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5.3 By: Jennie Page and Grace Arnold
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Apply the Parallel Postulate Identify the pairs of angles formed by a transversal cutting parallel lines Apply six theorems about parallel lines
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Through a point not on a line there is exactly one parallel to the given line A
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If two parallel lines are cut by a transversal each pair of alternate interior angles are congruent. (short form:||lines alt. int. s ) a b
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If two parallel lines are cut by a transversal, then any pairs of angles formed are either congruent or supplementary. x x (180-x) x x a b
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If two parallel lines are cut by a transversal, each pair of alternate exterior angles are congruent. (short form:||lines alt. ext. s ) a b
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If two parallel lines are cut by a transversal, each pair of corresponding angles are congruent. (short form: || lines corr. s ) a b
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If two parallel lines are cut by a transversal, each pair of interior angles on the same side of the transversal are supplementary. (short form: || lines same sided int. s supp.) a b
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If two parallel lines are cut by a transversal, each pair of exterior angles on the same side of the transversal are supplementary. (short form: || lines same sided ext. s supp.) a b
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In a plane, if a line is perpendicular to one of two parallel lines, it is perpendicular to the other. a b c
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If two lines are parallel to a third line, they are parallel to each other. (Transitive Property of Parallel Lines) abcabc If a || b and a || c then, b || c
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1202 34 5 6 78 From the given angle that is 120, name the degrees of the other angles. 1 st sample problem
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120 2 = 60 3= 60 4=120 5 =120 6=60 7=60 8=120 1 = 1 4, 2 3, 5 8, 6 7 because vertical angles are congruent. 1 8, 2 7 because alternate exterior angles are congruent. 3 6, 5 4 because alternate interior angles are congruent. 1 5, 2 6, 3 7, 4 8 because corresponding angles are congruent. 3 supp. 5, 4 supp. 6 because same sided int. angles are supp. 1 supp. 7, 2 supp. 8 because same sided ext. angles are supp.
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Use the given information to name the segments that must be ||. If there are no such segments, say so. ABCDEFABCDEF
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A. PL || AR B. PA || LR C. None D. PL || AR E. None
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This is an example of a crook problem. 180-34=146 (alt int. angles are congruent) Half of the x is 34 Once again because alt. int. angles are congruent the bottom half of the x is 28. Therefore, x= 28+34=62
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What is the value of x?
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Given: K||P Prove: 1 3
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1. 25 Alternate int. angles are congruent 2x-10=65-x 3x=75 x=25 2. 20 Corr. Angles are congruent x+80=5x 80=4x x=20 3. 33 3x+15+ 2x= 180 5x+15= 180 5x= 165 x= 33
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Statements 1. k||p 2. 1 2 3. 2 3 4. 1 3 Reasons 1. Given 2. || lines corr. s 3. Vertical angles are 4. Transitive
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