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© 2013 Pearson Education, Inc. Chapter 7, Section 8 General, Organic, and Biological Chemistry Fourth Edition Karen Timberlake 7.8 The Ideal Gas Law Chapter.

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Presentation on theme: "© 2013 Pearson Education, Inc. Chapter 7, Section 8 General, Organic, and Biological Chemistry Fourth Edition Karen Timberlake 7.8 The Ideal Gas Law Chapter."— Presentation transcript:

1 © 2013 Pearson Education, Inc. Chapter 7, Section 8 General, Organic, and Biological Chemistry Fourth Edition Karen Timberlake 7.8 The Ideal Gas Law Chapter 7 Gases © 2013 Pearson Education, Inc. Lectures

2 © 2013 Pearson Education, Inc. Chapter 7, Section 8 The four properties used in the measurement of a gas,  pressure (P),  volume (V),  temperature (T), and  amount (n), can be combined to give a single expression called the ideal gas law. PV = nRT Ideal Gas Law 2

3 © 2013 Pearson Education, Inc. Chapter 7, Section 8 Rearranging the ideal gas law equation shows that the four gas properties equal a constant, R. To calculate the value of R, we substitute the STP conditions for molar volume into the expression: R, Ideal Gas Constant 3

4 © 2013 Pearson Education, Inc. Chapter 7, Section 8 Another value for the universal gas constant, R, is obtained using mmHg for the STP pressure. What is the value of R when a pressure of 760 mmHg rather than 1.00 atm is used? Learning Check 4

5 © 2013 Pearson Education, Inc. Chapter 7, Section 8 Another value for the universal gas constant, R, is obtained using mmHg for the STP pressure. What is the value of R when a pressure of 760 mmHg rather than 1.00 atm is used? Solution 5

6 © 2013 Pearson Education, Inc. Chapter 7, Section 8 Unit Summary for R, the Ideal Gas Constant 6

7 © 2013 Pearson Education, Inc. Chapter 7, Section 8 Guide to Using the Ideal Gas Law 7

8 © 2013 Pearson Education, Inc. Chapter 7, Section 8 Dinitrogen oxide (N 2 O), laughing gas, is used by dentists as an anesthetic. If a 20.0 L tank of laughing gas contains 2.86 moles of N 2 O at 23  C, what is the pressure (mmHg) in the tank? Learning Check 8

9 © 2013 Pearson Education, Inc. Chapter 7, Section 8 If a 20.0 L tank of laughing gas contains 2.86 moles of N 2 O at 23 ˚C, what is the pressure (mmHg) in the tank? Step 1 State the given and needed quantities. Analyze the Problem. Solution 9

10 © 2013 Pearson Education, Inc. Chapter 7, Section 8 If a 20.0 L tank of laughing gas contains 2.86 moles of N 2 O at 23 ˚C, what is the pressure (mmHg) in the tank? Step 2 Rearrange the ideal gas law equation to solve for the needed quantity. Solution 10

11 © 2013 Pearson Education, Inc. Chapter 7, Section 8 If a 20.0 L tank of laughing gas contains 2.86 moles of N 2 O at 23 ˚C, what is the pressure (mmHg) in the tank? Step 3 Substitute the gas data into the equation and calculate the needed quantity. Solution 11

12 © 2013 Pearson Education, Inc. Chapter 7, Section 8 Ideal Gas Law and Molar Mass 12

13 © 2013 Pearson Education, Inc. Chapter 7, Section 8 Learning Check A cylinder contains 5.0 L of an unknown gas at 20.0 ˚C and 0.85 atm. If the mass of the gas in the cylinder is 5.8 g, what is the molar mass of the gas? 13

14 © 2013 Pearson Education, Inc. Chapter 7, Section 8 A cylinder contains 5.0 L of an unknown gas at 20.0 ˚C and 0.85 atm. If the mass of the gas in the cylinder is 5.8 g, what is the molar mass of the gas? Step 1 State the given and needed quantities. Analyze the Problem Solution 14

15 © 2013 Pearson Education, Inc. Chapter 7, Section 8 A cylinder contains 5.0 L of an unknown gas at 20.0 ˚C and 0.85 atm. If the mass of the gas in the cylinder is 5.8 g, what is the molar mass of the gas? Step 2 Rearrange the ideal gas law equation to solve for the number of moles. Step 3 Obtain the molar mass by dividing the given number of grams by the number of moles. Solution 15

16 © 2013 Pearson Education, Inc. Chapter 7, Section 8 Chemical Reactions and the Ideal Gas Law 16

17 © 2013 Pearson Education, Inc. Chapter 7, Section 8 Learning Check Nitrogen gas reacts with hydrogen gas to produce ammonia (NH 3 ) gas. How many liters of NH 3 can be produced at 0.93 atm and 24 ˚C from a 16.0-g sample of nitrogen gas and an excess of hydrogen gas? 17

18 © 2013 Pearson Education, Inc. Chapter 7, Section 8 Solution How many liters of NH 3 can be produced at 0.93 atm and 24 ˚C from a 16.0-g sample of nitrogen gas and an excess of hydrogen gas? Step 1 State the given and needed quantities. Analyze the Problem. 18

19 © 2013 Pearson Education, Inc. Chapter 7, Section 8 Solution How many liters of NH 3 can be produced at 0.93 atm and 24 ˚C from a 16.0-g sample of nitrogen gas and an excess of hydrogen gas? Step 2 Write a plan to convert the given quantity to the needed moles. grams molar moles mole−mole moles of N 2 mass of N 2 factor of NH 3 19

20 © 2013 Pearson Education, Inc. Chapter 7, Section 8 How many liters of NH 3 can be produced at 0.93 atm and 24 ˚C from a 16.0-g sample of nitrogen gas and an excess of hydrogen gas? Step 3 Write the equalities for molar mass and mole– mole factors. Solution 20

21 © 2013 Pearson Education, Inc. Chapter 7, Section 8 Solution How many liters of NH 3 can be produced at 0.93 atm and 24 ˚C from a 16.0-g sample of nitrogen gas and an excess of hydrogen gas? Step 4 Set up the problem to calculate moles of needed quantity. 21

22 © 2013 Pearson Education, Inc. Chapter 7, Section 8 Solution How many liters of NH 3 can be produced at 0.93 atm and 24 ˚C from a 16.0-g sample of nitrogen gas and an excess of hydrogen gas? Step 5 Convert the moles of needed to volume using the ideal gas law equation. 22


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