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TRANSFORMING FORMULA VARIABLES ON BOTH SIDES. LITERAL EQUATION "solving literal equations" is another way of saying, "taking an equation with lots of.

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Presentation on theme: "TRANSFORMING FORMULA VARIABLES ON BOTH SIDES. LITERAL EQUATION "solving literal equations" is another way of saying, "taking an equation with lots of."— Presentation transcript:

1 TRANSFORMING FORMULA VARIABLES ON BOTH SIDES

2 LITERAL EQUATION "solving literal equations" is another way of saying, "taking an equation with lots of letters, and solving for one letter in particular."

3 Examples of LITERAL EQUATIONS d= rt d=distancer=ratet=time A= ½(bh) A=area of a triangle b=baseh=height P= 2w + 2l P=perimeterw=widthl=length

4 Solving Literal Equations d= rt d=distancer=ratet=time Solve for t d= rt r d= t r t =d r r Solve for r d= rt t d= t t r =d t t

5 A= ½(bh) A=area of a triangle b=baseh=height Solve for b A = ½ (bh) (2)(2) 2A = (bh) hh 2A = b h b = 2A h

6 A= ½(bh) A=area of a triangle b=baseh=height Solve for h h = 2A b YOUR TURN!

7 P= 2w + 2l P=perimeterw=widthl=length Solve for l P = 2w + 2l -2w-2w P -2w = 2l 2 2 P -2w = l 2

8 Solve the following literal equations and write each step made m = ⅓ (t + e) Solve for t t= 3m-e b = 6k + 4d Solve for d d=(b-6k) 4

9 Homework X = 4a + s Solve for a X = 4a + s Solve for s m = ⅓ (t + e) Solve for t h = ⅓k - w Solve for k h = ⅓k - w Solve for w b = 6k + 4d Solve for d a= x - s 4 s= x - 4a t= 3m-e k=3(h+w) w=h - ⅓k d=(b-6k) 4


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