1. CHAPTER 5 – Equations Instructor: Dr.Gehan Shanmuganathan

2. Business Math, Ninth Edition Cheryl Cleaves, Margie Hobbs & Jeffrey Nobel © 2012 Pearson Education, Inc. Upper Saddle River, NJ 07458 All Rights Reserved Learning Outcomes Solve equations using multiplication or division. Solve equations using addition or subtraction. Solve equations using more than one operation. Solve equations containing multiple unknown terms. Solve equations containing parentheses. Solve equations that are proportions. 5-1

3. Business Math, Ninth Edition Cheryl Cleaves, Margie Hobbs & Jeffrey Nobel © 2012 Pearson Education, Inc. Upper Saddle River, NJ 07458 All Rights Reserved Equations 5-1-1 Section 5-1 Solve equations using multiplication or division An equation is a mathematical statement in which two quantities are equal. Solving an equation means finding the value of an unknown. Example: 8x = 24 To solve this equation, the value of x must be discovered. Division is used to solve this equation.

4. Business Math, Ninth Edition Cheryl Cleaves, Margie Hobbs & Jeffrey Nobel © 2012 Pearson Education, Inc. Upper Saddle River, NJ 07458 All Rights Reserved EquationsSection 5-1 Solve equations using multiplication or division Letters, such as (x,y,z) represent unknown amounts and are called unknowns or variables. 4x = 16 The numbers are called known or given amounts.

5. Business Math, Ninth Edition Cheryl Cleaves, Margie Hobbs & Jeffrey Nobel © 2012 Pearson Education, Inc. Upper Saddle River, NJ 07458 All Rights Reserved EquationsSection 5-1 Solve equations using multiplication or division Any operation performed on one side of the equation must be performed on the other side of the equation as well. –If you “multiply by 2” on one side, you must “multiply by 2” on the other side. –If you “divide by 3” on one side, you must also “divide by 3” on the other side.

6. Business Math, Ninth Edition Cheryl Cleaves, Margie Hobbs & Jeffrey Nobel © 2012 Pearson Education, Inc. Upper Saddle River, NJ 07458 All Rights Reserved EquationsSection 5-1 Solve equations using multiplication or division STEP 2 Use division to divide both sides by 8. STEP 3 Simplify: x = 3 Isolate the unknown value and determine if multiplication or division is needed. STEP 1 8x = 24 3 x 8 = 24 HOW TO:

7. Business Math, Ninth Edition Cheryl Cleaves, Margie Hobbs & Jeffrey Nobel © 2012 Pearson Education, Inc. Upper Saddle River, NJ 07458 All Rights Reserved EquationsSection 5-1 Find the value of an unknown using multiplication Multiply both sides by 3 to isolate a. The left side becomes 1a or a. The right side becomes the product of 6 x 3, or 18. a = 18 HOW TO: Find the value of a:

8. Business Math, Ninth Edition Cheryl Cleaves, Margie Hobbs & Jeffrey Nobel © 2012 Pearson Education, Inc. Upper Saddle River, NJ 07458 All Rights Reserved EquationsSection 5-1 STEP 2 Perform the same operation to both sides. STEP 3 Isolate the variable and solve. Determine which operation is needed. STEP 1 2b = 40 Division Divide both sides by 2. An Example…

9. Business Math, Ninth Edition Cheryl Cleaves, Margie Hobbs & Jeffrey Nobel © 2012 Pearson Education, Inc. Upper Saddle River, NJ 07458 All Rights Reserved EquationsSection 5-1 Solve equations using addition or subtraction 5-1-2 Adding or subtracting any number from one side must be carried out on the other side as well. –Subtract “the given amount” from both sides. Would solving 4 + x = 16 require addition or subtraction of “4” from each side? Subtraction

10. Business Math, Ninth Edition Cheryl Cleaves, Margie Hobbs & Jeffrey Nobel © 2012 Pearson Education, Inc. Upper Saddle River, NJ 07458 All Rights Reserved EquationsSection 5-1 Solve equations using addition or subtraction STEP 2 Use subtraction to isolate x. STEP 3 Simplify: x = 6 Isolate the unknown value and determine if addition or subtraction is needed. STEP 1 4 + x = 10 HOW TO:

11. Business Math, Ninth Edition Cheryl Cleaves, Margie Hobbs & Jeffrey Nobel © 2012 Pearson Education, Inc. Upper Saddle River, NJ 07458 All Rights Reserved EquationsSection 5-1 STEP 2 Perform the same operation to both sides. STEP 3 Isolate the variable and solve. Determine which operation is needed. STEP 1 b - 12 = 8 Addition Add 12 to both sides An Example… b = 8 + 12 = 20

12. Business Math, Ninth Edition Cheryl Cleaves, Margie Hobbs & Jeffrey Nobel © 2012 Pearson Education, Inc. Upper Saddle River, NJ 07458 All Rights Reserved EquationsSection 5-1 Solve equations using more than one operation 5-1-3 Isolate the unknown value. –Add or subtract as necessary first. –Multiply or divide as necessary second. Identify the solution. –The number on the side opposite the unknown. Check the solution by “plugging in” the number using the original equation.

13. Business Math, Ninth Edition Cheryl Cleaves, Margie Hobbs & Jeffrey Nobel © 2012 Pearson Education, Inc. Upper Saddle River, NJ 07458 All Rights Reserved When two or more calculations are written symbolically, the operations are performed according to a specified order of operations. –First — perform multiplication and division as they appear from left to right. –Second — perform addition and subtraction as they appear from left to right. EquationsSection 5-1 Order of operations

14. Business Math, Ninth Edition Cheryl Cleaves, Margie Hobbs & Jeffrey Nobel © 2012 Pearson Education, Inc. Upper Saddle River, NJ 07458 All Rights Reserved To solve an equation, undo the operations, working in reverse order –First — undo the addition or subtraction. –Second — undo multiplication or division. EquationsSection 5-1 Order of operations

15. Business Math, Ninth Edition Cheryl Cleaves, Margie Hobbs & Jeffrey Nobel © 2012 Pearson Education, Inc. Upper Saddle River, NJ 07458 All Rights Reserved EquationsSection 5-1 STEP 2 Divide each side by 7. STEP 3 Verify by plugging in 5 in place of x. Undo the addition by subtracting 4 from each side. STEP 1 7x + 4 = 39 7x = 35 An Example… 7 (5) + 4 = 39 35 + 4 = 39

16. Business Math, Ninth Edition Cheryl Cleaves, Margie Hobbs & Jeffrey Nobel © 2012 Pearson Education, Inc. Upper Saddle River, NJ 07458 All Rights Reserved In some equations, the unknown value may occur more than once. The simplest instance is when the unknown value occurs in two addends, such as 3a + 2a = 25 –Add the numbers in each addend (2+3). –Multiply the sum by the unknown (5a = 25). –Solve for a (a = 5). EquationsSection 5-1 5-1-4 Solve equations containing multiple unknown terms

17. Business Math, Ninth Edition Cheryl Cleaves, Margie Hobbs & Jeffrey Nobel © 2012 Pearson Education, Inc. Upper Saddle River, NJ 07458 All Rights Reserved EquationsSection 5-1 STEP 2 Undo the subtraction. STEP 4 Check by replacing a with 7. Combine the unknown value addends. STEP 1 Find a if: a + 4a – 5 = 39 a + 4a = 5a 5a – 5 = 30 An Example… 5a = 35 STEP 3 Undo the multiplication. a = 7 7 + 4(7) = 35 Correct!

18. Business Math, Ninth Edition Cheryl Cleaves, Margie Hobbs & Jeffrey Nobel © 2012 Pearson Education, Inc. Upper Saddle River, NJ 07458 All Rights Reserved Eliminate the parentheses. –Multiply the number just outside the parentheses by each addend inside the parentheses. –Show the resulting products as addition or subtraction, as indicated Solve the resulting equation. EquationsSection 5-1 5-1-5 Solve equations containing parentheses

19. Business Math, Ninth Edition Cheryl Cleaves, Margie Hobbs & Jeffrey Nobel © 2012 Pearson Education, Inc. Upper Saddle River, NJ 07458 All Rights Reserved EquationsSection 5-1 STEP 2 Show the resulting products. STEP 3 Check by replacing a with 7. Multiply 6 by each addend. STEP 1 Solve: 6A + 2 = 24 6 multiplied by A + 6 multiplied by 2 An Example… 6A + 12 = 24 7 + 4(7) = 35

20. Business Math, Ninth Edition Cheryl Cleaves, Margie Hobbs & Jeffrey Nobel © 2012 Pearson Education, Inc. Upper Saddle River, NJ 07458 All Rights Reserved 5x -10 = 45 5x = 55 x = 11 EquationsSection 5-1 5 (x - 2) = 45 Remove the parentheses first. TIP: An Example…

21. Business Math, Ninth Edition Cheryl Cleaves, Margie Hobbs & Jeffrey Nobel © 2012 Pearson Education, Inc. Upper Saddle River, NJ 07458 All Rights Reserved A proportion is based on two pairs of related quantities. The most common way to write proportions is to use fraction notation—also called a ratio. –When two ratios are equal, they form a proportion. EquationsSection 5-1 5-1-6 Solve equations that are proportions

22. Business Math, Ninth Edition Cheryl Cleaves, Margie Hobbs & Jeffrey Nobel © 2012 Pearson Education, Inc. Upper Saddle River, NJ 07458 All Rights Reserved A cross product is the product of the numerator of one fraction, times the denominator of another fraction. –An important property of proportions is that the cross products are equal. EquationsSection 5-1 5-1-6 Solve equations that are proportions

23. Business Math, Ninth Edition Cheryl Cleaves, Margie Hobbs & Jeffrey Nobel © 2012 Pearson Education, Inc. Upper Saddle River, NJ 07458 All Rights Reserved STEP 2 Multiply the denominator of the first fraction by the numerator of the second fraction. Multiply the numerator from the first fraction by the denominator of the second fraction. STEP 1 4 x 18 = 72 6 x 12 = 72 EquationsSection 5-1 Verify that two fractions form a proportion HOW TO: Do and form a proportion? Are they equal? Yes, they form a proportion.

24. Business Math, Ninth Edition Cheryl Cleaves, Margie Hobbs & Jeffrey Nobel © 2012 Pearson Education, Inc. Upper Saddle River, NJ 07458 All Rights Reserved

25. Business Math, Ninth Edition Cheryl Cleaves, Margie Hobbs & Jeffrey Nobel © 2012 Pearson Education, Inc. Upper Saddle River, NJ 07458 All Rights Reserved Learning Outcome Use the problem-solving approach to analyze and solve word problems. 5-2

26. Business Math, Ninth Edition Cheryl Cleaves, Margie Hobbs & Jeffrey Nobel © 2012 Pearson Education, Inc. Upper Saddle River, NJ 07458 All Rights Reserved Five step problem solving approach: – What you know. Known or given facts. – What you are looking for. Unknown or missing amounts. – Solution Plan. Equation or relationship among known/unknown facts. – Solution. Solve the equation. – Conclusion. Solution interpreted within context of problem. Using Equations to Solve Problems 5-2-1 Section 5-2 Use the problem-solving approach to analyze and solve word problems.

27. Business Math, Ninth Edition Cheryl Cleaves, Margie Hobbs & Jeffrey Nobel © 2012 Pearson Education, Inc. Upper Saddle River, NJ 07458 All Rights Reserved Using Equations to Solve Problems 5-2-1 Section 5-2 Use the problem-solving approach to analyze and solve word problems. Key words in Table 5-1 will guide you in using the problem-solving approach. See page 533 These words help you interpret the information and begin to set up the equation to solve the problem. “of” often implies multiplication. “¼ of her salary” means “multiply her salary by ¼” Example:

28. Business Math, Ninth Edition Cheryl Cleaves, Margie Hobbs & Jeffrey Nobel © 2012 Pearson Education, Inc. Upper Saddle River, NJ 07458 All Rights Reserved Full time employees work more hours than part-time employees. What are we looking for? Number of hours that FT employees work. What do we know? PT employees work 6 hours, and the difference between FT and PT is 4 hours. If the difference is four per day, and part-time employees work six hours per day, how many hours per day do full-timers work? Use the solution plan HOW TO: Using Equations to Solve ProblemsSection 5-2

29. Business Math, Ninth Edition Cheryl Cleaves, Margie Hobbs & Jeffrey Nobel © 2012 Pearson Education, Inc. Upper Saddle River, NJ 07458 All Rights Reserved Set up a solution plan. FT – PT = 4 FT = N [unknown]PT = 6 hours N – 6 = 4 Solution plan: N = 4 + 6 = 10 What are we looking for? Number of hours that FT employees work. What do we know? PT employees work 6 hours, and the difference between FT and PT is 4 hours. Use the solution plan HOW TO: Using Equations to Solve ProblemsSection 5-2 Full time employees work more hours than part-time employees. If the difference is four per day, and part-time employees work six hours per day, how many hours per day do full-timers work? We also know that “difference” implies subtraction. Conclusion: Full time employees work 10 hours.

30. Business Math, Ninth Edition Cheryl Cleaves, Margie Hobbs & Jeffrey Nobel © 2012 Pearson Education, Inc. Upper Saddle River, NJ 07458 All Rights Reserved 1. What are you looking for? The number of cards that Jill has. 2. What do you know? The relationship in the number of cards is 3:1; total is 200 3. Set up a solution plan. x(Matt’s) + 3x(Jill’s) = 200 4. Solve it. x + 3x = 200; 4x = 200; x = 50 5. Draw the conclusion. Jill has 3x, or 150 cards Jill has three times as many trading cards as Matt. If the total number both have is 200, how many does Jill have? Use the solution plan HOW TO: Using Equations to Solve ProblemsSection 5-2

31. Business Math, Ninth Edition Cheryl Cleaves, Margie Hobbs & Jeffrey Nobel © 2012 Pearson Education, Inc. Upper Saddle River, NJ 07458 All Rights Reserved Diane’s Card Shop spent a total of $950 ordering 600 cards from Wit’s End Co., whose humorous cards cost $1.75 each and whose nature cards cost $1.50 each. How many of each style of card did the card shop order? Use the solution plan HOW TO: Using Equations to Solve ProblemsSection 5-2 MORE How many humorous cards were ordered and how many nature cards were ordered—the total of H + N = 600 or N = 600 – H. If we let H represent the humorous cards, Nature cards will be 600 – H, which will simplify the solution process by using only one unknown: H. What are you looking for?

32. Business Math, Ninth Edition Cheryl Cleaves, Margie Hobbs & Jeffrey Nobel © 2012 Pearson Education, Inc. Upper Saddle River, NJ 07458 All Rights Reserved Diane’s Card Shop spent a total of $950 ordering 600 cards from Wit’s End Co., whose humorous cards cost $1.75 each and whose nature cards cost $1.50 each. How many of each style of card did the card shop order? Use the solution plan HOW TO: Using Equations to Solve ProblemsSection 5-2 MORE A total of $950 was spent. Two types of cards were ordered. The total number of cards ordered was 600. Humorous cards cost $1.75 each and nature cards cost $1.50 each. What do you know?

33. Business Math, Ninth Edition Cheryl Cleaves, Margie Hobbs & Jeffrey Nobel © 2012 Pearson Education, Inc. Upper Saddle River, NJ 07458 All Rights Reserved Diane’s Card Shop spent a total of $950 ordering 600 cards from Wit’s End Co., whose humorous cards cost $1.75 each and whose nature cards cost $1.50 each. How many of each style of card did the card shop order? Use the solution plan HOW TO: Using Equations to Solve ProblemsSection 5-2 MORE Volume unknowns $1.75(H) + $1.50 (600 – H) = $950.00 Unit prices Total spent Solution Plan Set up the equation by multiplying the unit price of each by the volume, represented by the unknowns equaling the total amount spent.

34. Business Math, Ninth Edition Cheryl Cleaves, Margie Hobbs & Jeffrey Nobel © 2012 Pearson Education, Inc. Upper Saddle River, NJ 07458 All Rights Reserved Diane’s Card Shop spent a total of $950 ordering 600 cards from Wit’s End Co., whose humorous cards cost $1.75 each and whose nature cards cost $1.50 each. How many of each style of card did the card shop order? Use the solution plan HOW TO: Using Equations to Solve ProblemsSection 5-2 MORE $1.75H + $1.50(600 - H) = $950.00 $1.75H + $900.00 - $1.50H = $950.00 $0.25H + $900.00 = $950.00 $0.25H = $50.00 H = 200 Solution

35. Business Math, Ninth Edition Cheryl Cleaves, Margie Hobbs & Jeffrey Nobel © 2012 Pearson Education, Inc. Upper Saddle River, NJ 07458 All Rights Reserved Diane’s Card Shop spent a total of $950 ordering 600 cards from Wit’s End Co., whose humorous cards cost $1.75 each and whose nature cards cost $1.50 each. How many of each style of card did the card shop order? Use the solution plan HOW TO: Using Equations to Solve ProblemsSection 5-2 The number of humorous cards ordered is 200. Since nature cards are 600 – H, we can conclude that 400 nature cards were ordered. Using “200” and “400” in the original equation proves that the volume amounts are correct. Conclusion

36. Business Math, Ninth Edition Cheryl Cleaves, Margie Hobbs & Jeffrey Nobel © 2012 Pearson Education, Inc. Upper Saddle River, NJ 07458 All Rights Reserved Denise ordered 75 dinners for the awards banquet. Fish dinners cost $11.75 and chicken dinners cost $9.25 each. If she spent a total of $756.25, how many of each type of dinner did she order? Use the solution plan HOW TO: Using Equations to Solve ProblemsSection 5-2 $11.75(F) + $9.25(75 - F) = $756.25 $11.75F + $693.75 - $9.25F = $756.25 $2.50F + $693.75 = $756.25 $2.50F = $62.50 F = 25 Conclusion: 25 fish dinners and 50 chicken dinners were ordered.

37. Business Math, Ninth Edition Cheryl Cleaves, Margie Hobbs & Jeffrey Nobel © 2012 Pearson Education, Inc. Upper Saddle River, NJ 07458 All Rights Reserved The relationship between two factors is often described in proportions. –You can use proportions to solve for unknowns. Proportions Using Equations to Solve ProblemsSection 5-2 The label on a container of weed killer gives directions to mix three ounces of weed killer with every two gallons of water. For five gallons of water, how many ounces of weed killer should you use? Example:

38. Business Math, Ninth Edition Cheryl Cleaves, Margie Hobbs & Jeffrey Nobel © 2012 Pearson Education, Inc. Upper Saddle River, NJ 07458 All Rights Reserved 1. What are you looking for? Number of ounces of weed killer needed for 5 gallons of water. 2. What do you know? For every 2 gallons of water, you need 3 oz. of weed killer. The relationship between two factors is often described in proportions. –You can use proportions to solve for unknowns. Proportions Using Equations to Solve ProblemsSection 5-2 Example: The label on a container of weed killer gives directions to mix three ounces of weed killer with every two gallons of water. For five gallons of water, how many ounces of weed killer should you use? Set up a solution plan. Solve it. Cross multiply: 2x = 15; x = 7.5 Conclusion. You need 7.5 oz of weed killer for 5 gal of water.

39. Business Math, Ninth Edition Cheryl Cleaves, Margie Hobbs & Jeffrey Nobel © 2012 Pearson Education, Inc. Upper Saddle River, NJ 07458 All Rights Reserved Many business-related problems that involve pairs of numbers that are proportional involve direct proportions. –An increase (or decrease) in one amount causes an increase (or decrease) in the number that pairs with it. Proportions Using Equations to Solve ProblemsSection 5-2

40. Business Math, Ninth Edition Cheryl Cleaves, Margie Hobbs & Jeffrey Nobel © 2012 Pearson Education, Inc. Upper Saddle River, NJ 07458 All Rights Reserved Using Equations to Solve ProblemsSection 5-2 In this example, an increase in the amount of gas would directly and proportionately increase the mileage yielded. Your car gets 23 miles to the gallon. How far can you go on 16 gallons of gas? Cross multiply: 1x = 368 miles Conclusion: You can travel 368 miles on 16 gallons of gas. An Example…

41. Business Math, Ninth Edition Cheryl Cleaves, Margie Hobbs & Jeffrey Nobel © 2012 Pearson Education, Inc. Upper Saddle River, NJ 07458 All Rights Reserved

42. Business Math, Ninth Edition Cheryl Cleaves, Margie Hobbs & Jeffrey Nobel © 2012 Pearson Education, Inc. Upper Saddle River, NJ 07458 All Rights Reserved Learning Outcomes Evaluate a formula. Find an equivalent formula by rearranging the formula. 5-3

43. Business Math, Ninth Edition Cheryl Cleaves, Margie Hobbs & Jeffrey Nobel © 2012 Pearson Education, Inc. Upper Saddle River, NJ 07458 All Rights Reserved Evaluate the formula Write the formula. Rewrite the formula substituting known values for the letters of the formula. Solve the equation for the unknown letter or perform the indicated operations, applying the order of operations. Interpret the solution within the context of the formula. Formulas 5-3-1 Section 5-3

44. Business Math, Ninth Edition Cheryl Cleaves, Margie Hobbs & Jeffrey Nobel © 2012 Pearson Education, Inc. Upper Saddle River, NJ 07458 All Rights Reserved FormulasSection 5-3 A plasma TV that costs $2,145 is marked up $854. What is the selling price of the TV? Use the formula S = C + M where S is the selling price, C is the cost, and M is Markup. S = $2,145 + $854 S or Selling Price = $2,999 An Example…

45. Business Math, Ninth Edition Cheryl Cleaves, Margie Hobbs & Jeffrey Nobel © 2012 Pearson Education, Inc. Upper Saddle River, NJ 07458 All Rights Reserved Determine which variable of the formula is to be isolated (solved for). Highlight or mentally locate all instances of the variable to be isolated. Treat all other variables of the formula as you would treat numbers in an equation, and perform normal steps for solving an equation. If the isolated variable is on the right side of the equation, interchange the sides so that it appears on the left side. Find an Equivalent Formula by Rearranging the Formula FormulasSection 5-3 5-3-2

46. Business Math, Ninth Edition Cheryl Cleaves, Margie Hobbs & Jeffrey Nobel © 2012 Pearson Education, Inc. Upper Saddle River, NJ 07458 All Rights Reserved FormulasSection 5-3 An Example… The formula for Square Footage = Length x Width or S = L x W. Solve the formula for W or width. Isolate W by dividing both sides by L. The new formula is:

47. Business Math, Ninth Edition Cheryl Cleaves, Margie Hobbs & Jeffrey Nobel © 2012 Pearson Education, Inc. Upper Saddle River, NJ 07458 All Rights Reserved

48. Business Math, Ninth Edition Cheryl Cleaves, Margie Hobbs & Jeffrey Nobel © 2012 Pearson Education, Inc. Upper Saddle River, NJ 07458 All Rights Reserved EXERCISE SET A

49. Business Math, Ninth Edition Cheryl Cleaves, Margie Hobbs & Jeffrey Nobel © 2012 Pearson Education, Inc. Upper Saddle River, NJ 07458 All Rights Reserved EXERCISE SET A

50. Business Math, Ninth Edition Cheryl Cleaves, Margie Hobbs & Jeffrey Nobel © 2012 Pearson Education, Inc. Upper Saddle River, NJ 07458 All Rights Reserved EXERCISE SET A

51. Business Math, Ninth Edition Cheryl Cleaves, Margie Hobbs & Jeffrey Nobel © 2012 Pearson Education, Inc. Upper Saddle River, NJ 07458 All Rights Reserved EXERCISE SET A

52. Business Math, Ninth Edition Cheryl Cleaves, Margie Hobbs & Jeffrey Nobel © 2012 Pearson Education, Inc. Upper Saddle River, NJ 07458 All Rights Reserved EXERCISE SET A

53. Business Math, Ninth Edition Cheryl Cleaves, Margie Hobbs & Jeffrey Nobel © 2012 Pearson Education, Inc. Upper Saddle River, NJ 07458 All Rights Reserved EXERCISE SET A

54. Business Math, Ninth Edition Cheryl Cleaves, Margie Hobbs & Jeffrey Nobel © 2012 Pearson Education, Inc. Upper Saddle River, NJ 07458 All Rights Reserved

55. Business Math, Ninth Edition Cheryl Cleaves, Margie Hobbs & Jeffrey Nobel © 2012 Pearson Education, Inc. Upper Saddle River, NJ 07458 All Rights Reserved PRACTICE TEST

56. Business Math, Ninth Edition Cheryl Cleaves, Margie Hobbs & Jeffrey Nobel © 2012 Pearson Education, Inc. Upper Saddle River, NJ 07458 All Rights Reserved PRACTICE TEST

57. Business Math, Ninth Edition Cheryl Cleaves, Margie Hobbs & Jeffrey Nobel © 2012 Pearson Education, Inc. Upper Saddle River, NJ 07458 All Rights Reserved PRACTICE TEST

58. Business Math, Ninth Edition Cheryl Cleaves, Margie Hobbs & Jeffrey Nobel © 2012 Pearson Education, Inc. Upper Saddle River, NJ 07458 All Rights Reserved PRACTICE TEST

59. Business Math, Ninth Edition Cheryl Cleaves, Margie Hobbs & Jeffrey Nobel © 2012 Pearson Education, Inc. Upper Saddle River, NJ 07458 All Rights Reserved PRACTICE TEST

60. Business Math, Ninth Edition Cheryl Cleaves, Margie Hobbs & Jeffrey Nobel © 2012 Pearson Education, Inc. Upper Saddle River, NJ 07458 All Rights Reserved PRACTICE TEST

61. Business Math, Ninth Edition Cheryl Cleaves, Margie Hobbs & Jeffrey Nobel © 2012 Pearson Education, Inc. Upper Saddle River, NJ 07458 All Rights Reserved PRACTICE TEST

62. Business Math, Ninth Edition Cheryl Cleaves, Margie Hobbs & Jeffrey Nobel © 2012 Pearson Education, Inc. Upper Saddle River, NJ 07458 All Rights Reserved PRACTICE TEST

63. Business Math, Ninth Edition Cheryl Cleaves, Margie Hobbs & Jeffrey Nobel © 2012 Pearson Education, Inc. Upper Saddle River, NJ 07458 All Rights Reserved