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Chapter 20: Electrochemistry Chemistry 1062: Principles of Chemistry II Andy Aspaas, Instructor.

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1 Chapter 20: Electrochemistry Chemistry 1062: Principles of Chemistry II Andy Aspaas, Instructor

2 Oxidation-Reduction reactions Oxidation-reduction (redox) reaction: transfer of electrons from one species to another H 3 O + becomes simply H + when dealing with redox reactions to simplify balancing –(still the same species, just different notation) Skeleton oxidation-reduction equation: involves only the species being oxidized and reduced. –Write oxidation numbers above each species. –No spectator ions, no balancing Half reaction: shows only one oxidation OR one reduction –Most redox reactions are split into an oxidation half- reaction and a reduction half-reaction –LEO, GER

3 Balancing redox equations in acidic solutions For each half reaction… –Balance everything except H or O –Balance O by adding H 2 O to one side –Balance H by adding H + to one side –Balance charge by adding e - to one side Multiply each half reaction by a factor so that the electrons cancel when the two half reactions are added together (e - cannot appear in the final equation) Add the reactions, cancel anything that appears on the left and right, and simplify the coefficients to the smallest integers

4 Practice balancing acidic redox reactions Balance I 2 (s) + NO 3 - (aq)  IO 3 - (aq) + NO 2 (g) in acidic solution Half reactions Cancel electrons Add half-reactions Simplify

5 Voltaic cells A voltaic cell consists of two half-cells –Each half-cell contains a metal rod dipped in a solution containing that metal ion –Anode: a species is being oxidized –Cathode: a species is being reduced Cell reaction: redox reaction for entire voltaic cell Zn(s) + Cu 2+ (aq)  Zn 2+ (aq) + Cu(s) Zn(s)  Zn 2+ (aq): oxidation half-reaction, anode Cu 2+ (aq)  Cu(s): reduction half-reaction, cathode

6 Cell notation Zn(s) + Cu 2+ (aq)  Zn 2+ (aq) + Cu(s) Cell notation: Zn(s) | Zn 2+ (aq) || Cu 2+ (aq) | Cu(s) –Anode || Cathode Write half reactions and cell reactions for the following cell: Tl(s) | Tl + (s) || Sn 2+ (aq) | Sn(s)

7 emf, Standard Cell emf, Standard electrode potential Electromotive force, emf, E cell = electrical pressure across the conductors of an electrochemical cell –Unit: Volt, V –Measure of the driving force of a cell reaction Standard cell emf, E o cell = solutes are 1 M, gases are 1 atm, temperature is 25 o C Standard electrode potenital –By convention, the standard hydrogen electrode has an emf of 0 V –All reactions shown as reductions E cell = E cathode – E anode E cell is positive for spontaneous reactions as written

8 Practice calculating E cell Using standard potentials, calculate E cell for Zn(s) | Zn 2+ (aq) || Cu 2+ (aq) | Cu(s) Standard cell potentials are an intensive property –Do not depend on quantity! –If you have to multiply a half-reaction to cancel electrons, do not multiply the E o for that half- reaction

9 Free energy and K from E cell ΔG o = -nFE cell n = moles of electrons transferred F = Faraday’s constant, 96,500 C/mol e - This gives an answer in J, since 1 J = 1 C·V Convert to kJ since that’s what ΔG o is usually expressed in E cell = (0.0592 / n) log K (Nernst equation)

10 Practice with ΔG o and K Calculate ΔG o and K for the following cell: Zn(s) | Zn 2+ (aq) || Cu 2+ (aq) | Cu(s) ΔG o = -nFE cell E cell = (0.0592 / n) log K

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