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**Chapter 3 –Systems of Linear Equations**

3.2 – Solving Linear Systems by Substitution

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**3.2 – Solving Linear Systems by Substitution**

Today we will review: Solving a system of linear equations in two variables by substitution

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**3.2 – Solving Linear Systems by Substitution**

Substitute (real-life) – Replace one thing with another Substitute – Replace one variable with an expression containing the other variable

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**3.2 – Solving Linear Systems by Substitution**

Steps for Solving a Linear System by Substitution Solve for one of the variables (the one with no coefficient (number in front)) Substitute the value from the step 1 into the other equation & solve for the other variable Substitute the value from step 2 into the revised equation from step 1 and solve Check the solution

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**3.2 – Solving Linear Systems by Substitution**

Example 1 Solve the system using substitution y = 4x -2x + y = -4

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**3.2 – Solving Linear Systems by Substitution**

Example 2 Solve the system using substitution 3x + 2y = 1 -2x + y = 4

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**3.2 – Solving Linear Systems by Substitution**

Example 3 In one week, a pizza restaurant sold 210 pizzas and made $ The price of a small is $12 and the price of a large pizza is $15. How many small pizzas and large pizzas were sold last week?

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**3.2 – Solving Linear Systems by Substitution**

HOMEWORK Worksheet 3.2 Practice A

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