1. The Cosine Rule A B C a c b Pythagoras’ Theorem allows us to calculate unknown lengths in right-angled triangles using the relationship a 2 = b 2 + c 2 a 2 > b 2 + c 2 a 2 < b 2 + c 2 It would be very useful to be able to calculate unknown sides for any value of the angle at A. Consider the square on the side opposite A when angle A is not a right-angle. a 2 = b 2 + c 2 A a2a2 1 A Angle A obtuse a2a2 2 A Angle A acute a2a2 3

2. Deriving the rule A B C a b c Consider a general triangle ABC. We require a in terms of b, c and A. Draw BP perpendicular to AC b P x b - x BP 2 = a 2 – (b – x) 2 Also: BP 2 = c 2 – x 2  a 2 – (b – x) 2 = c 2 – x 2  a 2 – (b 2 – 2bx + x 2 ) = c 2 – x 2  a 2 – b 2 + 2bx – x 2 = c 2 – x 2  a 2 = b 2 + c 2 – 2bx*  a 2 = b 2 + c 2 – 2bcCosA *Since Cos A = x/c  x = cCosA When A = 90 o, CosA = 0 and reduces to a 2 = b 2 + c 2 1 When A > 90 o, CosA is positive,  a 2 > b 2 + c 2 2 When A b 2 + c 2 3 The Cosine Rule The Cosine Rule generalises Pythagoras’ Theorem and takes care of the 3 possible cases for Angle A. a 2 > b 2 + c 2 a 2 < b 2 + c 2 a 2 = b 2 + c 2 A A A 1 2 3 Pythagoras + a bit Pythagoras - a bit Pythagoras

3. a 2 = b 2 + c 2 – 2bcCosA Applying the same method as earlier to the other sides produce similar formulae for b and c. namely: b 2 = a 2 + c 2 – 2acCosB c 2 = a 2 + b 2 – 2abCosC A B C a b c The Cosine Rule The Cosine rule can be used to find: 1. An unknown side when two sides of the triangle and the included angle are given. 2. An unknown angle when 3 sides are given. Finding an unknown side.

4. a 2 = b 2 + c 2 – 2bcCosA The Cosine Rule To find an unknown side we need 2 sides and the included angle. a2 a2 = 82 82 + 9.6 2 – 2 x 8 x 9.6 x Cos 40 o a = (82 (82 + 9.6 2 – 2 x 8 x 9.6 x Cos 40 o ) a = 6.2 cm (1 dp) m2 m2 = 5.4 2 + 7.7 2 – 2 x 5.4 x 7.7 x Cos 65 o m =  (5.4 2 + 7.7 2 – 2 x 5.4 x 7.7 x Cos 65 o ) m = 7.3 cm (1 dp) Not to scale 8 cm 9.6 cm a 1. 40 o 2. 7.7 cm 5.4 cm 65 o m 85 m 100 m 15 o 3. p p2 p2 = 85 2 + 100 2 – 2 x 85 x 100 x Cos 15 o p =  (85 2 + 100 2 – 2 x 85 x 100 x Cos 15 o ) p = 28.4 m (1 dp)

5. a 2 = b 2 + c 2 – 2bcCosA The Cosine Rule Application Problem A fishing boat leaves a harbour (H) and travels due East for 40 miles to a marker buoy (B). At B the boat turns left onto a bearing of 035 o and sails to a lighthouse (L). It then returns to harbour. (a)Make a sketch of the journey (b)Find the total distance travelled by the boat. (nearest mile) H 40 miles 24 miles B L 125 o HL 2 = 40 2 + 24 2 – 2 x 40 x 24 x Cos 125 0 HL =  (40 2 + 24 2 – 2 x 40 x 24 x Cos 125 0 ) = 57 miles  Total distance = 57 + 64 = 121 miles.

6. An AWACS aircraft takes off from RAF Waddington (W) on a navigation exercise. It flies 430 miles North to a point P before turning left onto a bearing of 230 o to a second point Q, 570 miles away. It then returns to base. (a) Make a sketch of the flight. (b) Find the total distance flown by the aircraft. (nearest mile) The Cosine Rule a 2 = b 2 + c 2 – 2bcCosA QW 2 = 430 2 + 570 2 – 2 x 430 x 570 x Cos 50 0 QW =  (430 2 + 570 2 – 2 x 430 x 570 x Cos 50 0 ) = 441 miles  Total distance = 1000 + 441 = 1441 miles. 50 o P 570 miles W 430 miles Not to Scale Q

7. A B C a b c The Cosine Rule To find unknown angles the 3 formula for sides need to be re-arranged in terms of CosA, B or C. a 2 = b 2 + c 2 – 2bcCosA b 2 = a 2 + c 2 – 2acCosB c 2 = a 2 + b 2 – 2abCosC Similarly

8. Not to scale 8 cm 9.6 cm 6.2 1. A 2. 7.7 cm 5.4 cm P 7.3 cm 85 m 100 m 3. R 28.4 m The Cosine Rule To find an unknown angle we need 3 given sides.

9. A fishing boat leaves a harbour (H) and travels due East for 40 miles to a marker buoy (B). At B the boat turns left and sails for 24 miles to a lighthouse (L). It then returns to harbour, a distance of 57 miles. (a)Make a sketch of the journey. (b)Find the bearing of the lighthouse from the harbour. (nearest degree) The Cosine Rule Application Problems H 40 miles 24 miles B L 57 miles A

10. The Cosine Rule a 2 = b 2 + c 2 – 2bcCosA An AWACS aircraft takes off from RAF Waddington (W) on a navigation exercise. It flies 530 miles North to a point (P) as shown, It then turns left and flies to a point (Q), 670 miles away. Finally it flies back to base, a distance of 520 miles. Find the bearing of Q from point P. P 670 miles W 530 miles Not to Scale Q 520 miles