not all real numbers.)
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7 The Cross Product
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8 Note the minus sign in front of the j-component. Note that each of the three 2 2 determinants can be evaluated by using the following pattern.
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9 Example 1 – Finding Cross Products Given u = i + 2j + k and v = 3i + j + 2k, find each cross product. a. u v b. v u c. v v Solution: a.
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10 Example 1 – Solution b. cont’d
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11 Example 1 – Solution Note that this result is the negative of that in part (a). c. cont’d
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12 The Cross Product The results obtained in Example 1 suggest some interesting algebraic properties of the cross product. For instance, u v = –(v u) and v v = 0.
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13 The Cross Product These properties, and several others, are summarized in the following list.
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14 Geometric Properties of the Cross Product
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15 Geometric Properties of the Cross Product The first property, u v = –(v u) indicates that the cross product is not commutative. In particular, this property indicates that the vectors u v and v u have equal lengths but opposite directions.
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16 Geometric Properties of the Cross Product The following list gives some other geometric properties of the cross product of two vectors.
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17 Geometric Properties of the Cross Product Both u v and v u are perpendicular to the plane determined by u and v. One way to remember the orientations of the vectors u, v, and u v is to compare them with the unit vectors i, j, and k = i j, respectively, as shown in Figure 11.13. The three vectors u, v, and u v form a right-handed system. Figure 11.13
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18 Example 2 – Using the Cross Product Find a unit vector that is orthogonal to both u = 3i – 4j + k and v = –3i + 6j. Solution: The cross product u v, as shown in Figure 11.14, is orthogonal to both u and v. Figure 11.14
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19 Example 2 – Solution Because a unit vector orthogonal to both u and v is. cont’d
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20 Geometric Properties of the Cross Product In Example 2, note that you could have used the cross product v u to form a unit vector that is orthogonal to both u and v. With that choice, you would have obtained the negative of the unit vector found in the example. The fourth geometric property of the cross product states that || u v || is the area of the parallelogram that has u and v as adjacent sides. It follows that the area of a triangle having vectors u and v as adjacent sides is || u v ||.
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21 The Triple Scalar Product
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22 The Triple Scalar Product
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23 The Triple Scalar Product When the vectors u, v, and w do not lie in the same plane, the triple scalar product u (v w) determines the volume of a parallelepiped (a polyhedron, where all faces are parallelograms) with u, v, and w as adjacent edges, as shown in Figure 11.17. Area of base = ||v w|| Volume of parallelepiped =| u (v w)| Figure 11.17
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24 The Triple Scalar Product
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25 Example 5 – Volume by the Triple Scalar Product Find the volume of the parallelepiped having u, v, and w as adjacent edges, as shown in Figure 11.18. Figure 11.18
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26 Example 5 – Solution The value of the triple scalar product is
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27 Example 5 – Solution So, the volume of the parallelepiped is. cont’d
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