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Education as a Signaling Device and Investment in Human Capital Topic 3 Part I.

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Presentation on theme: "Education as a Signaling Device and Investment in Human Capital Topic 3 Part I."— Presentation transcript:

1 Education as a Signaling Device and Investment in Human Capital Topic 3 Part I

2 Outline Tools –Probability Theory –Game Theory Games of Incomplete Information Perfect Bayesian Equilibrium A Model of Education as a Signaling Device of the Productivity of the Worker (Spence, 1974) Education as Human Capital Accumulation (Becker, 1962) Empirical Evidence

3 Probability: Basic Operations and Bayes’ Rule We need to use probabilities in deriving the Perfect Bayesian Equilibrium Then, we will review basic probability operations and the Bayes’ Rule

4 Sample Space Let “S” denote a set (collection) of all possible states of the environment known as the sample space A typical state is denoted as “s” Examples S = {s 1, s 2 }: success/failure S = {s 1, s 2,...,s n-1,s n }: number of n units sold

5 Event An event is a collection of those states “s i ” that result in the occurrence of the event An event can imply that one state occurs or that multiple states occur

6 Probability The likelihood that an uncertain event (or set of events, for example, A 1 or A 2 ) occurs is measured using the concept of probability P(A i ) expresses the probability that the event Ai occurs We assume that  A i = S P (  A i ) = 1 0  P (A i )  1, for any i

7 Addition Rules The probability that event “A or event B” occurs is denoted by P(A  B) If the events are mutually exclusive (events are disjoint subsets of S, so that A  B=  ), then the probability of A or B is simply the sum of the two probabilities P(A  B) = P(A) + P(B) If the events are not mutually exclusive (events are not disjoint, so that A  B ‡  ), we use the modified addition rule P(A  B) = P(A) + P(B) – P(A  B)

8 Multiplication Rules The probability that “event A and event B occur” is denoted by P(A  B) Multiplication rule applies if A and B are independent events. A and B are independent events if P(A) does not depend on whether B occurs or not, and P(B) does not depend on whether A occurs or not. Then, P(A  B)= P(A)*P(B) We apply the modified multiplication rule when A and B are not independent events. Then, P(A  B) = P(A)*P(B/A) where, P(B/A) is the conditional probability of B given that A has already occurred

9 Bayes’ Rule Bayes’ Rule (or Bayes’ Theorem) is used to revise probabilities when additional information becomes available Example: We want to assess the likelihood that individual X is a drug user given that he tests positive –Initial information: 5% of the population are drug users –New information: individual X tests positive. The test is only 95% effective (the test will be positive on a drug user 95% of the time, and will be negative on a non-drug user 95% of the time)

10 Bayes’ Rule Let A be the event “individual X tests positive in the drug test”. Let B be the event “individual X is a drug user”. Let B c be the complementary event “individual X is not a drug user” We need to find P(B|A), the probability that “individual X is a drug user given that the test is positive”. We assume S consists of “B” and “not B” = B c The Bayes rule can be stated as

11 Bayes’ Rule Information given Test effective 95%. Then, –Probability that the test results positive given that the individual is a drug addict = P(A|B) = 0.95 (test correct) –Probability that the test results positive given that the individual is not a drug addict = P(A|B c ) = 0.05 (test wrong) 5% of population are drug users: –Probability of being a drug addict = P(B) = 0.05 –Probability of not being a drug addict = P(B c ) = 0.95

12 Bayes’ Rule Using Bayes’ Rule we get


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