Presentation is loading. Please wait.

Presentation is loading. Please wait.

PowerPoint Presentation Materials to accompany

Similar presentations


Presentation on theme: "PowerPoint Presentation Materials to accompany"— Presentation transcript:

1 PowerPoint Presentation Materials to accompany
Genetics: Analysis and Principles Robert J. Brooker CHAPTER 6 GENETIC TRANSFER AND MAPPING IN BACTERIA AND BACTERIOPHAGES Copyright ©The McGraw-Hill Companies, Inc. Permission required for reproduction or display

2 INTRODUCTION Bacteria and viruses account for a quarter to a third of human deaths worldwide. Their impact on health is a major reason for studying them. Like eukaryotes, bacteria often possess allelic differences that affect their cellular traits However, these allelic differences (such as different sensitivity to antibiotics) are between different strains of bacteria because HOW ??? They do this. 6-2 Copyright ©The McGraw-Hill Companies, Inc. Permission required for reproduction or display

3 INTRODUCTION genetic transfer
In this process, a segment of bacterial DNA is transferred from one bacterium to another 6-3 Copyright ©The McGraw-Hill Companies, Inc. Permission required for reproduction or display

4 6.1 GENETIC TRANSFER AND MAPPING IN BACTERIA
Like sexual reproduction in eukaryotes, genetic transfer in bacteria enhances genetic diversity Transfer of genetic material from one bacterium to another can occur in three ways: Conjugation Involves direct physical contact Transduction Involves viruses Transformation Involves uptake from the environment See Table 6.1 6-4 Copyright ©The McGraw-Hill Companies, Inc. Permission required for reproduction or display

5 6-5

6

7 movie

8 Conjugation Genetic transfer in bacteria was discovered in 1946 by Joshua Lederberg and Edward Tatum They were studying strains of Escherichia coli that had different nutritional growth requirements Auxotrophs cannot synthesize a needed nutrient Prototrophs make all their nutrients from basic components One auxotroph strain was designated bio– met– phe+ thr+ It required one vitamin (biotin) and one amino acid (methionine) It could produce the amino acids phenylalanine and threonine The other strain was designated bio+ met+ phe– thr– Had the opposite requirements for growth Their experiment is described in Figure 6.1 6-6 Copyright ©The McGraw-Hill Companies, Inc. Permission required for reproduction or display

9 6-7 Figure 6.1

10 The genotype of the bacterial cells that grew on the plates has to be bio+ met+ phe+ thr+
Lederberg and Tatum reasoned that some genetic material was transferred between the two strains Either the bio– met– phe+ thr+ strain got the ability to synthesize biotin and methionine (bio+ met+) Or the bio+ met+ phe– thr– strain got the ability to synthesize phenylalanine and threonine (phe+ thr+) The results of this experiment cannot distinguish between the two possibilities 6-8 Copyright ©The McGraw-Hill Companies, Inc. Permission required for reproduction or display

11 He used an apparatus known as U-tube
Bernard Davis later showed that the bacterial strains must make physical contact for transfer to occur He used an apparatus known as U-tube It contains at the bottom a filter which has pores that were Large enough to allow the passage of the genetic material But small enough to prevent the passage of bacterial cells Davis placed the two strains in question on opposite sides of the filter Application of pressure or suction promoted the movement of liquid through the filter Refer to Figure 6.2 6-9 Copyright ©The McGraw-Hill Companies, Inc. Permission required for reproduction or display

12 Figure 6.2 Nutrient agar plates lacking biotin, methionine, phenylalanine and threonine No colonies Thus, without physical contact, the two bacterial strains did not transfer genetic material to one another 6-10

13 Many, but not all, species of bacteria can conjugate
The term conjugation now refers to the transfer of DNA from one bacterium to another following direct cell-to cell contact Many, but not all, species of bacteria can conjugate Moreover, only certain strains of a bacterium can act as donor cells Those strains contains a small circular piece of DNA termed the F factor (for Fertility factor) Strains containing the F factor are designated F+ Those lacking it are F– Plasmid is the general term used to describe extra-chromosomal DNA 6-11 Copyright ©The McGraw-Hill Companies, Inc. Permission required for reproduction or display

14 These genes play a role in the transfer of DNA
Plasmids, such as F factors, which are transmitted via conjugation are termed conjugative plasmids These plasmids carry genes required for conjugation These genes play a role in the transfer of DNA They are thus designated tra and trb followed by a capital letter Figure 6.3 6-12

15 Refer to Figure 6.4a for the molecular details of conjugation
The first step in conjugation is the contact between donor and recipient cells This is mediated by sex pili (or F pili) which are made only by F+ strains These pili act as attachment sites for the F– bacteria Refer to Figure 6.4b Once contact is made, the pili shorten Donor and recipient cell are drawn closer together A conjugation bridge is formed between the two cells The successful contact stimulates the donor cells to begin the transfer process Refer to Figure 6.4a for the molecular details of conjugation 6-13 Copyright ©The McGraw-Hill Companies, Inc. Permission required for reproduction or display

16 6-14 Figure 6.4 Together, these form the conjugation bridge
a complex of proteins encoded by the F factor that span both inner and outer membranes Together, these form the conjugation bridge Accessory proteins of the relaxosome are released One protein, relaxase, remains bound to the end of the T-DNA Protein complex encoded by the F factor Transferred DNA Figure 6.4 6-14

17

18 6-15

19 F’ factors can be transferred through conjugation
The result of conjugation is that the recipient cell has acquired an F factor Thus, it is converted from an F– to an F+ cell The F+ cell remains unchanged In some cases, the F factor may carry genes that were once found on the bacterial chromosome These types of F factors are called F’ factors F’ factors can be transferred through conjugation This may introduce new genes into the recipient and thereby alter its genotype 6-16 Copyright ©The McGraw-Hill Companies, Inc. Permission required for reproduction or display

20 Hfr Strains In the 1950s, Luca Cavalli-Sforza discovered a strain of E. coli that was very efficient at transferring chromosomal genes He designated this strain as Hfr (for High frequency of recombination) Hfr Strains Contain an F Factor Integrated into the Bacterial Chromosome An episome is a segment of DNA that can exist as a plasmid and integrate into the chromosome 6-17

21 Hfr Strains Can Transfer a Portion of the Bacterial Chromosome to Recipient Cells

22

23 William Hayes demonstrated that conjugation between an Hfr and an F– strain involves the transfer of a portion of the Hfr bacterial chromosome The origin of transfer of the integrated F factor determines the starting point and direction of the transfer process The cut, or nicked site is the starting point that will enter the F– cell Then, a strand of bacterial DNA begins to enter in a linear manner 6-18 Copyright ©The McGraw-Hill Companies, Inc. Permission required for reproduction or display

24 The F– cell does pick up chromosomal DNA
It generally takes about hours for the entire Hfr chromosome to be passed into the F– cell Most matings do not last that long Only a portion of the Hfr chromosome gets into the F– cell Since the nick is internal to the integrated F factor, only part of the plasmid is transferred and the F– cells does not become F+ The F– cell does pick up chromosomal DNA This DNA can recombine with the homologous region on the chromosome of the recipient cell This may provide the recipient cell with new combination of alleles Refer to Figure 6.5b 6-19 Copyright ©The McGraw-Hill Companies, Inc. Permission required for reproduction or display

25 6-20 Figure 6.5b Transfer of bacterial genes by an Hfr strain
F– cell received short segment of the Hfr chromosome It has become lac+ but remains pro– lac+  Ability to metabolize lactose lac–  Inability pro+  Ability to synthesize proline pro–  Inability Therefore, the order of transfer is lac+ – pro+ F– cell received longer segment of the Hfr chromosome It has become lac+ AND pro+ Figure 6.5b 6-20 Copyright ©The McGraw-Hill Companies, Inc. Permission required for reproduction or display

26 Experiment 6A Interrupted Mating Technique
Conjugation Experiments Can Map Genes Along the E. coli Chromosome The rationale behind this mapping strategy The time it takes genes to enter the recipient cell is directly related to their order along the bacterial chromosome The Hfr chromosome is transferred linearly to the F– recipient cell Therefore, interrupted mating at different times would lead to various lengths being transferred The order of genes along the chromosome can be deduced by determining the genes transferred during short matings vs. those transferred during long matings 6-21 Copyright ©The McGraw-Hill Companies, Inc. Permission required for reproduction or display

27 Wollman and Jacob started the experiment with two E. coli strains
The donor (Hfr) strain had the following genetic composition thr+ : Able to synthesize the essential amino acid threonine leu+ : Able to synthesize the essential amino acid leucine azis : Sensitive to killing by azide (a toxic chemical) tons : Sensitive to infection by T1 (a bacterial virus) lac+ : Able to metabolize lactose and use it for growth gal+ : Able to metabolize galactose and use it for growth strs : Sensitive to killing by streptomycin (an antibiotic) The recipient (F–) strain had the opposite genotype thr– leu– azir tonr lac – gal – strr r = resistant 6-22 Copyright ©The McGraw-Hill Companies, Inc. Permission required for reproduction or display

28 Wollman and Jacob already knew that
The thr+ and leu+ genes were transferred first, in that order Both were transferred within 5-10 minutes of mating Therefore their main goal was to determine the times at which genes azis, tons, lac+, and gal+ were transferred The transfer of the strs was not examined Streptomycin was used to kill the donor (Hfr) cell following conjugation The recipient (F– cell) is streptomycin resistant 6-23 Copyright ©The McGraw-Hill Companies, Inc. Permission required for reproduction or display

29 Testing the Hypothesis
The chromosome of the donor strain in an Hfr mating is transferred in a linear manner to the recipient strain The order of genes along the chromosome can be deduced by determining the time various genes take to enter the recipient cell Testing the Hypothesis Refer to Figure 6.6 6-24 Copyright ©The McGraw-Hill Companies, Inc. Permission required for reproduction or display

30 Figure 6.6 6-25

31 Percent of Surviving Bacterial Colonies with the Following Genotypes
The Data Minutes that Bacterial Cells were Allowed to Mate Before Blender Treatment Percent of Surviving Bacterial Colonies with the Following Genotypes thr+ leu azis tons lac gal+ 5 –– 10 100 12 3 15 70 31 20 88 71 25 92 80 28 0.6 30 90 75 36 40 38 50 91 78 42 27 60 6-26 Copyright ©The McGraw-Hill Companies, Inc. Permission required for reproduction or display

32 Percent of Surviving Bacterial Colonies with the Following Genotypes
Interpreting the Data After 10 minutes, the thr+ leu+ genotype was obtained Minutes that Bacterial Cells were Allowed to Mate Before Blender Treatment Percent of Surviving Bacterial Colonies with the Following Genotypes thr+ leu azis tons lac gal+ 5 –– 10 100 12 3 15 70 31 20 88 71 25 92 80 28 0.6 30 90 75 36 40 38 50 91 78 42 27 60 There were no surviving colonies after 5 minutes of mating The azis gene is transferred first It is followed by the tons gene The lac+ gene enters between 15 and 20 minutes The gal+ gene enters between 20 and 25 minutes 6-27 Copyright ©The McGraw-Hill Companies, Inc. Permission required for reproduction or display

33 From these data, Wollman and Jacob constructed the following genetic map:
They also identified various Hfr strains in which the origin of transfer had been integrated at different places in the chromosome Comparison of the order of genes among these strains, demonstrated that the E. coli chromosome is circular 6-28 Copyright ©The McGraw-Hill Companies, Inc. Permission required for reproduction or display

34 The E. coli Chromosome Conjugation experiments have been used to map more than 1,000 genes on the E. coli chromosome The E. coli genetic map is 100 minutes long Approximately the time it takes to transfer the complete chromosome in an Hfr mating Refer to Figure 6.7 6-29 Copyright ©The McGraw-Hill Companies, Inc. Permission required for reproduction or display

35 Arbitrarily assigned the starting point
Units are minutes Refer to the relative time it takes for genes to first enter an F– recipient during a conjugation experiment Figure 6.7 6-30 Copyright ©The McGraw-Hill Companies, Inc. Permission required for reproduction or display

36 The distance between genes is determined by comparing their times of entry during an interrupted mating experiment The approximate time of entry is computed by extrapolating the time back to the origin Figure 6.8 Therefore these two genes are approximately 9 minutes apart along the E. coli chromosome 6-31 Copyright ©The McGraw-Hill Companies, Inc. Permission required for reproduction or display

37 Plasmids Plasmids occur naturally in many strains of bacteria and a few eukaryotic cells such as yeast Range in size from a few thousand to 500,000 bp Carry from one to hundreds of genes Different plasmids will have one to 100 copies per cell Have their own origins of replication which are strong or weak Plasmids can provide a growth advantage to the cell 6-32 Copyright ©The McGraw-Hill Companies, Inc. Permission required for reproduction or display

38 Plasmids Plasmids fall into five different categories: 6-33
1. Fertility plasmids-allow bacteria to mate to each other 2. Resistance plasmids-confer resistance to antibiotics or toxins 3. Degradative plasmids-enable the digestion of unusual substances 4. Col-plasmids-encode colicines which are proteins that kill other bacteria 5. Virulence plasmids-turn a bacterium into a pathogenic strain 6-33 Copyright ©The McGraw-Hill Companies, Inc. Permission required for reproduction or display

39 Transduction Transduction is the transfer of DNA from one bacterium to another via a bacteriophage A bacteriophage is a virus that specifically attacks bacterial cells It is composed of genetic material surrounded by a protein coat It can undergo two types of cycles Lytic Lysogenic Refer to Figure 6.9 6-34 Copyright ©The McGraw-Hill Companies, Inc. Permission required for reproduction or display

40 It will switch to the lytic cycle
Prophage can exist in a dormant state for a long time Virulent phages only undergo a lytic cycle Temperate phages can follow both cycles The lytic and lysogenic reproductive cycles of certain bacteriophages. Some bacteriophages, such as temperate phages, can follow both cycles. Other phages, known as virulent phages, can follow only a lytic cycle.

41 Transduction Phages that can transfer bacterial DNA include
P22, which infects Salmonella typhimurium P1, which infects Escherichia coli Both are temperate phages Figure 6.10 illustrates the process of transduction 6-36 Copyright ©The McGraw-Hill Companies, Inc. Permission required for reproduction or display

42 Any piece of bacterial DNA can be incorporated into the phage
This type of transduction is termed generalized transduction Figure 6.10 6-37

43 They used an experimental strategy similar to that of Figure 6.1
Transduction was discovered in 1952 by Joshua Lederberg and Norton Zinder They used an experimental strategy similar to that of Figure 6.1 They used two strains of the bacterium Salmonella typhimurium One strain, designated LA-22, was phe– trp– met+ his+ Unable to synthesize phenylalanine or tryptophan Able to synthesize methionine and histidine The other strain, designated LA-2, was phe+ trp+ met– his– Able to synthesize phenylalanine and tryptophan Unable to synthesize methionine or histidine Their experiment is described next 6-38 Copyright ©The McGraw-Hill Companies, Inc. Permission required for reproduction or display

44 6-39 phe– trp– met+ his+ phe+ trp+ met– his–
Nutrient agar plates lacking the four amino acids Genotypes of surviving bacteria must be phe+ trp+ met+ his+ Therefore, genetic material had been transferred between the two strains ~ 1 cell in 100,000 was observed to grow However, Lederberg and Zinder obtained novel results when repeating the experiment using the U-tube apparatus 6-39 Copyright ©The McGraw-Hill Companies, Inc. Permission required for reproduction or display

45 Nutrient agar plates lacking the four amino acids
phe– trp– met+ his+ phe+ trp+ met– his– Nutrient agar plates lacking the four amino acids Colonies No colonies Genotypes of surviving bacteria must be phe+ trp+ met+ his+ 6-40

46 In this case, the LA-2 strain contained a prophage (such as P22)
Therefore, some agent was being transferred from LA-2 to LA-22 through the filter Norton and Zinder conducted the same experiment with filters of different pore sizes They found out that the filterable agent was less then 0.1mm in diameter They correctly concluded that the filterable agent was a bacteriophage In this case, the LA-2 strain contained a prophage (such as P22) The prophage switched to the lytic cycle Packaged a segment of DNA containing the phe+ and trp+ genes Passed through the filter and injected the DNA into the LA-22 strain 6-41 Copyright ©The McGraw-Hill Companies, Inc. Permission required for reproduction or display

47 Transformation Transformation is the process by which a bacterium will take up extracellular DNA released by a dead bacterium It was discovered by Frederick Griffith in 1928 while working with strains of Streptococcus pneumoniae There are two types Natural transformation DNA uptake occurs without outside help Artificial transformation DNA uptake occurs with the help of special techniques 6-48 Copyright ©The McGraw-Hill Companies, Inc. Permission required for reproduction or display

48 Transformation Natural transformation occurs in a wide variety of bacteria Bacterial cells able to take up DNA are termed competent cells They carry genes that encode proteins called competence factors These proteins facilitate the binding, uptake and subsequent corporation of the DNA into the bacterial chromosome The steps of bacterial transformation are presented in Figure 6.12 6-49 Copyright ©The McGraw-Hill Companies, Inc. Permission required for reproduction or display

49 A region of mismatch caused by sequence differences between the two alleles
By DNA repair enzymes Figure 6.12 6-50

50

51

52 Transformation Sometimes, the DNA that enters the cell is not homologous to any genes on the chromosome It may be incorporated at a random site on the chromosome This process is termed nonhomologous or illegitimate recombination Some bacteria preferentially take up DNA of bacteria from the same or related species Directed by DNA uptake signal sequences 9 or 10 bp long repeated 1-2,000 times throughout genome 6-51 Copyright ©The McGraw-Hill Companies, Inc. Permission required for reproduction or display

53 Horizontal Gene Transfer
Horizontal gene transfer is the transfer of genes between two different species Vertical gene transfer is the transfer of genes from mother to daughter cell or from parents to offspring A sizable fraction of bacterial genes are derived from horizontal gene transfer Roughly 17% of E. coli and S. typhimurium genes during the past 100 million years 6-52 Copyright ©The McGraw-Hill Companies, Inc. Permission required for reproduction or display

54 Horizontal Gene Transfer
The types of genes acquired through horizontal gene transfer are quite varied and include Genes that confer the ability to cause disease Genes that confer antibiotic resistance Genes that give the ability to degrade toxins Horizontal gene transfer has dramatically contributed to the phenomenon of acquired antibiotic resistance Bacterial resistance to antibiotics is a serious problem worldwide In many countries, nearly 50% of Streptococcus pneumoniae strains are resistant to penicillin 6-53 Copyright ©The McGraw-Hill Companies, Inc. Permission required for reproduction or display

55

56

57

58 6.2 INTRAGENIC MAPPING IN BACTERIOPHAGES
Viruses are not living They rely on a host cell for existence and replication However, they have unique biological structures and functions, and therefore have traits We will focus our attention on bacteriophage T4 Its genetic material contains several dozen genes These genes encode a variety of proteins needed for the viral cycle Refer to Figure 6.13 for the T4 structure 6-54 Copyright ©The McGraw-Hill Companies, Inc. Permission required for reproduction or display

59 6-55 Figure 6.13 Contains the genetic material
Used for attachment to the bacterial surface Figure 6.13 6-55

60 In the 1950s, Seymour Benzer embarked on a ten-year study focusing on the function of the T4 genes
He conducted a detailed type of genetic mapping known as intragenic or fine structure mapping The difference between intragenic and intergenic mapping is: 6-56

61 Plaques A plaque is a clear area on an otherwise opaque bacterial lawn on the agar surface of a petri dish It is caused by the lysis of bacterial cells as a result of the growth and reproduction of phages Figure 6.14 6-57

62 Plaques are visible with the naked eye
Some mutations in the phage’s genetic material can alter the ability of the phage to produce plaques Thus, plaques can be viewed as traits of bacteriophages Plaques are visible with the naked eye So mutations affecting them lend themselves to easier genetic analysis An example is a rapid-lysis mutant of bacteriophage T4, which forms unusually large plaques Refer to Figure 6.15 This mutant lyses bacterial cells more rapidly than do the wild-type phages Rapid-lysis mutant forms large, clearly defined plaques Wild-type phages produce smaller, fuzzy-edged plaques 6-58 Copyright ©The McGraw-Hill Companies, Inc. Permission required for reproduction or display

63 Benzer studied one category of T4 phage mutant, designated rII (r stands for rapid lysis)
It behaved differently in three different strains of E. coli In E. coli B rII phages produced unusually large plaques that had poor yields of bacteriophages The bacterium lyses so quickly that it does not have time to produce many new phages In E. coli K12S rII phages produced normal plaques that gave good yields of phages In E. coli K12(l) (has phage lambda DNA integrated into its chromosome) rII phages were not able to produce plaques at all As expected, the wild-type phage could infect all three strains 6-59 Copyright ©The McGraw-Hill Companies, Inc. Permission required for reproduction or display

64 Complementation Tests
Benzer collected many rII mutant strains that can form large plaques in E. coli B and none in E. coli K12(l) But, are the mutations in the same gene or in different genes? To answer this question, he conducted complementation experiments 6-60 Copyright ©The McGraw-Hill Companies, Inc. Permission required for reproduction or display

65 Figure 6.16 shows the possible outcomes of complementation experiments involving coinfection of plaque formation mutants Figure 6.16 6-61

66 A cistron is equivalent to a gene
Benzer carefully considered the pattern of complementation and noncomplementation He determined that the rII mutations occurred in two different genes, which were termed rIIA and rIIB Benzer coined the term cistron to refer to the smallest genetic unit that gives a negative complementation test So, if two mutations occur in the same cistron, they cannot complement each other A cistron is equivalent to a gene However, it is not as commonly used 6-62 Copyright ©The McGraw-Hill Companies, Inc. Permission required for reproduction or display

67 Function of protein A will be restored
At an extremely low rate, two noncomplementing strains of viruses can produce an occasional viral plaque, if intragenic recombination has occurred rII mutations Viruses cannot form plaques in E. coli K12(l) rII mutations Function of protein A will be restored Therefore new phages can be made in E. coli K12(l) Viral plaques will now be formed Figure 6.17 6-63

68 Figure 6.18 describes the general strategy for intragenic mapping of rII phage mutations
6-64 Copyright ©The McGraw-Hill Companies, Inc. Permission required for reproduction or display

69 r103 r104 Both rII mutants and wild-type phages can infect this strain rII mutants cannot infect this strain Number of wild-type phages produced by intragenic recombination Total number of phages 6-65 Copyright ©The McGraw-Hill Companies, Inc. Permission required for reproduction or display

70 The data from Figure 6.18 can be used to estimate the distance between the two mutations in the same gene The phage preparation used to infect E. coli B was diluted by 108 (1:100,000,000) 1 ml of this dilution was used and 66 plaques were produced Therefore, the total number of phages in the original preparation is 66 X 108 = 6.6 X 109 or 6.6 billion phages per milliliter The phage preparation used to infect E. coli k12(l) was diluted by 106 (1:1,000,000) 1 ml of this dilution was used and 11 plaques were produced Therefore, the total number of wild-type phages is 11 X 106 or 11 million phages per milliliter 6-66 Copyright ©The McGraw-Hill Companies, Inc. Permission required for reproduction or display

71 In this experiment, the intragenic recombination produces an equal number of recombinants
Wild-type phages and double mutant phages However, only the wild-type phages are detected in the infection of E. coli k12(l) Therefore, the total number of recombinants is the number of wild-type phages multiplied by two 2 [wild-type plaques obtained in E. coli k12(l)] Frequency of recombinants = Total number of plaques obtained in E. coli B 2(11 X 106) 6.6 X 109 Frequency of recombinants = = 3.3 X 10–3 = In this example, there was approximately 3.3 recombinants per 1,000 phages 6-67 Copyright ©The McGraw-Hill Companies, Inc. Permission required for reproduction or display

72 Homoallelic mutations
As in eukaryotic mapping, the frequency of recombinants can provide a measure of map distance along the bacteriophage chromosome In this case the map distance is between two mutations in the same gene The frequency of intragenic recombinants is correlated with the distance between the two mutations The farther apart they are the higher the frequency of recombinants Homoallelic mutations Mutations that happen to be located at exactly the same site in a gene They are not able to produce any wild-type recombinants So the map distance would be zero 6-68 Copyright ©The McGraw-Hill Companies, Inc. Permission required for reproduction or display

73 Deletion Mapping Benzer used deletion mapping to localize many rII mutations to a fairly short region in gene A or gene B He utilized deletion strains of phage T4 Each is missing a known segment of the rIIA and/or rIIB genes 6-69 Copyright ©The McGraw-Hill Companies, Inc. Permission required for reproduction or display

74 Let’s suppose that the goal is to know the approximate location of an rII mutation, such as r103
E. coli k12(l) is coinfected with r103 and a deletion strain If the deleted region includes the same region that contains the r103 mutation No intragenic wild-type recombinants are produced Therefore, plaques will not be formed If the deleted region does not overlap with the r103 mutation Intragenic wild-type recombinants can be produced And plaques will be formed 6-70 Copyright ©The McGraw-Hill Companies, Inc. Permission required for reproduction or display

75 Mutation must be in region contained in BP242 but not in PT1
Mutation must be in region contained in BP242 but not in PT1. This corresponds to A4 in the rIIA gene Figure 6.19 6-71

76 As described in Figure 6.19, the first step in the deletion mapping strategy localized rII mutations to seven regions Six in rIIA and one in rIIB Other strains were used to eventually localize each rII mutation to one of 47 regions 36 in rIIA and 11 in rIIB At this point, pairwise coinfections were made between mutant strains that had been localized to the same region This would precisely map their location relative to each other This resulted in a fine structure map with depicting the locations of hundreds of different rII mutations Refer to Figure 6.20 6-72 Copyright ©The McGraw-Hill Companies, Inc. Permission required for reproduction or display

77 Contain many mutations at exactly the same site within the gene
Figure 6.20 6-73

78 Intragenic mapping studies were a pivotal achievement in our early understanding of gene structure
Some scientists had envisioned a gene as being a particle-like entity that could not be further subdivided However, intragenic mapping revealed convincingly that this is not the case It showed that Mutations can occur at different parts within a single gene Intragenic crossing over can recombine these mutations, resulting in wild-type genes 6-74 Copyright ©The McGraw-Hill Companies, Inc. Permission required for reproduction or display


Download ppt "PowerPoint Presentation Materials to accompany"

Similar presentations


Ads by Google