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Integration of ex ∫ ex.dx = ex + k ∫ eax+b.dx = eax+b + k 1 a.

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Presentation on theme: "Integration of ex ∫ ex.dx = ex + k ∫ eax+b.dx = eax+b + k 1 a."— Presentation transcript:

1 Integration of ex ex.dx = ex + k eax+b.dx = eax+b + k 1 a

2 ∫ ∫ ∫ Integration of ex Proof eax+b.dx = eax+b + k 1 a (eax+b) = d dx
eax+b x a = aeax+b a eax+b.dx = eax+b + k eax+b.dx = eax+b + k 1 a

3 ∫ ∫ Integration of ex Example 1 eax+b.dx = eax+b + k 1 a e2x.dx = 1 2

4 ∫ ∫ Integration of ex [e3x+1] = (e7 – e4) 3 Example 2
eax+b.dx = eax+b + k 1 a 2 e3x+1.dx = 1 3 [e3x+1] 1 2 1 1 3 = (e7 – e4) e7 – e4 3 = = Exact Approx

5 ∫ ∫ Integration of ex Example 3
Find the volume of the solid of revolution made when the curve y = ex is rotated about the x-axis from x = 0 to x = 2. = [e2x] 2 π y = ex y2 = e2x = (e4 – e0] π 2 V = π y2.dx a b = (e4 – 1] units3 π 2 Exact V = π e2x.dx 2 = units3 Approx


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