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Applications - Business - Economics - Life Sciences Lesson 6.6.

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Presentation on theme: "Applications - Business - Economics - Life Sciences Lesson 6.6."— Presentation transcript:

1 Applications - Business - Economics - Life Sciences Lesson 6.6

2 Compound Interest Recall continuous compounding formula A = future value P 0 = initial, one time investment Consider, instead, periodic deposits into the account  Referred to as an annuity

3 Future Value The future value of a periodic investment represented by f(t) Try for $1200 per year for 7 years  Yielding 6% compounded continuously Note (7 – t)

4 Present Value The present value is the amount that must be invested in order to generate a periodic pay out for a specified number of years You wish to receive $1800 per year for 10 years from an investment  The account receives 6.5% interest continually  What must be the initial investment?

5 Cost and Revenue Consider Cost function C(x) Revenue function R(x) Then profit or Earnings E(x) = R(x) – C(x) at any point in time What if we are given the rate of change of these functions  Called the marginal cost, revenue, earnings

6 Cost and Revenue What if we are given the rate of change of these functions  Called the marginal cost, revenue Net earnings can be interpreted as the area between these two curves R'(x) C'(x)

7 Try It Out Given rate of change (marginal) functions for Cost and Revenue Find the total revenue/earnings for the first 10 months

8 Consumer's and Producer's Surplus Let p = D(q) represent a demand function  p = price consumers are willing to pay  q = number of units purchased q0q0 Total willingness to spend - Actual Expenditure = Consumer's Surplus p = D(q)

9 Consumer's and Producer's Surplus Consumer's surplus given by p = D(q) q0q0

10 Consumer's and Producer's Surplus q0q0 Actual consumer expenditure for q 0 units - Total amt producers receive when q 0 units supplied Producer's Surplus = p = S(q)

11 Assignment A Lesson 6.6A Page 414 Exercises 5 – 27 odd

12 Survival and Renewal Consider a situation where f(t) gives us the proportion (fraction) of an initial population remaining after time t  We know an initial population = p 0  And we know a renewal rate r(t) At the end of t months, we know we have

13 Survival and Renewal Example: The fraction of people residing t years after they area is given by Current population is 20,000. New townspeople are arriving at rate of 500 /yr What will the population be 10 years from now?

14 Assignment B Lesson 6.6B Page 415 Exercises 29 – 53 odd


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