1. Strain Energy Due to Shear, Bending and Torsion Lecture No-6 J P Supale Mechanical Engineering Department SKN SITS LONAVALA Strength of Materials

2. Strain Energy due to Shear Consider a cube ABCD of side L being subjected to a shear force P which is applied tangentially to the side CD. As a result, side CD changes to C’D’. δlδl P BA Φ Φ L C D D’ C’ Let Φ=Angle turned by the side AD as a result of P being applied τ=Shear stress induced on the side CD A= Area of each side=LxL G=Modulus of rigidity of the material of cube

3. Strain Energy due to Shear Strength of Materials The shear force P is given as In ADD’ When Φ is very small

4. Strain Energy due to Shear Strength of Materials Work done by shear force is given as As we know, work done =strain energy stored in the cube, is given as WhereV=LxLxL= Volume of cube

5. Strain Energy Due to Torsion Strength of Materials Consider a solid shaft subjected to a torque T. O r R dr Let D=Diameter of the shaft=2R R=Radius of shaft J=Polar moment of inertia of shaft cross- section τ max =Shear stress induced in the shaft at R θ=Angle of twist produced in the shaft L=Length of the shaft Consider a circular ring of radius r and thickness dr. The shear stress at r is assumed to be τ.

6. Strain Energy Due to Torsion Strength of Materials Strain energy stored in the ring is given as Total strain energy stored in the shaft is obtained as From torsion equation, we have

7. Strain Energy Due to Torsion Strength of Materials Equation 22 on substituting τ becomes,

8. Strain Energy Due to Torsion Strength of Materials If solid shaft is replaced by a hollow shaft of outside diameter Do and inside diameter Di, then equation 23 changes to Volume of hollow shaft is given as

9. Strain Energy Due to Bending Strength of Materials Consider a small length dx of the beam at a distance x from A. Let bending moment acting on the length be M. 1 2 A B x dx L N A y dAdA Bending stress acting on the elementary area(dA) at a distance y from the neutral axis is given by using bending equation WhereI=moment of inertia of x-section about N.A.

10. Strain Energy Due to Bending Strength of Materials Strain energy stored in the elementary area is Strain energy stored in the beam between 1 and 2 is given as

11. Strain Energy Due to Bending Strength of Materials Strain energy stored in the entire beam is obtained as

12. Numerical 1 1.A cantilever beam of span 2m having cross section 30 mm wide by 75 mm deep. Determine strain energy stored in beam if Concentrated load of 1.75kN act at free end. Take E=200 GPa L=2m b=30mm= 0.03m d= 75mm =0.075mm E=200x10 9 N/m 2 Strength of Materials

13. Moment of Inertia Flexural Rigidity, EI Strength of Materials

14. Concentrated load of 1.75kN act at free end. Strain Energy Strength of Materials X 1.75kN L=2m

15. Numerical 2 A cantilever beam of span 2m having cross section 30 mm wide by 75 mm deep. Determine strain energy stored in beam if total 2kN load is uniformly spread over entire span  Take E=200 Gpa L=2m b=30mm= 0.03m d= 75mm =0.075mm E=200x10 9 N/m 2 Strength of Materials

16. Moment of Inertia Flexural Rigidity, EI Strength of Materials

17. 2kN load is uniformly spread over entire span Strain Energy Strength of Materials 2 1000 N/m X

18. Workout Numerical 1 Find an expression for strain energy due to bending for a SSB of span L, the beam carrying UDL w per unit run over whole span.  Draw beam diagram. Calculate Reactions.  Apply Macaulays method, to get  Put this bending moment in strain energy equation Strength of Materials

19. Workout Numerical 1 A beam 6m in length is carrying UDL of 10 kN/m length. Determine the strain energy stored in the beam. Take E 200 GPa and I=1500 cm 4.  Draw diagram of loading, calculate reactions.  Apply Macaulays method to get moment equation as  Put this bending moment in strain energy equation Strength of Materials