1. Learn to find the probabilities of independent and dependent events. Course 3 10-5 Independent and Dependent Events

2. A compound event is made up of one or more separate events. To find the probability of a compound event, you need to know if the events are independent or dependent. Course 3 10-5 Independent and Dependent Events Events are independent events if the occurrence of one event does not affect the probability of the other. Events are dependent events if the occurrence of one does affect the probability of the other.

3. Determine if the events are dependent or independent. A. getting tails on a coin toss and rolling a 6 on a number cube B. getting 2 red gumballs out of a gumball machine Additional Example 1: Classifying Events as Independent or Dependent Tossing a coin does not affect rolling a number cube, so the two events are independent. After getting one red gumball out of a gumball machine, the chances for getting the second red gumball have changed, so the two events are dependent. Course 3 10-5 Independent and Dependent Events

4. Determine if the events are dependent or independent. A. rolling a 6 two times in a row with the same number cube B. a computer randomly generating two of the same numbers in a row Check It Out: Example 1 The first roll of the number cube does not affect the second roll, so the events are independent. The first randomly generated number does not affect the second randomly generated number, so the two events are independent. Course 3 10-5 Independent and Dependent Events

5. Course 3 10-5 Independent and Dependent Events

6. Three separate boxes each have one blue marble and one green marble. One marble is chosen from each box. What is the probability of choosing a blue marble from each box? Additional Example 2A: Finding the Probability of Independent Events The outcome of each choice does not affect the outcome of the other choices, so the choices are independent. P(blue, blue, blue) = In each box, P(blue) =. 1212 1212 · 1212 · 1212 = 1818 = 0.125 Multiply. Course 3 10-5 Independent and Dependent Events

7. What is the probability of choosing at least one blue marble? Additional Example 2C: Finding the Probability of Independent Events 1 – 0.125 = 0.875 Subtract from 1 to find the probability of choosing at least one blue marble. Think: P(at least one blue) + P(not blue, not blue, not blue) = 1. In each box, P(not blue) =. 1212 P(not blue, not blue, not blue) = 1212 · 1212 · 1212 = 1818 = 0.125Multiply. Course 3 10-5 Independent and Dependent Events

8. Two boxes each contain 4 marbles: red, blue, green, and black. One marble is chosen from each box. What is the probability of choosing a blue marble from each box? Check It Out: Example 2A The outcome of each choice does not affect the outcome of the other choices, so the choices are independent. In each box, P(blue) =. 1414 P(blue, blue) = 1414 · 1414 = 1 16 = 0.0625 Multiply. Course 3 10-5 Independent and Dependent Events

9. Course 3 10-5 Independent and Dependent Events To calculate the probability of two dependent events occurring, do the following: 1. Calculate the probability of the first event. 2. Calculate the probability that the second event would occur if the first event had already occurred. 3. Multiply the probabilities.

10. The letters in the word dependent are placed in a box. If two letters are chosen at random, what is the probability that they will both be consonants? Additional Example 3A: Find the Probability of Dependent Events P(first consonant) = Course 3 10-5 Independent and Dependent Events 2323 6969 = Because the first letter is not replaced, the sample space is different for the second letter, so the events are dependent. Find the probability that the first letter chosen is a consonant.

11. Additional Example 3A Continued Course 3 10-5 Independent and Dependent Events If the first letter chosen was a consonant, now there would be 5 consonants and a total of 8 letters left in the box. Find the probability that the second letter chosen is a consonant. P(second consonant) = 5858 5 12 5858 2323 ·= The probability of choosing two letters that are both consonants is. 5 12 Multiply.

12. If two letters are chosen at random, what is the probability that they will both be consonants or both be vowels? Additional Example 3B: Find the Probability of Dependent Events There are two possibilities: 2 consonants or 2 vowels. The probability of 2 consonants was calculated in Example 3A. Now find the probability of getting 2 vowels. Find the probability that the first letter chosen is a vowel. If the first letter chosen was a vowel, there are now only 2 vowels and 8 total letters left in the box. Course 3 10-5 Independent and Dependent Events P(first vowel) = 1313 3939 =

13. Additional Example 3B Continued Find the probability that the second letter chosen is a vowel. The events of both consonants and both vowels are mutually exclusive, so you can add their probabilities. Course 3 10-5 Independent and Dependent Events P(second vowel) = 1414 2828 = 1 12 1414 1313 ·= Multiply. 1212 5 12 1 12 + = 6 12 = The probability of getting two letters that are either both consonants or both vowels is. 1212 P(consonant) + P(vowel)

14. Course 3 10-5 Independent and Dependent Events Two mutually exclusive events cannot both happen at the same time. Remember!

15. The letters in the phrase I Love Math are placed in a box. If two letters are chosen at random, what is the probability that they will both be consonants? Check It Out: Example 3A Course 3 10-5 Independent and Dependent Events P(first consonant) = 5959 Because the first letter is not replaced, the sample space is different for the second letter, so the events are dependant. Find the probability that the first letter chosen is a consonant.

16. Check It Out: Example 3A Continued Course 3 10-5 Independent and Dependent Events P(second consonant) = 5 18 1212 5959 ·= The probability of choosing two letters that are both consonants is. 5 18 Multiply. If the first letter chosen was a consonant, now there would be 4 consonants and a total of 8 letters left in the box. Find the probability that the second letter chosen is a consonant. 1212 4848 =