2. Example: y=x 2 +2x-3 a=1b= +2 c= -3 Step 1. Find and graph the axis of symmetry x=-(b/2a) x=-(2/2(1)) x=-1 The axis of symmetry is the x-value of the ordered pair of the vertex and is expressed as the vertical line x=___ (-1,-4) x=(-1) Steps to graph a function of the form y=ax 2 +bx+c Step 2. Find and graph the vertex The x-coordinate is –(b/2a); x=(-1) The y-coordinate is found by substi- tuting the value for x back into the original quadratic and solving for y. y=(-1) 2 +2(-1)-3; y= (-4) vertex = (-1, -4) (0,-3) (-2,-3) Step 3. Find and graph the y-intercept and its reflection Since c is the y-intercept, the points are (0,-3) and the reflection is equidistant from the axis of symmetry (-2,-3)

3. Step 4. Evaluate the function for another value of x, such as y=1 2 +2(1)-3=0. Graph (1,0) and its reflection ( -3, 0) Step 5. Graph all of the points and construct the parabola. (-1,-4) (0,-3) (-2,-3) x=(-1)