Presentation is loading. Please wait.

Presentation is loading. Please wait.

Newton’s Law of Gravitation Chapter 7, Section 3 Pg. 263-265.

Similar presentations


Presentation on theme: "Newton’s Law of Gravitation Chapter 7, Section 3 Pg. 263-265."— Presentation transcript:

1 Newton’s Law of Gravitation Chapter 7, Section 3 Pg. 263-265

2 Newton’s Universal Law of Gravitation Earth MOON FgFg To keep two moving bodies from shooting off in a straight line, a mutual gravitational force attraction occurs between them. FEmFEm FmEFmE

3 The amount of gravitational force that occurs between two masses depends on the distance between the two masses. Newton’s universal law of gravitation F g = (G m 1 m 2 ) /r² G = constant of universal gravitation G = 6.673 x 10 -11 Nm²/kg²

4 Sample Problem 2 Find the distance between a 0.300 kg billiard ball and a 0.400 kg billiard ball if the magnitude of the gravitational force is 8.92 x 10 -11 N. r = ? m 1 = 0.300 kgm 2 = 0.400 kg Fg = (G m 1 m 2 ) /r² F g = 8.92 x 10 -11 N r² = (G m 1 m 2 ) / Fg r = √(G m 1 m 2 ) / Fg r = √[6.673 x 10 -11 Nm²/kg² (0.4 kg) (0.3kg)]/8.92x10 -11 N r = 3.00 x 10 -1 m G = 6.673 x 10 -11 Nm²/kg²


Download ppt "Newton’s Law of Gravitation Chapter 7, Section 3 Pg. 263-265."

Similar presentations


Ads by Google