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Lesson 9 MI/Vocab solve solution inverse operations Solve equations using the Subtraction and Addition Properties of Equality.

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Presentation on theme: "Lesson 9 MI/Vocab solve solution inverse operations Solve equations using the Subtraction and Addition Properties of Equality."— Presentation transcript:

1 Lesson 9 MI/Vocab solve solution inverse operations Solve equations using the Subtraction and Addition Properties of Equality.

2 Lesson 9 KC 1

3 Lesson 9 Ex1 Solve an Addition Equation Solve 7 = 15 + c. Check your solution. Method 1 Vertical Method 7=15 + cWrite the equation. –8=c 7 =15 + c –15–15Subtract 15 from each side.

4 Lesson 9 Ex1 Solve an Addition Equation Method 2 Horizontal Method 7=15 + cWrite the equation. 7 – 15 =15 – 15 + cSubtract 15 from each side. –8=c

5 Lesson 9 Ex1 Solve an Addition Equation Check Answer: The solution is –8. 7=15 + cWrite the original equation. 7 =15 + (–8)Replace c with –8. Is this sentence true? 7=7

6 A.A B.B C.C D.D Lesson 9 CYP1 A.–5 B.–3 C.13 D.17 Solve 6 = 11 + a. Check your solution.

7 Lesson 9 KC 2

8 Lesson 9 Ex2 Solve an Addition Equation OCEANOGRAPHY At high tide, the top of a coral formation is 2 feet above the surface of the water. This represents a change of –6 feet from the height of the coral at low tide. Write and solve an equation to determine h, the height of the coral at low tide. WordsThe height of the coral at low tide plus (–6) feet is 2 feet. VariableLet h represent the height of the coral at low tide. Equationh + (–6) = 2

9 Lesson 9 Ex2 Solve an Addition Equation h + (–6)=2Write the equation. h + (–6) + 6=2 + 6Add 6 to each side. h =8 Answer: The height of the coral at low tide is 8 feet.

10 Lesson 9 CYP2 1.A 2.B 3.C 4.D A.$65 B.$45 C.$62 D.$32 If Carlos makes a withdrawal of $15 from his savings account, the amount in the account will be $47. Write and solve an equation to find the balance of the account before the withdrawal.

11 Lesson 9 Ex3 Solve a Subtraction Equation Solve –5 = z – 16. Method 1 Vertical Method –5=z – 16Write the equation. –5 =z – 16 Add 16 to each side.+16 11=z

12 Lesson 9 Ex3 Solve a Subtraction Equation Method 2 Horizontal Method –5= z – 16Write the equation. Answer: The solution is 11. –5 + 16= z – 16 + 16Add 16 to each side. z= 11

13 1.A 2.B 3.C 4.D Lesson 9 CYP3 A.–6 B.–3 C.6 D.9 Solve –6 = x –12.


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