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Math I.  Probability is the chance that something will happen.  Probability is most often expressed as a fraction, a decimal, a percent, or can also.

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Presentation on theme: "Math I.  Probability is the chance that something will happen.  Probability is most often expressed as a fraction, a decimal, a percent, or can also."— Presentation transcript:

1 Math I

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3  Probability is the chance that something will happen.  Probability is most often expressed as a fraction, a decimal, a percent, or can also be written out in words.  To determine the probability… P(event) = number of true outcomes total number of equally likely outcomes

4  Independent : Two events are independent if the occurrence of one has no effect on the occurrence of the other…

5  Example 1: (probability of two events) What is the probability of drawing a king and then an ace from a standard 52 card deck with replacement? P(King, Ace) =  Example 2 : What is the probability of flipping heads on a coin three times in a row? P(H, H, H) =

6  Example 3: A die is rolled twice. What’s the probability of rolling a 2 and then an even number? Solution:  Example 4: You spin the spinner 3 times. What is the probability of spinning a 4, a 3 and then a 1? Solution:

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8  Dependent: Two events such that the occurrence of one affects the occurrence of the other. P(A and B) = P(A) P(B|A) **P(B|A) = means the probability of B given that event A has already occurred.

9  Example 1 : What is the probability of drawing a King and then an Ace without replacement ? P(King, Ace) =

10  Example 2: You randomly select two marbles from a bag that contains 14 green, 7 blue, and 9 red marbles. What is the probability that the first marble is blue and the second marble is not blue if you do not replace the first marble? Solution:

11  Example 3: Your teacher passes around a basket with 6 red erasers, 9 blue erasers, and 7 green erasers. If you and your two neighbors are the first to randomly select an eraser, what is the probability that all three of you select green erasers? Solution : P(A) and P(B|A) and P(C|A and B)

12  The table shows the number of males and females with certain hair colors. Find …  A) the probability that a listed person has red hair  B) the probability that a female has red hair Brown hair Blonde hair Red hair Black hair OtherMale421131727 Female471613915

13  P(red hair) = # of people with red hair total # of people  P(red hair | female) = # of red hair females total # of females

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15  When you consider the outcomes for either of two events A and B, you form the union of A and B.

16  When you consider only the outcomes shared by both A and B, you form the intersection of A and B.

17  When the sets of A and B have nothing in common (no intersection) then they are considered mutually exclusive events.

18  If A and B are mutually exclusive events (one event does not have anything in common with the other), then… P(A or B) = P(A) + P(B)

19  A die is rolled one time. What is the probability of rolling a 2 or a 6? Solution: P(A or B) = P(A) + P(B) =

20  A card is randomly selected out of a standard deck of 52 cards. What is the probability that it is a 2 or a king? P(A or B) = P(A) + P(B) =

21  If A and B are not mutually exclusive, then there are some outcomes in common.  Therefore, the intersection of A and B are counted twice when P(A) and P(B) are added.  So, P(A and B) must be subtracted once from the sum… P(A or B) = P(A) + P(B) – P(A and B)

22  A die is rolled one time. What is the probability of rolling an odd number or a prime number?  Odd = 1, 3, 5 P(A) = Prime = 2, 3, 5 P(B) =  Odd and prime = 3, 5 P(A and B) =

23  A card is randomly selected from standard deck of 52 cards. What is the probability that it is a red card or a king?  Red cards = 26 = Kings = 4 =  Red Kings = 2 =

24  The probability that it will rain today is 40%. The probability that is will rain tomorrow is 30%. The probability that it will rain both days is 20%. Find the probability that it will rain either today OR tomorrow.  Solution: P(A ) + P(B) – P(A and B) P(today) + P(tomorrow) – P(today and tomorrow) =


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