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Published byPatricia Morgan Modified over 9 years ago
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Quadratic Equations: Factoring, Square Root Methods
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Recall, linear equations, ax + b = 0, we could solve easily For second degree polynomials, we have some increased complexity Quadratic = second degree polynomial – ax 2 + bx + c = 0 Quadrus = Latin for square
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Methods to consider A) Factoring (when possible) B) Square Roots (when possible) C) Graphing (tricky, not always precise) D) Quadratic Equation (last resort)
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Factoring To solve the problem ax 2 + bx + c = 0, we can factor into (a + b) (c + d = 0, and set each term = 0 – Zero Product Property Example. Solve: 5x 2 + 10x = 0
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Example. Solve: 9x 2 + 6x = -6x – 6x 2 Only solve when = 0.
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Square Root In some cases, we may have special factors involving squared terms (ax + b) 2 = 0 Remember, to “undue” a squared term, we can use square roots 0, 1, or 2 possible answers
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Example. Solve: (3x – 5) 2 = 25 Solutions?
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Example. Solve: -(2x – 3) 2 + 6 = 0
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Imaginary Case Example. Solve: (10x -1) 2 = - 36
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Assignment Pg. 93 #1-23 odd
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