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Published byAshlie Hodges Modified over 8 years ago
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Analysis of Diode Circuits using the Ideal Diode Model
Determine the state (on or off) of D1 and D2. Recall -- Forward Bias: VA > VK, short circuit Reverse Bias: VK > VA, open circuit
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Start by assuming diode states
Assume D1 is OFF and D2 is ON. The current through D2 flows from anode to cathode The anode voltage D1 is 10V, and the cathode voltage is 3V. This means D1 is actually forward biased and should be ON.
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Let’s try again Assume D1 is ON and D2 is OFF.
The current through D1 flows from anode to cathode The anode voltage D2 is 3V, and the cathode voltage is 6V. This means D2 is indeed reverse biased and is OFF. So D1 is forward biased (ON) and D2 is reverse biased (OFF).
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Let’s try some more!
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Let’s try some more!
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Let’s try some more! OFF ON VA VK
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Full-Wave (Bridge) Rectifier
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Full-Wave (Bridge) Rectifier
Positive Half-Cycle:
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Full-Wave (Bridge) Rectifier
Negative Half-Cycle:
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Full-Wave (Bridge) Rectifier
Iload
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Full-Wave (Bridge) Rectifier
What happens when a diode fails? (Diodes always fail as OPEN circuits)
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